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(a) Make a table of values for \(y=e^{x}\) using \(x=\) 0,1,2,3 (b) Plot the points found in part (a). Does the graph look like an exponential growth or decay function? (c) Make a table of values for \(y=e^{-x}\) using \(x=\) 0,1,2,3 (d) Plot the points found in part (c). Does the graph look like an exponential growth or decay function?

Short Answer

Expert verified
(a) and (b) show exponential growth; (c) and (d) show exponential decay.

Step by step solution

01

Table of Values for \( y = e^x \)

Start by calculating the values of \( y = e^x \) for the given \( x \) values.For \( x = 0 \), \( y = e^0 = 1 \).For \( x = 1 \), \( y = e^1 \approx 2.718 \).For \( x = 2 \), \( y = e^2 \approx 7.389 \).For \( x = 3 \), \( y = e^3 \approx 20.086 \).Thus, the table of values is:| \( x \) | \( y = e^x \) ||-------|--------------|| 0 | 1 || 1 | 2.718 || 2 | 7.389 || 3 | 20.086 |
02

Plot for \( y = e^x \)

Using the table of values obtained in Step 1, plot the points on a graph with \( x \) on the horizontal axis and \( y \) on the vertical axis. The points are (0,1), (1,2.718), (2,7.389), and (3,20.086). Connect these points with a smooth curve.Observe the trend: the graph shows a rapid increase, indicating that it is an exponential growth function.
03

Table of Values for \( y = e^{-x} \)

Calculate the values of \( y = e^{-x} \) for the given \( x \) values.For \( x = 0 \), \( y = e^{0} = 1 \).For \( x = 1 \), \( y = e^{-1} \approx 0.368 \).For \( x = 2 \), \( y = e^{-2} \approx 0.135 \).For \( x = 3 \), \( y = e^{-3} \approx 0.050 \).Thus, the table of values is:| \( x \) | \( y = e^{-x} \) ||-------|------------------|| 0 | 1 || 1 | 0.368 || 2 | 0.135 || 3 | 0.050 |
04

Plot for \( y = e^{-x} \)

Using the table of values obtained in Step 3, plot the points on a graph with \( x \) on the horizontal axis and \( y \) on the vertical axis. The points are (0,1), (1,0.368), (2,0.135), and (3,0.050). Connect these points with a smooth curve.Observe the trend: the graph shows a rapid decrease, indicating that it is an exponential decay function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Growth
Exponential growth occurs when the value of a function increases rapidly over time. In the context of mathematical functions, exponential growth can be represented by functions such as \( y = e^x \), where \( e \) (approximately 2.718) is the base of the natural logarithm. In these functions, the variable \( x \) is the exponent, and as \( x \) increases, \( y \) increases quickly due to the multiplication involved in each step. Consider the exercise example of making a table for \( y = e^x \) using the values \( x = 0, 1, 2, 3 \). We notice:
  • At \( x = 0 \), \( y = e^0 = 1 \)
  • At \( x = 1 \), \( y \approx 2.718 \)
  • At \( x = 2 \), \( y \approx 7.389 \)
  • At \( x = 3 \), \( y \approx 20.086 \)
With each step, the output value \( y \) grows larger at an increasing rate, which characterizes exponential growth. This concept is crucial in various fields, such as biology for population models and finance for compound interest.
Exponential Decay
Exponential decay describes a process where a function's value decreases quickly as time progresses. This type of decay can be represented by equations like \( y = e^{-x} \). Here, the negative sign in the exponent causes the base \( e \) to be raised to a decreasing power as \( x \) increases, resulting in a smaller \( y \) value each time.From the exercise, we create a table for \( y = e^{-x} \) with the same \( x \) values:
  • At \( x = 0 \), \( y = e^0 = 1 \)
  • At \( x = 1 \), \( y \approx 0.368 \)
  • At \( x = 2 \), \( y \approx 0.135 \)
  • At \( x = 3 \), \( y \approx 0.050 \)
In this scenario, we see how \( y \) decreases rapidly, illustrating exponential decay. This concept is widely applied in physics for modeling radioactive decay and in medicine to describe the decrease of drug concentration in the bloodstream over time.
Table of Values
Creating a table of values is an essential step to understand the behavior of exponential functions. It involves calculating and organizing pairs of \( x \) and \( y \) values, which are derived from substituting \( x \) into the given function equation.For the exercise at hand, two tables were created for functions \( y = e^x \) and \( y = e^{-x} \). Here’s why this process is important:
  • It helps visualize the rapid increase or decrease as \( x \) changes.
  • Provides clear numerical insight into how small changes in \( x \) can have significant effects.
  • Serves as a foundation for plotting these functions on a graph.
By carefully compiling these values, students gain a tangible sense of how exponential functions behave, which is critical for further study and application in real-world scenarios.
Graphing Exponential Functions
Graphing is an invaluable tool for visually understanding how exponential functions behave. By plotting the points from a table of values, one can observe either an exponential growth or decay. Here's how it works:For the growth function \( y = e^x \), the graph revealed:
  • Points were plotted at coordinates \( (0, 1) \), \( (1, 2.718) \), \( (2, 7.389) \), and \( (3, 20.086) \).
  • Connecting these points forms a curve that rises steeply, illustrating the rapid increase characteristic of exponential growth.
For the decay function \( y = e^{-x} \), the decline appeared as:
  • Points marked the locations \( (0, 1) \), \( (1, 0.368) \), \( (2, 0.135) \), and \( (3, 0.050) \).
  • The curve drops swiftly, showing how values decrease quickly with greater \( x \).
Through graphing, students can have an immediate visual representation of how the function behaves across different values, reinforcing their understanding of exponential growth and decay.

