Chapter 7: Problem 8
Find the integrals. $$ \int(t+2) \sqrt{2+3 t} d t $$
Short Answer
Expert verified
The integral is \( \frac{2}{45} (2 + 3t)^{5/2} + \frac{8}{27} (2+3t)^{3/2} + C.\)
Step by step solution
01
Identify the Form of Integration
The integral \( \int(t+2) \sqrt{2+3t} \, dt \) involves a product of a polynomial and a square root function. Recognizing the form of the integral suggests using a substitution method.
02
Choose a Suitable Substitution
Let \( u = 2 + 3t \). Then, differentiate to find \( du = 3 \, dt \). Therefore, \( dt = \frac{du}{3} \). Adjusting the variables simplifies the integral.
03
Substitute and Simplify
Substitute into the integral: \( \int(t+2) \sqrt{u} \, \frac{du}{3} \). Note that \( t = \frac{u-2}{3} \) (from solving \( u = 2 + 3t \) for \( t \)).Replace \( t \) in the integral: \( \int \frac{(\frac{u-2}{3} + 2) \cdot \sqrt{u} }{3} \, du \).
04
Simplify the Integrand
Simplify the expression: \[ \int \left( \frac{u-2}{3} + 2 \right) \cdot \frac{\sqrt{u}}{3} \, du = \int \left( \frac{u-2}{9} + \frac{2}{3} \right) \sqrt{u} \, du \]This can be written as: \( \int \left( \frac{1}{9} u^{3/2} - \frac{2}{9} u^{1/2} + \frac{2}{3} u^{1/2} \right) \, du \).
05
Integrate Term by Term
Calculate the integral of each term separately:\[ \int \frac{1}{9} u^{3/2} \, du = \frac{1}{9} \cdot \frac{2}{5} u^{5/2}, \]\[ \int \frac{2}{9} u^{1/2} \, du = \frac{2}{9} \cdot \frac{2}{3} u^{3/2}, \]\[ \int \frac{2}{3} u^{1/2} \, du = \frac{2}{3} \cdot \frac{2}{3} u^{3/2}. \]
06
Substitute Back in Terms of t
Combine the integrated results and substitute back \( u = 2 + 3t \):\[ \frac{2}{45} (2 + 3t)^{5/2} + \left(-\frac{4}{27} + \frac{4}{9}\right)(2 + 3t)^{3/2} + C.\]Where \( C \) is the constant of integration.
07
Simplify the Expression
Simplify the expression:\[\frac{2}{45} (2 + 3t)^{5/2} + \frac{8}{27} (2+3t)^{3/2} + C. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique used to simplify complex integrals. It involves changing the variable of integration to make the integral easier to solve.
The main goal of substitution is to transform a difficult integral into a simpler form. This simplifies the calculation and achieves an easier solution.When applying the substitution method, you generally follow these steps:
The main goal of substitution is to transform a difficult integral into a simpler form. This simplifies the calculation and achieves an easier solution.When applying the substitution method, you generally follow these steps:
- Identify a part of the integrand to substitute with a new variable, usually by setting a complex expression equal to this new variable (commonly denoted as \(u\)).
- Differentiate this equation to find \(du\) in terms of \(dt\).
- Rewrite the original integral using \(u\) and \(du\) instead of \(t\) and \(dt\).
Polynomial Functions
Polynomial functions are expressions that involve terms in the form of \(x^n\), where \(n\) is a non-negative integer. In integrals, polynomials can often be split and handled individually, making them easier to integrate.In our integral, the expression \(t+2\) is a polynomial of degree 1, meaning it involves \(t\) raised to the power of 0 and 1 respectively.
These types of functions are straightforward to work with when integrating. After substituting \(u = 2 + 3t\), the polynomial \(t + 2\) is rewritten in terms of \(u\), making the entire expression much simpler.Key points about polynomial functions in integration:
These types of functions are straightforward to work with when integrating. After substituting \(u = 2 + 3t\), the polynomial \(t + 2\) is rewritten in terms of \(u\), making the entire expression much simpler.Key points about polynomial functions in integration:
- Polynomials can be integrated term by term.
- They often require algebraic manipulation to fit into a solvable form after substitution.
- Each term's integration involves using the power rule \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \) where \(n eq -1\).
Square Root Function
The square root function is characterized by its form \(\sqrt{x}\), which can introduce complexity in integration. However, when paired with substitution, it becomes much more tractable.For our integral \(\int(t+2) \sqrt{2+3t} \, dt\), the square root function \(\sqrt{2+3t}\) is reworked through substitution, letting \( u = 2 + 3t \).
The expression \(\sqrt{u}\) replaces \(\sqrt{2+3t}\), which allows the integral to be addressed easily.Integrating square roots often requires:
This rule dictates how to handle expressions raised to a fractional power, thus making the overall integration feasible.
The expression \(\sqrt{u}\) replaces \(\sqrt{2+3t}\), which allows the integral to be addressed easily.Integrating square roots often requires:
- Rewriting the square root in exponent form (e.g., \(\sqrt{u} = u^{1/2}\)).
- Utilizing substitution to transform complicated expressions into more straightforward forms.
This rule dictates how to handle expressions raised to a fractional power, thus making the overall integration feasible.