/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Evaluate the indefinite integral... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the indefinite integral. \(\int \sin ^{3} x \cos ^{2} x d x\)

Short Answer

Expert verified
\( \frac{\cos^5 x}{5} - \frac{\cos^3 x}{3} + C \)

Step by step solution

01

Simplify the Expression

Start by recognizing that the integral \( \int \sin^3 x \cos^2 x \, dx \) can be approached by rewriting one of the trigonometric functions using Pythagorean identities. Since one function has an odd power, isolate \( \sin^3 x \) as \( \sin^2 x \sin x \). This gives \( \int \sin^2 x \cdot \sin x \cdot \cos^2 x \, dx \).
02

Use Trigonometric Identity

Rewrite \( \sin^2 x \) using the identity \( \sin^2 x = 1 - \cos^2 x \). The integral becomes \( \int (1 - \cos^2 x) \sin x \cos^2 x \, dx \). This simplifies to \( \int (\sin x \cos^2 x - \sin x \cos^4 x) \, dx \).
03

Substitute \( u = \cos x \)

Let \( u = \cos x \), which means \( du = -\sin x \, dx \) or \( -du = \sin x \, dx \). Substitute this into the integral: \( \int (u^2 - u^4)(-du) \), which simplifies to \( \int (u^4 - u^2) \, du \).
04

Integrate with Respect to \( u \)

Now integrate \( \int (u^4 - u^2) \, du \), which gives:\[ \int u^4 \, du - \int u^2 \, du = \frac{u^5}{5} - \frac{u^3}{3} + C \].
05

Substitute Back \( x \)

Since \( u = \cos x \), substitute back to get:\[ \frac{\cos^5 x}{5} - \frac{\cos^3 x}{3} + C \]. This is the antiderivative of the original integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Substitution
Trigonometric substitution is a technique used to simplify the integration process, especially when dealing with integrals involving square roots or powers of trigonometric functions. By substituting trigonometric identities, we transform the integral into a simpler form.

In our example of \( \int \sin^3 x \cos^2 x \, dx \), we use trigonometric substitution to handle the odd power of \( \sin x \). The substitution \( \sin^2 x = 1 - \cos^2 x \) helps pivot the integral into a more manageable form.

  • This substitution rearranges the integral to \( \int (1 - \cos^2 x) \sin x \cos^2 x \, dx \).
  • It allows us to express powers of sine and cosine in a way that prepares the integral for further simplification and integration.

This strategic substitution can make complicated integrals more approachable and is a common practice in calculus to streamline integration tasks.
Pythagorean Identity
The Pythagorean identity is a fundamental trigonometric identity that relates the squares of sine and cosine functions: \( \sin^2 x + \cos^2 x = 1 \).
This identity is incredibly useful in calculus for simplifying integrals involving trigonometric functions.

For instance, when we encounter \( \sin^3 x \cos^2 x \), and since one of the trigonometric functions \( \sin^2 x \) has an odd power, isolating it using the Pythagorean identity transforms it into \( \sin^2 x = 1 - \cos^2 x \).
This facilitates breaking down the integral into more straightforward components that can be tackled individually.

  • Aids in transforming complex trigonometric expressions.
  • Helps in setting up simpler integrals for evaluation.
  • Reduces dependency on complex powers, making manipulation easier.

Utilizing the Pythagorean identity is a powerful tool that enhances our ability to solve trigonometric integrals by making them more straightforward.
Integration by Substitution
Integration by substitution, often called "u-substitution," is a method used to evaluate integrals by transforming a given integral into a simpler form. It involves substituting part of the integral with a new variable, typically represented by \( u \), which makes it easier to integrate.

In our solution to \( \int \sin^3 x \cos^2 x \, dx \), after rewriting with a trigonometric identity, substitution is applied:
  • Select \( u = \cos x \) which implies \( du = -\sin x \, dx \).
  • Replace the integral terms involving \( \sin x \, dx \) with \( -du \), transforming the integral into \( \int (u^4 - u^2) \, du \).

This substitution simplifies the function and reduces the number of trigonometric terms.
From there, we integrate the resulting expression with respect to \( u \), yielding the antiderivative.

Finally, substituting back \( x \) for \( u \) provides the solution to the original integral.
This technique, while seeming complex at first, becomes intuitive with practice.
It's a versatile tool in calculus, especially effective for handling integrals of products and compositions of functions.

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