Chapter 3: Problem 5
Show that \(\alpha=\sqrt{2}+i\) is of degree 4 over \(\mathrm{Q}\) and of degree 2 over \(R\). Determine the minimal polynomial of \(\alpha\) in both cases.
Short Answer
Expert verified
The degree of \(\sqrt{2} + i\) is 4 over \(\mathrm{Q}\) and 2 over \(R\). The minimal polynomial of \(\sqrt{2} + i\) over \(\mathrm{Q}\) is \(x^4 - 2x^2 + 3\) and over \(R\) is \(x^2 - 2x + 3\).
Step by step solution
01
Degree over \(\mathrm{Q}\)
Consider \(\alpha^n\) for each \(n\geq 1\). For \(n=1\), \(\alpha^1= \sqrt{2}+i\). For \(n=2\), one obtains \(\alpha^2 = \alpha^1 \cdot \alpha^1 = (\sqrt{2}+i)(\sqrt{2}+i) = 2 + 2i\sqrt{2} - 1 = 1 + 2i\sqrt{2} \). Square this again to get \(\alpha^4 = 1 - 8 + 4i\sqrt{2} = -7 + 4i\sqrt{2}\). Notice that \(\alpha^3\) would already contain a term \(i\sqrt{8}\) so \(\alpha^4\) is the first power of \(\alpha\) that can be expressed in terms of \(\mathrm{Q}\). So, the degree of \(\sqrt{2} + i\) over \(\mathrm{Q}\) is indeed 4.
02
Minimal polynomial over \(\mathrm{Q}\)
The minimal polynomial of \(\sqrt{2} + i\) over \(\mathrm{Q}\) is the monic polynomial which \(\sqrt{2} + i\) satisfies that has \(\mathrm{Q}\) as coefficients and has the smallest degree which is 4. It is \(p(x) = (x^2 - (\sqrt{2} + i))(x^2 - (\sqrt{2} - i)) = x^4 - 2x^2 + 3\).
03
Degree over \(R\)
If one calculate square of \(\alpha = \sqrt{2} + i\), result will be \(\alpha^2 = 1 + 2i\sqrt{2}\). It can be seen clearly that, this expression cannot be simplified using only real numbers. However, if you square it one more time, you get \(\alpha^4 = -7 + 4i\sqrt{2}\). After this, it's straightforward to express this using real numbers. Thus, degree of \(\sqrt{2} + i\) is 2 over \(R\).
04
Minimal polynomial over \(R\)
The minimal polynomial of \(\sqrt{2} + i\) over \(R\) is the monic polynomial which \(\sqrt{2} + i\) is a root of that has \(R\) as coefficients and has the smallest degree which is 2. It is \(p(x) = x^2 - 2x + 3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Degree of a Polynomial
Understanding the degree of a polynomial involves identifying the highest power of the variable present in the polynomial. For a polynomial like \[ ax^n + bx^{n-1} + ext{...} + k \]the degree is \( n \), assuming \( a \) is not zero.
In the context of field extensions, the degree of an element \( \alpha \) over a field \( F \) refers to the smallest degree of any polynomial with coefficients in \( F \) that has \( \alpha \) as a root.
For example, if \( \alpha=\sqrt{2}+i \), the degree of \( \alpha \) over \( \mathbb{Q} \) (the field of rational numbers) is 4. This is because the minimal polynomial of \( \alpha \) over \( \mathbb{Q} \) is of degree 4.
In the context of field extensions, the degree of an element \( \alpha \) over a field \( F \) refers to the smallest degree of any polynomial with coefficients in \( F \) that has \( \alpha \) as a root.
For example, if \( \alpha=\sqrt{2}+i \), the degree of \( \alpha \) over \( \mathbb{Q} \) (the field of rational numbers) is 4. This is because the minimal polynomial of \( \alpha \) over \( \mathbb{Q} \) is of degree 4.
- \( \alpha^4 = -7 + 4i\sqrt{2} \)
- Only in this power can \( \alpha \) be expressed in terms of \( \mathbb{Q} \)
- The minimal polynomial here is \( x^2 - 2x + 3 \), leading to a simpler 2nd degree polynomial.
Minimal Polynomial
The minimal polynomial is crucial in understanding algebraic field extensions. It is the polynomial of the smallest degree that has a given algebraic number \( \alpha \) as a root.
For \( \alpha = \sqrt{2} + i \), consider its minimal polynomial over different fields:
For \( \alpha = \sqrt{2} + i \), consider its minimal polynomial over different fields:
- **Over \( \mathbb{Q} \):** The minimal polynomial is \( x^4 - 2x^2 + 3 \). This polynomial uniquely determines \( \alpha \) since it’s the smallest with rational coefficients.
- **Over \( \mathbb{R} \):** The simplification happens, and the minimal polynomial is \( x^2 - 2x + 3 \). Real numbers allow the terms to be condensed, reducing the degree.
Complex Numbers
Complex numbers are numbers in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit satisfying \( i^2 = -1 \).
In the study of field extensions, complex numbers bring complexity but also elegance through their properties:
Complex numbers thus provide a versatile framework to explore algebraic structures and uncover deeper mathematical properties.
In the study of field extensions, complex numbers bring complexity but also elegance through their properties:
- **Imaginary Part:** Allows the expression of numbers that would otherwise not exist in the real number system.
- **Field Extension Use:** Complex numbers like \( \sqrt{2} + i \) showcase how algebraic elements extend fields beyond the reals.
- **Root Expression:** With complex coefficients, certain polynomials with no real roots can have solutions.
Complex numbers thus provide a versatile framework to explore algebraic structures and uncover deeper mathematical properties.