Chapter 6: Problem 8
Evaluate the indefinite integral to develop an understanding of Substitution. $$ \int \frac{1}{\sqrt{2 x+3}} d x $$
Short Answer
Expert verified
The integral is \((2x + 3)^{\frac{1}{2}} + C\).
Step by step solution
01
Identify the function to be substituted
Consider the expression under the square root, which is \(2x + 3\). We will set this equal to a new variable: \( u = 2x + 3 \). This will simplify the integral.
02
Differentiate the substitution expression
Differentiate the expression \( u = 2x + 3 \) with respect to \( x \) to find the differential \( du \) in terms of \( dx \). This gives us \( \frac{du}{dx} = 2 \), hence \( du = 2dx \).
03
Solve for dx
Rearrange the expression \( du = 2 dx \) to solve for \( dx \). Thus, \( dx = \frac{1}{2}du \).
04
Substitute into the integral
Substitute \( u \) and \( dx \) into the original integral. The original integral \( \int \frac{1}{\sqrt{2x+3}} \, dx \) becomes \( \int \frac{1}{\sqrt{u}} \cdot \frac{1}{2} \, du \).
05
Simplify and integrate
Factor out the constant \( \frac{1}{2} \): \( \frac{1}{2} \int u^{-\frac{1}{2}} \, du \). Integrate \( u^{-\frac{1}{2}} \) to get \( 2u^{\frac{1}{2}} + C \). Combined with the constant factor, it becomes \( u^{\frac{1}{2}} + C \).
06
Back-substitute for the original variable
Replace \( u \) with \( 2x + 3 \), the original substitution: \( (2x + 3)^{\frac{1}{2}} + C \). This represents the indefinite integral in terms of \( x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a technique used in calculus to simplify the process of evaluating integrals. By transforming the integral into a simpler form, it becomes easier to handle. In our problem, the expression inside the square root, \(2x + 3\), is replaced with a new variable, \(u\).
- Identify the complex part of the integral: the expression \(2x + 3\) in \(\int \frac{1}{\sqrt{2x+3}} \, dx\).
- Set \(u = 2x + 3\), transforming the integrand into a simpler expression.
Differentiation
Differentiation is key in the substitution method, as it allows us to relate the variables \(x\) and \(u\). By differentiating the substitution expression \(u = 2x + 3\) with respect to \(x\), we find the relationship between \(dx\) and \(du\). The derivative \(\frac{du}{dx} = 2\) gives us \(du = 2dx\). This relationship is crucial for replacing \(dx\) and ensuring the integral remains valid, letting us rewrite \(dx\) as \(\frac{1}{2} du\). This step ensures a clear path for substituting every term.
Integration
Once the substitution and differentiation are done, the integral takes on a simpler form: \(\int \frac{1}{\sqrt{u}} \cdot \frac{1}{2} \, du\). Factor out constants to simplify further:
- Recognize \(\int u^{-1/2} \, du\) is a basic power rule problem.
- Apply the power rule: the integral of \(u^{-1/2}\) is \(2u^{1/2} + C\).
Variable Substitution
After integrating in terms of \(u\), it's time to reintroduce the original variable \(x\). This step is known as back-substitution.Replace \(u\) with the original expression \(2x + 3\) that was substituted, resulting in \((2x + 3)^{1/2} + C\). This final expression represents the indefinite integral in terms of \(x\), concluding the substitution process.