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Check that \(y=t^{4}\) is a solution to the differential equation \(t \frac{d y}{d t}=4 y\).

Short Answer

Expert verified
Yes, \( y = t^4 \) is a solution to the differential equation.

Step by step solution

01

Differentiate y with respect to t

The function provided is \( y = t^4 \). To check if it is a solution to the differential equation, we first need to compute \( \frac{d y}{d t} \). Using the power rule for differentiation, we find that \( \frac{d y}{d t} = 4t^3 \).
02

Substitute the derivative into the differential equation

The differential equation is \( t \frac{d y}{d t} = 4y \). We substitute \( \frac{d y}{d t} = 4t^3 \) and \( y = t^4 \) into the equation. This results in \( t (4t^3) = 4(t^4) \).
03

Simplify both sides of the equation

Simplify the left-hand side: \( t \cdot 4t^3 = 4t^{4} \). Simplifying the right-hand side gives \( 4t^4 = 4t^4 \).
04

Verify equality

Both sides of the equation, \( 4t^4 \), are equal after substitution and simplification. Hence, \( y = t^4 \) is indeed a solution to the given differential equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solution Verification
When tackling differential equations, verifying a solution is a crucial step. It involves substituting back into the original equation to see if it holds true. For our exercise, we have the function \( y = t^4 \). To verify if it's a solution to the differential equation \( t \frac{d y}{d t} = 4y \), we follow a simple process. First, differentiate \( y \) with respect to \( t \) to find \( \frac{d y}{d t} \). Then, both our original function and its derivative need to be plugged into the differential equation.
By substituting \( \frac{d y}{d t} = 4t^3 \) and \( y = t^4 \) into the equation, we form \( t(4t^3) = 4(t^4) \).
Finally, simplify both sides of this equation. If they match, as they do in this case \( 4t^4 = 4t^4 \), our initial function is verified as a correct solution. This process ensures that the function satisfies the differential equation under the given conditions.
Differentiation
Differentiation is a fundamental concept in calculus. It involves finding the derivative of a function, which gives you the rate of change. It’s like figuring out how a variable quantity changes at any given point. In our problem, we started with \( y = t^4 \).
The differentiation process required us to compute \( \frac{d y}{d t} \), which gives the slope of the function \( y \) or how \( y \) changes concerning \( t \). This involves using differentiation rules such as the power rule. By applying these rules, we discover that \( \frac{d y}{d t} = 4t^3 \).
Differentiating functions correctly is essential when solving differential equations. This allows solving problems where functions may not appear in explicit form, such as motion problems, economic models, and more.
Power Rule
The power rule is a quick and efficient way of differentiating functions where variables are raised to a power. It’s a handy tool in calculus that simplifies the process of finding derivatives. In the problem at hand, we used the power rule to differentiate \( y = t^4 \).
The rule states that for any function \( x^n \), its derivative is \( nx^{n-1} \). Therefore, applying the power rule to \( t^4 \) results in \( 4t^3 \).
Employing the power rule makes it easy to handle polynomial functions with any exponent. This technique is particularly useful because it saves time. It also provides accuracy in obtaining derivatives, which can then be used to check or predict real-world scenarios through differential equations.

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Most popular questions from this chapter

At \(1: 00 \mathrm{pm}\) one winter afternoon, there is a power failure at your house in Wisconsin, and your heat does not work without electricity. When the power goes out, it is \(68^{\circ} \mathrm{F}\) in your house. At \(10: 00 \mathrm{pm}\), it is \(57^{\circ} \mathrm{F}\) in the house, and you notice that it is \(10^{\circ} \mathrm{F}\) outside. (a) Assuming that the temperature, \(T\), in your home obeys Newton's Law of Cooling, write the differential equation satisfied by \(T\). (b) Solve the differential equation to estimate the temperature in the house when you get up at \(7: 00 \mathrm{am}\) the next morning. Should you worry about your water pipes freezing? (c) What assumption did you make in part (a) about the temperature outside? Given this (probably incorrect) assumption, would you revise your estimate up or down? Why?

A quantity \(W\) satisfies the differential equation $$ \frac{d W}{d t}=5 W-20 $$ (a) Is \(W\) increasing or decreasing at \(W=10 ? W=2\) ? (b) For what values of \(W\) is the rate of change of \(W\) equal to zero?

A country's infrastructure is its transportation and communication systems, power plants, and other public institutions. The Solow model asserts that the value of national infrastructure \(K\) increases due to investment and decreases due to capital depreciation. The rate of increase due to investment is proportional to national income, \(Y\). The rate of decrease due to depreciation is proportional to the value of existing infrastructure. Write a differential equation for \(K\).

A deposit of \(\$ 5000\) is made to a bank account paying \(1.5 \%\) annual interest, compounded continuously. (a) Write a differential equation for the balance in the account, \(B\), as a function of time, \(t\), in years. (b) Solve the differential equation. (c) How much money is in the account in 10 years?

Let \(w\) be the number of worms (in millions) and \(r\) the number of robins (in thousands) living on an island. Suppose \(w\) and \(r\) satisfy the following differential equations, which correspond to the slope field in Figure \(10.42\). $$ \frac{d w}{d t}=w-w r, \quad \frac{d r}{d t}=-r+w r $$ Assume \(w=2\) and \(r=2\) when \(t=0 .\) Do the numbers of robins and worms increase or decrease at first? What happens in the long run?

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