Chapter 2: Problem 16
Solve the given inequality and express your answer in interval notation. $$ x^{2}-2 x+8 \leq 2 x+5 $$
Short Answer
Expert verified
The solution is \([1, 3]\).
Step by step solution
01
Move All Terms to One Side
First, subtract \(2x+5\) from both sides of the inequality to bring all terms to one side. This gives:\[x^2 - 2x + 8 - 2x - 5 \ = x^2 - 4x + 3 \ \leq 0\]
02
Factor the Quadratic Expression
Next, factor the quadratic expression \(x^2 - 4x + 3\). We need to find two numbers whose product is 3 and whose sum is -4. These numbers are -1 and -3. Thus:\[x^2 - 4x + 3 = (x - 1)(x - 3)\]
03
Determine the Critical Points
Solve \((x - 1)(x - 3) = 0\) to find the critical points where the expression equals zero. Set each factor equal to zero:\[x - 1 = 0 \Rightarrow x = 1\]\[x - 3 = 0 \Rightarrow x = 3\]
04
Test Intervals Around Critical Points
Now test intervals around the critical points to see where the inequality \((x - 1)(x - 3) \leq 0\) holds. The three intervals based on critical points 1 and 3 are:1. \(x < 1\) (e.g., \(x = 0\))2. \(1 < x < 3\) (e.g., \(x = 2\))3. \(x > 3\) (e.g., \(x = 4\))Evaluate the sign of \((x - 1)(x - 3)\) in each interval:- For \(x = 0\), \((0-1)(0-3) = (+)\), does not satisfy \(\leq 0\).- For \(x = 2\), \((2-1)(2-3) = (-)\), satisfies \(\leq 0\).- For \(x = 4\), \((4-1)(4-3) = (+)\), does not satisfy \(\leq 0\).
05
Include Critical Points
Check if critical points \(x = 1\) and \(x = 3\) satisfy the inequality. Both points make \((x - 1)(x - 3) = 0\), which satisfies \(\leq 0\). Therefore, include \([1, 3]\) in the solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Inequalities
Quadratic inequalities are inequalities that involve a quadratic expression, which is an expression containing a term with a square, like \(x^2\). This type of inequality can often be expressed in the form \(ax^2 + bx + c \leq 0\), \(ax^2 + bx + c \geq 0\), or with strict inequalities like \(<\) or \(>\). Solving quadratic inequalities involves finding the values of \(x\) for which the inequality holds true. The solution process typically involves the following steps:
- Moving all terms to one side to create an expression set less than or greater than zero.
- Factoring the quadratic expression to find its roots, also known as critical points.
- Testing intervals determined by the critical points to see where the inequality is satisfied.
- Using these intervals to express the solution in interval notation, which provides a concise way of describing ranges of values for \(x\).
Factoring Quadratic Expressions
Factoring is a crucial method used to solve quadratic inequalities and equations. A quadratic expression of the form \(x^2 + bx + c\) can frequently be rewritten as a product of two binomials, namely \((x + m)(x + n)\), where:
- \(m\) and \(n\) are numbers whose product is \(c\) and sum is \(b\).
Interval Notation
Interval notation is a succinct way to describe the set of solutions to an inequality. It uses brackets and parentheses to denote intervals and whether endpoints are included in the solution:- **Square brackets** \([\), \(]\) indicate that an endpoint is included (\(\leq\) or \(\geq\)).- **Parentheses** \((\), \()\) show that an endpoint is not included (\(<\) or \(>\)).For example, if after checking the intervals in a quadratic inequality, you find that values between 1 and 3 satisfy the condition, with both endpoints included, the interval notation is \([1, 3]\). This notation means all \(x\) in the range from 1 to 3, inclusive, satisfy the inequality.
Critical Points in Inequalities
Critical points in a quadratic inequality are the values of \(x\) where the quadratic expression equals zero. These points are found by solving \((x - m)(x - n) = 0\), resulting in \(x = m\) and \(x = n\). In the inequality \((x - 1)(x - 3) \leq 0\), the critical points are 1 and 3. Graphically, these points are where the parabola intersects the x-axis.Determining critical points helps divide the number line into intervals that can be tested to see where the inequality holds. After finding critical points, test intervals:
- Choose test values from the intervals formed around critical points.
- Check the signs of the expression at these points.
- Determine which intervals satisfy the inequality.