/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 An air-freshener starts with 30 ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An air-freshener starts with 30 grams and evaporates. In each of the following cases, write a formula for the quantity, \(Q\) grams, of air-freshener remaining \(t\) days after the start and sketch a graph of the function. The decrease is: (a) 2 grams a day (b) \(12 \%\) a day

Short Answer

Expert verified
(a) \( Q(t) = 30 - 2t \); (b) \( Q(t) = 30(0.88)^t \); Graphs: linear for (a), exponential for (b).

Step by step solution

01

Understand the Problem

We have to determine the remaining quantity of air-freshener, starting with 30 grams, given two different types of decrease over time: (a) a constant decrease of 2 grams per day, and (b) a percentage decrease of 12% per day.
02

Model Constant Decrease Case (a)

For the constant decrease of 2 grams per day, the quantity of air-freshener remaining can be modeled by a linear function. Since the decrease is constant, the formula is given by: \( Q(t) = 30 - 2t \), where \(Q(t)\) is the quantity of air-freshener remaining after \(t\) days.
03

Sketch the Graph for Case (a)

Draw a graph where the y-axis represents the quantity of air-freshener \( Q(t) \) and the x-axis represents time \( t \) in days. The graph for \( Q(t) = 30 - 2t \) will be a line starting at (0,30) and decreasing linearly with a slope of -2.
04

Model Percentage Decrease Case (b)

For a 12% daily decrease, we use an exponential decay function. After one day, the air-freshener retains 88% of its quantity. The formula is \( Q(t) = 30(0.88)^t \), where each day multiplies the remaining quantity by 0.88.
05

Sketch the Graph for Case (b)

Draw a graph with the y-axis for the quantity \(Q(t)\) and x-axis for time \(t\). For \( Q(t) = 30(0.88)^t \), the curve starts at (0,30) and decreases exponentially, approaching zero but never quite reaching it.
06

Compare Both Models

The linear model (a) shows a straight-line decrease, while the exponential model (b) shows a curved decrease which becomes less steep over time. Model (a) stops at 15 days where \( Q(t) = 0 \), while (b) asymptotically approaches zero, but never exactly reaches it.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Decay
Exponential decay is a process that decreases a quantity at a rate proportional to its current value. Unlike linear decrease, where the amount reduced is constant, exponential decay reduces the substance by a consistent percentage. In our example of the air-freshener, the decrease is 12% daily. This means that after each day, only 88% of the air-freshener is left. To model this mathematically, we use the formula: \[ Q(t) = Q_0(1 - r)^t \]
where - \( Q(t) \) is the quantity remaining after time \( t \), - \( Q_0 \) is the initial quantity, and - \( r \) is the rate of decay as a decimal. Here, \( Q_0 = 30 \) grams and \( r = 0.12 \). Therefore, the equation becomes \( Q(t) = 30(0.88)^t \). This formula shows how the air-freshener will decrease exponentially over time, continuing to get smaller and smaller, but never actually reaching zero. This reflects how real-world phenomena such as the decay of radioactive substances or depreciation of assets can be more accurately modeled with exponential decay.
Linear Function
A linear function represents a relationship in which there is a constant rate of change. This can be visualized as a straight line when graphed on a coordinate plane. In our air-freshener problem, the linear function models a situation where the substance decreases by a fixed amount each day. The formula representing this linear decrease is given as: \[ Q(t) = 30 - 2t \]
Here, - \( Q(t) \) is the remaining air-freshener after \( t \) days, - \( 30 \) is the starting quantity in grams, and - \( -2 \) is the rate of decrease in grams per day. When we graph this linear function, it produces a straight line starting from the point \((0, 30)\) and descends with a slope of -2. This means for every day that passes, 2 grams of the air-freshener evaporate, continuing until the quantity reaches zero. This type of function is common in scenarios where consistent or "steady" changes occur, like in monthly car payments or wage growth over time.
Modeling with Functions
Modeling with functions is a powerful mathematical tool for describing real-world situations. In this context, functions can portray how quantities change over time, with each function providing a different perspective based on the nature of the change.
  • A linear function is well-suited for steady, uniform changes, where the same amount is added or subtracted over equal intervals.
  • An exponential function fits scenarios where the rate of change is proportional to the current value, leading to rapid or tapered outcomes.
In our example, both linear and exponential functions were employed to model the diminishing quantity of air-freshener. The linear function \( Q(t) = 30 - 2t \) reflects a constant downward slope, indicating a uniform loss each day. Alternatively, the exponential function \( Q(t) = 30(0.88)^t \) provides insight into how the decrease becomes less aggressive over each continuing day.Understanding these differences allows us to select the appropriate function to model various situations. It empowers decision-making and prediction, whether it’s projecting financial depreciation, calculating dosage decay in medicine, or understanding population growth dynamics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A person is to be paid $$\$ 2000$$ for work done over a year. Three payment options are being considered. Option 1 is to pay the $$\$ 2000$$ in full now. Option 2 is to pay $$\$ 1000$$ now and $$\$ 1000$$ in a year. Option 3 is to pay the full $$\$ 2000$$ in a year. Assume an annual interest rate of \(5 \%\) a year, compounded continuously. (a) Without doing any calculations, which option is the best option financially for the worker? Explain. (b) Find the future value, in one year's time, of all three options. (c) Find the present value of all three options.

A firm decides to increase output at a constant relative rate from its current level of 20,000 to 30,000 units during the next five years. Calculate the annual percent rate of increase required to achieve this growth.

A company is considering whether to buy a new machine, which costs $$\$ 97,000$$. The cash flows (adjusted for taxes and depreciation) that would be generated by the new machine are given in the following table: $$ \begin{array}{c|c|c|c|c} \hline \text { Year } & 1 & 2 & 3 & 4 \\ \hline \text { Cash flow } & \$ 50,000 & \$ 40,000 & \$ 25,000 & \$ 20,000 \\ \hline \end{array} $$ (a) Find the total present value of the cash flows. Treat each year's cash flow as a lump sum at the end of the year and use an interest rate of \(7.5 \%\) per year, compounded annually. (b) Based on a comparison of the cost of the machine and the present value of the cash flows, would you recommend purchasing the machine?

Kleiber's Law states that the metabolic needs (such as calorie requirements) of a mammal are proportional to its body weight raised to the \(0.75\) power. \(^{67}\) Surprisingly, the daily diets of mammals conform to this relation well. Assuming Kleiber's Law holds: (a) Write a formula for \(C\), daily calorie consumption, as a function of body weight, \(W\). (b) Sketch a graph of this function. (You do not need scales on the axes.) (c) If a human weighing 150 pounds needs to consume 1800 calories a day, estimate the daily calorie requirement of a horse weighing 700 lbs and of a rabbit weighing 9 lbs. (d) On a per-pound basis, which animal requires more calories: a mouse or an elephant?

Write a formula representing the function. The average velocity, \(v\), for a trip over a fixed distance, \(d\), is inversely proportional to the time of travel, \(t .\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.