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Use differentials to approximate the given value by hand. \(5.1^{3}\)

Short Answer

Expert verified
Approximate value of \(5.1^3\) is 132.5.

Step by step solution

01

Identify the function and point

The function we are dealing with is \(f(x) = x^3\). We want to approximate \(5.1^3\), so we'll choose \(a = 5\) because \(5.1\) is near 5. Then, \(f(a) = 5^3 = 125\).
02

Find the derivative and calculate the differential

First, calculate the derivative of \(f(x)\): \(f'(x) = 3x^2\). At \(x = 5\), \(f'(5) = 3 \times 5^2 = 75\). The differential \(df\) at this point is given by the formula \(df = f'(a) \, dx\), where \(dx\) is the small change in \(x\), which is \(dx = 5.1 - 5 = 0.1\). Thus, \(df = 75 \cdot 0.1 = 7.5\).
03

Approximate the original value

To find the approximate value of \(5.1^3\), use the formula \(f(a + dx) \approx f(a) + df\). This gives us \(5.1^3 \approx 125 + 7.5 = 132.5\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Approximation Techniques
When faced with complex calculations, approximation techniques can be a powerful tool. These methods help us get close to an actual number without doing the exhaustive math. Here, we used differentials to approximate the value of \(5.1^3\). The idea is simple: instead of working out the full calculation, we "zoomed in" on a known value near our target number.
This technique relies on recognizing a mathematical function, such as \(f(x) = x^3\), and calculating derivatives to find a tangent line at a point close to the number we're interested in. With this approach, calculating \(5.1^3\) becomes less taxing. We first considered the number 5, which is near 5.1, because \(5^3\) is easy to compute.
  • Begin with a function \(f(x)\).
  • Next, determine a close, easily calculable point, like \(x = 5\).
  • Find the derivative to explore changes around your point.
This trims down complex multiplication into a simple addition, making math both quick and accurate for close estimates.
Derivatives
Derivatives are like the secret weapon in calculus and play a vital role in approximation techniques. In essence, a derivative shows how a function changes as its input changes. Here, our function was \(f(x) = x^3\), so the derivative is \(f'(x) = 3x^2\).
This derivative tells us the slope of the tangent line at any point \(x\) on our cubic curve. So, when \(x = 5\), we calculated \(f'(5) = 75\). This is the "rate of change" when \(x\) hovers around 5, giving us critical insights into how the function behaves close to this number.
  • Calculate the derivative of your function for insight into its behavior.
  • A derivative can simplify complex calculations by providing tangent line approximations.
  • These insights are generally captured with equations like \(df = f'(a) \, dx\).
It's all about understanding the dynamics of change — a key aspect when using approximations.
Mathematical Functions
Mathematical functions serve as the backbone for organizing and solving problems in calculus. They provide a structured rule that relates an input to an output. In our case, the function \(f(x) = x^3\) dictated our approach for approximating \(5.1^3\).
Functions are like machines: you put a number in, and they "process" it to produce another number. But beyond their basic use, they have properties like continuity and differentiability, which we harness in advanced techniques like using derivatives and differentials.
  • Identify and define your function, such as \(f(x) = x^3\).
  • Use familiar values (like \(a = 5\)) to ease calculations.
  • Explore the changes through derivatives to better approximate values near those familiar points.
By understanding functions deeply, you can break down larger problems into manageable parts, making math more achievable.

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Most popular questions from this chapter

A hot air balloon lifts off from ground rising vertically. From 100 feet away, a \(5^{\prime}\) woman tracks the path of the balloon. When her sightline with the balloon makes a \(45^{\circ}\) angle with the horizontal, she notes the angle is increasing at about \(5^{\circ} / \mathrm{min} .\) (a) What is the elevation of the balloon? (b) How fast is it rising?

A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The man holds the rope at the same height as the connection point between rope and weight. Suppose the man stands directly next to the weight (i.e., a total rope length of \(60 \mathrm{ft}\) ) and begins to walk away at a rate of \(2 \mathrm{ft} / \mathrm{s}\). How fast is the weight rising when the man has walked: (a) 10 feet? (b) 40 feet? How far must the man walk to raise the weight all the way to the pulley?

Exercises 31-34 use differentials to approximate propagated error. A set of plastic spheres are to be made with a diameter of \(1 \mathrm{~cm}\). If the manufacturing process is accurate to \(1 \mathrm{~mm}\), what is the propagated error in volume of the spheres?

A standard soda can is roughly cylindrical and holds \(355 \mathrm{~cm}^{3}\) of liquid. What dimensions should the cylinder be to minimize the material needed to produce the can? Based on your dimensions, determine whether or not the standard can is produced to minimize the material costs.

Use Newton's Method to approximate all roots of the given functions accurate to 3 places after the decimal. If an interval is given, find only the roots that lie in that interval. Use technology to obtain good initial approximations. $$ f(x)=x^{17}-2 x^{13}-10 x^{8}+10 \text { on }(-2,2) $$

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