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Find \(f(x)\) described by the given initial value problem. $$ f^{\prime}(x)=7^{x} \text { and } f(2)=1 $$

Short Answer

Expert verified
The function is \( f(x) = \frac{7^x - 49}{\ln(7)} + 1 \).

Step by step solution

01

Integrate to Find General Solution

To find the function \( f(x) \), we need to integrate the derivative \( f'(x) = 7^x \). The integral of \( 7^x \) with respect to \( x \) is \( \frac{7^x}{\ln(7)} + C \). Therefore, the general solution is \( f(x) = \frac{7^x}{\ln(7)} + C \), where \( C \) is a constant.
02

Apply the Initial Condition

We are given the initial condition \( f(2) = 1 \). Substitute \( x = 2 \) and \( f(2) = 1 \) into the general solution: \[ 1 = \frac{7^2}{\ln(7)} + C \].Calculate \(7^2 = 49\), so the equation becomes \[ 1 = \frac{49}{\ln(7)} + C \].
03

Solve for the Constant C

Rearrange the equation from Step 2 to solve for \( C \): \[ 1 - \frac{49}{\ln(7)} = C \].Now you have \( C = 1 - \frac{49}{\ln(7)} \).
04

Write the Particular Solution

Substitute the value of \( C \) back into the general solution to get the particular solution: \[ f(x) = \frac{7^x}{\ln(7)} + \left(1 - \frac{49}{\ln(7)}\right) \].Simplify this to \[ f(x) = \frac{7^x - 49}{\ln(7)} + 1 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration
Integration is a fundamental concept in calculus. It is the process of finding the antiderivative, which is basically the reverse of differentiation.
When you encounter a derivative function, like in our problem where we have \( f'(x) = 7^x \), you can "integrate" this function to find the original function, \( f(x) \).

The goal of integration is to find the area under the curve of a function. In simpler terms, if differentiation breaks down a function into its rate of change, integration pieces it back together to find the original function.
  • To integrate \( 7^x \), we use the formula \( \int a^x \, dx = \frac{a^x}{\ln a} + C \), where \( C \) is a constant.
  • Using this, integrating \( 7^x \) results in \( \frac{7^x}{\ln 7} + C \).
The constant \( C \) arises because integration is not a precise point function; instead, it provides a family of functions that differ by a constant.
Exponential Functions
Exponential functions are those which involve exponential expressions such as \( a^x \), where \( a \) is a positive constant.
These functions display constant growth or decay rates proportional to their value.
In our exercise, the function \( 7^x \) is an exponential function which shows exponential growth.

Exponential functions have unique characteristics:
  • The base, \( a \), should be greater than zero and not equal to one.
  • As \( x \) increases, \( a^x \) grows rapidly when \( a > 1 \).
In calculus problems, knowing how to recognize and manipulate exponential components is crucial. When you have the derivative \( f'(x) = 7^x \), integrating it involves recognizing the base \( 7 \) and applying the integration rules specific to exponential functions.
Constant of Integration
The constant of integration, commonly denoted by \( C \), plays a significant role in the process of integration.
Since integration gives an entire family of solutions, the constant \( C \) represents the infinite family of functions that have the same derivative.
  • When integrating a function like \( 7^x \), \( C \) is included to account for any potential initial values or conditions.
  • The constant is determined by applying any initial conditions or boundary values provided in a problem.
In our example, after integrating to find the general solution \( f(x) = \frac{7^x}{\ln(7)} + C \), the initial condition \( f(2) = 1 \) is used to find the specific value of \( C \). By substituting these values into the general solution, we isolate \( C \) and use it to find the particular solution, showing how initial values solidify the solution as a single specific function.

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