Chapter 14: Problem 15
Find the divergence and curl of the given vector field. \(\vec{F}=\nabla f,\) where \(f(x, y)=\frac{1}{2} x^{2}+\frac{1}{3} y^{3}\)
Short Answer
Expert verified
Divergence: \(1 + 2y\); Curl: \(0\).
Step by step solution
01
Compute the Gradient of f
The first step is to compute the gradient of the scalar function \(f(x, y) = \frac{1}{2}x^2 + \frac{1}{3}y^3\). The gradient \( abla f \) is found by calculating the partial derivatives of \(f\) with respect to each variable and forming a vector. \[ abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \]Calculate the partial derivatives:- \( \frac{\partial f}{\partial x} = x \)- \( \frac{\partial f}{\partial y} = y^2 \)Thus, \(\vec{F} = abla f = (x, y^2) \).
02
Find the Divergence of Vector Field F
The divergence of a vector field \(\vec{F} = (P(x, y), Q(x, y))\) is given by \(abla \cdot \vec{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y}\).For \(\vec{F} = (x, y^2)\):- \( P(x, y) = x \) and \( Q(x, y) = y^2 \)Now compute the partial derivatives:- \( \frac{\partial P}{\partial x} = \frac{\partial x}{\partial x} = 1 \)- \( \frac{\partial Q}{\partial y} = \frac{\partial y^2}{\partial y} = 2y \)Therefore, the divergence is:\[ abla \cdot \vec{F} = 1 + 2y = 1 + 2y \].
03
Find the Curl of Vector Field F
In two dimensions, the curl of a vector field \(\vec{F} = (P(x, y), Q(x, y))\) is defined as \(abla \times \vec{F} = \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\).For \(\vec{F} = (x, y^2)\):- \( \frac{\partial Q}{\partial x} = \frac{\partial y^2}{\partial x} = 0 \)- \( \frac{\partial P}{\partial y} = \frac{\partial x}{\partial y} = 0 \)Thus, the curl is:\[ abla \times \vec{F} = 0 - 0 = 0 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient
In vector calculus, the gradient plays a crucial role in understanding how a scalar field changes in space. Think of the gradient as a vector that indicates the direction and rate of the fastest increase of a function. When dealing with functions of two variables, like our example function \( f(x, y) = \frac{1}{2}x^2 + \frac{1}{3}y^3 \), the gradient is calculated by taking partial derivatives of \( f \) with respect to each variable.
- Partial Derivative Definition: A partial derivative of a function of several variables is its derivative with respect to one of those variables, with the other variables held constant.
- \( \frac{\partial f}{\partial x} = x \)
- \( \frac{\partial f}{\partial y} = y^2 \)
Divergence
Divergence is another key concept in vector calculus. It measures the magnitude of a vector field's source or sink at a given point, essentially telling us how much the field spreads out or converges. It's a scalar value, indicating how a vector field's flow expands or contracts. For a two-dimensional vector field \( \vec{F} = (P(x, y), Q(x, y)) \), the divergence is calculated as follows:\[ abla \cdot \vec{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} \]In our example, where \( \vec{F} = (x, y^2) \):
- \( P(x, y) = x \) with \( \frac{\partial P}{\partial x} = 1 \)
- \( Q(x, y) = y^2 \) with \( \frac{\partial Q}{\partial y} = 2y \)
Curl
The curl of a vector field in two dimensions offers insights into the rotational characteristics of the field. It detects the tendency of a field to rotate around a point. Mathematically speaking, for a two-dimensional vector field \( \vec{F} = (P(x, y), Q(x, y)) \), the curl is defined by:\[ abla \times \vec{F} = \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \]In our specific example, the vector field is \( \vec{F} = (x, y^2) \):
- \( \frac{\partial Q}{\partial x} = \frac{\partial y^2}{\partial x} = 0 \)
- \( \frac{\partial P}{\partial y} = \frac{\partial x}{\partial y} = 0 \)