Chapter 10: Problem 38
Find a unit vector orthogonal to both \(\vec{u}\) and \(\vec{v} .\) \(\vec{u}=\langle 1,-2,1\rangle, \quad \vec{v}=\langle-2,4,-2\rangle\)
Short Answer
Expert verified
No such unit vector exists; \(\vec{u}\) and \(\vec{v}\) are parallel.
Step by step solution
01
Find the Cross Product
To find a unit vector orthogonal to both \(\vec{u}\) and \(\vec{v}\), we first need to find the cross product \(\vec{u} \times \vec{v}\). The cross product of two vectors in three dimensions is given by:\[\vec{u} \times \vec{v} = \langle u_2v_3 - u_3v_2, u_3v_1 - u_1v_3, u_1v_2 - u_2v_1 \rangle\]Applying this formula to \(\vec{u} = \langle 1,-2,1 \rangle\) and \(\vec{v} = \langle -2,4,-2 \rangle\), we calculate each component:- First component: \((-2)(-2) - (1)(4) = 4 - 4 = 0\)- Second component: \((1)(-2) - (1)(-2) = -2 + 2 = 0\)- Third component: \((1)(4) - (-2)(-2) = 4 - 4 = 0\)The cross product is \(\langle 0, 0, 0 \rangle\).
02
Check for Zero Cross Product
The cross product of \(\vec{u}\) and \(\vec{v}\) is \(\langle 0, 0, 0 \rangle\), which is a zero vector. This implies that \(\vec{u}\) and \(\vec{v}\) are parallel or one is a scalar multiple of the other. In such a case, we cannot find a unit vector orthogonal to both \(\vec{u}\) and \(\vec{v}\).
03
State Conclusion
Since the cross product is the zero vector, there is no unit vector orthogonal to both \(\vec{u}\) and \(\vec{v}\), as they are parallel or linearly dependent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is a fundamental operation in vector calculus that allows us to find a vector that is orthogonal (or perpendicular) to two given vectors. It is only applicable in three-dimensional space and is denoted by the symbol \(\times\). The cross product of two vectors \(\vec{a}\) and \(\vec{b}\) is written as \(\vec{a} \times \vec{b}\). To compute this, you use the determinant of a matrix formed by the unit vectors \(\hat{i}, \hat{j}, \hat{k}\) and the components of the vectors \(\vec{a}\) and \(\vec{b}\).
- First Component: \(a_2b_3 - a_3b_2\)
- Second Component: \(a_3b_1 - a_1b_3\)
- Third Component: \(a_1b_2 - a_2b_1\)
Orthogonal Vectors
Orthogonal vectors are vectors that meet at a right angle, or 90 degrees. This means that they have a dot product of zero. The dot product is another vector operation that provides a scalar and is calculated as \(\vec{a} \cdot \vec{b} = a_1b_1 + a_2b_2 + a_3b_3\).
When the dot product equals zero, it signifies orthogonality. The significance of finding a vector orthogonal to two known vectors lies in applications such as finding a normal to a plane, which can be invaluable in fields of physics and engineering.
When the dot product equals zero, it signifies orthogonality. The significance of finding a vector orthogonal to two known vectors lies in applications such as finding a normal to a plane, which can be invaluable in fields of physics and engineering.
- Orthogonality implies perpendicular direction.
- The cross product of any two vectors is an attempt to find a vector orthogonal to both.
- If the cross product is zero, no unique orthogonal vector exists.
Unit Vector
A unit vector is a vector with a magnitude of one. It serves to indicate direction without affecting magnitude. To convert any vector into a unit vector, you divide the vector by its magnitude. Given a vector \(\vec{a} = \langle a_1, a_2, a_3 \rangle\), the unit vector \(\hat{a}\) is calculated as follows:\[ \hat{a} = \frac{\vec{a}}{\| \vec{a} \|} \]Where \(\| \vec{a} \|\) represents the magnitude of the vector, computed by:\[ \| \vec{a} \| = \sqrt{a_1^2 + a_2^2 + a_3^2} \]Unit vectors are essential in mathematics and physics because they provide standard directions for referencing, while maintaining unit length.
- Used extensively in calculations and transformations.
- Coordinates direction without scaling the original vector.
- Facilitates understanding of vector fields and changes in vector functions.