Chapter 6: Problem 9
Evaluate the indefinite integral. \(\int \frac{-4}{3 x^{2}-12} d x\)
Short Answer
Expert verified
\( \int \frac{-4}{3 x^{2}-12} d x = \frac{2}{3} \ln \left| \frac{x-2}{x+2} \right| + C \)
Step by step solution
01
Simplify the Expression
Factor out common terms from the denominator. The expression inside the integral is \( \frac{-4}{3x^2 - 12} \). Notice that the denominator can be factored. Rewrite it as \( 3(x^2 - 4) \) by factoring out 3. Thus, the integral becomes:\[\int \frac{-4}{3(x^2 - 4)} \, dx\]
02
Apply Substitution
For easier integration, use the substitution method. Set \( u = x^2 - 4 \). Then, compute \( du = 2x \, dx \) or \( x \, dx = \frac{1}{2} \, du \). We need this to substitute in the integral.
03
Adjust the Integral
Since the original integral does not directly match the substitution \( x \, dx \), we reconsider the substitution. Recognizing \( x^2 - 4 = (x-2)(x+2) \), note the integral involves a square difference which hints to adjusting into partial fraction or recognizing integral forms. Let's rewrite and substitute:\[\int \frac{-4}{3 \cdot (x-2)(x+2)} \, dx\]
04
Perform Direct Integration
Recognizing we have an integrable form, recall standard integrals for \( \int \frac{1}{x^2 - a^2} \, dx \) which pieces to \( \int \frac{1}{a} \ln|x-a| - \frac{1}{a} \ln|x+a| + C\) for distinct linear factors. Specifically, \( \int \frac{-4}{3 \cdot (x-2)(x+2)} \, dx \) involves applying the logarithm result:Divide the expression as\[ \int \frac{-4/6}{x-2} - \frac{-4/6}{x+2} \, dx\]
05
Solve the Integral
Directly integrate each part separately:For the first part, you find:\[ -\frac{4}{6} \ln |x-2| - (-\frac{4}{6} \ln |x+2|) \]Combining these gives:\[ \frac{2}{3} \ln \left| \frac{x-2}{x+2} \right| + C \]
06
Finalize the Answer
Put together the results from differentiation and substitution steps across partial integrations:Combine intermediate steps to summarize the result as:\[ \frac{2}{3} \ln \left| \frac{x-2}{x+2} \right| + C \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful technique used in calculus to simplify the process of integration. It involves changing the variable of integration to make the problem more manageable. Typically, you identify a part of the integrand that can be substituted with a single variable, say \( u \).
- Substitution helps convert a complex integral into a simpler form.
- It is similar to the chain rule in differentiation.
- The key is choosing the right substitution.
Partial Fraction Decomposition
Partial fraction decomposition is a technique used to simplify rational expressions, especially useful in integration. It breaks down a complex fraction into simpler fractions that are easier to integrate.
- This is particularly handy for polynomial denominators.
- Each fraction has a denominator of lower degree than the original.
- The integrands become easier to manage.
Indefinite Integral
An indefinite integral is the reverse process of differentiation - essentially, it seeks the function whose derivative gives the original function. Indefinite integrals include a constant of integration, \( C \), because differentiation of a constant is zero.
- Symbolically represented by \( \int f(x) \, dx \).
- It leads to a family of functions, not just a single value.
- Often requires simplification or algebraic manipulation.
Factorization
Factorization plays a crucial role in simplifying expressions, particularly when dealing with algebraic fractions. This process involves expressing a polynomial as the product of its factors.
- Vital for simplifying expressions for easier integration.
- Helps reveal possible substitution methods or partial fractions.
- Allows isolation of roots or critical points in functions.