Chapter 1: Problem 16
For Problems \(1-16,\) solve for \(t\) using natural logarithms. $$5 e^{3 t}=8 e^{2 t}$$
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Chapter 1: Problem 16
For Problems \(1-16,\) solve for \(t\) using natural logarithms. $$5 e^{3 t}=8 e^{2 t}$$
These are the key concepts you need to understand to accurately answer the question.
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Write the functions in Problems \(21-24\) in the form \(P=P_{0} a^{t}\) Which represent exponential growth and which represent exponential decay? $$P=15 e^{0.25 t}$$
Soybean production, in millions of tons $$\begin{array}{c|c|c|c|c|c|c} \hline \text { Year } & 2000 & 2001 & 2002 & 2003 & 2004 & 2005 \\ \hline \text { Production } & 161.0 & 170.3 & 180.2 & 190.7 & 201.8 & 213.5 \\ \hline \end{array}$$ A photocopy machine can reduce copies to \(80 \%\) of their original size. By copying an already reduced copy, further reductions can be made. (a) If a page is reduced to \(80 \%,\) what percent enlargement is needed to return it to its original size? (b) Estimate the number of times in succession that a page must be copied to make the final copy less than \(15 \%\) of the size of the original.
Delta Cephei is one of the most visible stars in the night sky. Its brightness has periods of 5.4 days, the average brightness is 4.0 and its brightness varies by \(\pm 0.35 .\) Find a formula that models the brightness of Delta Cephei as a function of time, \(t,\) with \(t=0\) at peak brightness.
Soybean production, in millions of tons $$\begin{array}{c|c|c|c|c|c|c} \hline \text { Year } & 2000 & 2001 & 2002 & 2003 & 2004 & 2005 \\ \hline \text { Production } & 161.0 & 170.3 & 180.2 & 190.7 & 201.8 & 213.5 \\ \hline \end{array}$$ (a) Niki invested \(\$ 10,000\) in the stock market. The investment was a loser, declining in value \(10 \%\) per year each year for 10 years. How much was the investment worth after 10 years? (b) After 10 years, the stock began to gain value at \(10 \%\) per year. After how long will the investment regain its initial value \((\$ 10,000) ?\)
For Problems \(1-16,\) solve for \(t\) using natural logarithms. $$2 P=P e^{0.3 t}$$
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