/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Simplify the quantities in Probl... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify the quantities in Problems \(16-19\) using \(m(z)=z^{2}\) $$m(z+1)-m(z)$$

Short Answer

Expert verified
The simplified expression is \(2z + 1\).

Step by step solution

01

Understand the Function

The function given is \( m(z) = z^2 \). This implies for any input \( z \), the output is the square of \( z \).
02

Substitute \( z+1 \) into the Function

We need to find \( m(z+1) \). Substitute \( z+1 \) into the function: \[ m(z+1) = (z+1)^2 \].
03

Expand the Expression

Expand the expression \((z+1)^2\). \[(z+1)^2 = z^2 + 2z + 1 \].
04

Write the Expression for \(m(z+1) - m(z)\)

Now, find \( m(z+1) - m(z) \). This requires substituting the expanded form and original function: \[ m(z+1) - m(z) = (z^2 + 2z + 1) - z^2 \].
05

Simplify the Expression

Simplify the expression by canceling common terms:\[ m(z+1) - m(z) = z^2 + 2z + 1 - z^2 = 2z + 1 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Function Substitution
Function substitution is a powerful tool in calculus and algebra. It involves replacing a variable or an entire expression within a function with another value or expression. This technique can make complex problems easier to solve by breaking them down into smaller, more manageable parts.

In the exercise, the function given is \( m(z) = z^2 \). To solve the problem, we needed to substitute \( z+1 \) into the function. This required us to replace every instance of \( z \) with \( z+1 \) to find \( m(z+1) \). Remember, substitution helps us understand how changes in variables affect the function's value. It's like looking through a new lens to see how the function behaves differently.
  • Identify the function and its components.
  • Substitute new expressions systematically.
  • Rewrite the function to reflect the substitution.
By mastering this technique, you can handle increasingly complex functions with confidence.
Exploring Algebraic Expansion
Algebraic expansion is the process of multiplying out brackets to simplify expressions and combine like terms. It often requires distributing terms and arranging them systematically. The goal is to rewrite expressions without changing their value, making them easier to work with for further operations.

In our problem, we expanded \((z+1)^2\). This involved straightforward algebra. Think of \((z+1)(z+1)\) as multiplying each term in the first bracket with every term in the second.
First, multiply \(z\) by \(z\) to get \(z^2\). Next, multiply \(z\) by \(1\) to get \(z\). Do the same for the second \(1\), resulting in another \(z\). Finally, multiply \(1\) by \(1\) to get \(1\). When combined, these products form \(z^2 + 2z + 1\).
  • Ensure every term is multiplied correctly.
  • Look out for common terms to combine.
  • Double-check for any missed terms.
This method builds a solid foundation for tackling more complex algebraic expressions.
Mastering Expression Simplification
Expression simplification combines several techniques to represent an expression in its simplest form. Simplifying expressions is essentially cleaning up your work to reveal its core components. By doing this, we make complex expressions more intuitive to understand.

In our example, once we expanded \( m(z+1) = z^2 + 2z + 1 \), we moved to simplify \( m(z+1) - m(z) \). This step required us to recognize and cancel out the common terms \(z^2\) from each part: \((z^2 + 2z + 1) - z^2\). The \(z^2\) terms cancel each other, leaving us with \(2z + 1\).
  • Identify and remove terms that appear on both sides of the expression.
  • Combine like terms to make the expression as concise as possible.
  • Simplifying helps in understanding and solving further parts of complex problems.
Reducing expressions makes it easier for us to work with them later, whether evaluating, comparing, or further manipulating them.

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Most popular questions from this chapter

The concentration of the car exhaust fume nitrous oxide, \(\mathrm{NO}_{2},\) in the air near a busy road is a function of distance from the road. The concentration decays exponentially at a continuous rate of \(2.54 \%\) per meter. \(^{67}\) At what distance from the road is the concentration of \(\mathrm{NO}_{2}\) half what it is on the road?

You have a budget of 2000 dollars for the year to cover your books and social outings. Books cost (on average) 80 each and social outings cost (on average) 20 dollars each. Let \(b\) denote the number of books purchased per year and \(s\) denote the number of social outings in a year. (a) What is the equation of your budget constraint? (b) Graph the budget constraint. (It does not matter which variable you put on which axis.) (c) Find the vertical and horizontal intercepts, and give a financial interpretation for each.

The functions in Problems \(17-20\) represent exponential growth or decay. What is the initial quantity? What is the growth rate? State if the growth rate is continuous. $$P=15 e^{-0.06 t}$$

The circulation time of a mammal (that is, the average time it takes for all the blood in the body to circulate once and return to the heart) is proportional to the fourth root of the body mass of the mammal. (a) Write a formula for the circulation time, \(T\), in terms of the body mass, \(B\) (b) If an elephant of body mass 5230 kilograms has a circulation time of 148 seconds, find the constant of proportionality. (c) What is the circulation time of a human with body mass 70 kilograms?

Write the functions in Problems \(21-24\) in the form \(P=P_{0} a^{t}\) Which represent exponential growth and which represent exponential decay? $$P=15 e^{0.25 t}$$

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