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Most popular questions from this chapter

The infrastructure needs of a region (for example, the number of miles of electrical cable, the number of miles of roads, the number of gas stations) depend on its population. Cities enjoy economies of scale. \(^{90}\) For example, the number of gas stations is proportional to the population raised to the power of 0.77 (a) Write a formula for the number, \(N\), of gas stations in a city as a function of the population, \(P\), of the city. (b) If city \(A\) is 10 times bigger than city \(B\), how do their number of gas stations compare? (c) Which is expected to have more gas stations per person, a town of 10,000 people or a city of 500,000 people?

Kleiber's Law states that the metabolic needs (such as calorie requirements) of a mammal are proportional to its body weight raised to the 0.75 power. \(^{86}\) Surprisingly, the daily diets of mammals conform to this relation well. Assuming Kleiber's Law holds: (a) Write a formula for \(C,\) daily calorie consumption, as a function of body weight, \(W\) (b) Sketch a graph of this function. (You do not need scales on the axes.) (c) If a human weighing 150 pounds needs to consume 1800 calories a day, estimate the daily calorie requirement of a horse weighing 700 lbs and of a rabbit weighing 9 lbs. (d) On a per-pound basis, which animal requires more calories: a mouse or an elephant?

(a) Which (if any) of the functions in the following table could be linear? Find formulas for those functions. (b) Which (if any) of these functions could be exponential? Find formulas for those functions. $$\begin{array}{r|c|c|c} \hline x & f(x) & g(x) & h(x) \\ \hline-2 & 12 & 16 & 37 \\ -1 & 17 & 24 & 34 \\ 0 & 20 & 36 & 31 \\ 1 & 21 & 54 & 28 \\ 2 & 18 & 81 & 25 \\ \hline \end{array}$$

The demand curve for a product is given by \(q=\) \(120,000-500 p\) and the supply curve is given by \(q=\) \(1000 p\) for \(0 \leq q \leq 120,000,\) where price is in dollars. (a) At a price of \(\$ 100,\) what quantity are consumers willing to buy and what quantity are producers willing to supply? Will the market push prices up or down? (b) Find the equilibrium price and quantity. Does your answer to part (a) support the observation that market forces tend to push prices closer to the equilibrium price?

(a) Use the Rule of 70 to predict the doubling time of an investment which is earning \(8 \%\) interest per year. (b) Find the doubling time exactly, and compare your answer to part (a).

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