Chapter 5: Problem 38
\(\int \frac{\sin 2 t}{1-\cos 2 t} d t=\) (A) \(\frac{2}{(1-\cos 2 t)^{2}}+C\) (B) \(-\ln |1-\cos 2 t|+C\) (C) \(\frac{1}{2} \ln |1-\cos 2 t|+C\) (D) \(2 \ln |1-\cos 2 t|+C\)
Short Answer
Expert verified
(B) \(-\ln |1 - \cos 2 t| + C\).
Step by step solution
01
Simplify the Integrand
The integrand is \( \frac{\sin 2t}{1 - \cos 2t} \). Using trigonometric identities, we know that \( \sin 2t = 2\sin t \cos t \) and \( \cos 2t = 1 - 2\sin^2 t \). Therefore, \( 1 - \cos 2t = 2\sin^2 t \). Substituting these, we get \( \frac{\sin 2t}{1 - \cos 2t} = \frac{2\sin t \cos t}{2\sin^2 t} = \frac{\cos t}{\sin t} = \cot t \).
02
Integral of cotangent
The integral \( \int \cot t \, dt\) is equal to \( \ln |\sin t| + C \). This uses the standard integral \( \int \cot u \, du = \ln |\sin u| + C \).
03
Substitute back using double angle identity
Since \( t \) is replaced by \( 2t \), change the variable back. Let us note that \( \sin 2t = 1 - \cos 2t \) and thus the substitution \( u = \sin 2t \) gives \( |\sin t| = |1 - \cos 2t| \). So \( \ln |\sin t| + C \) becomes \( \ln |1 - \cos 2t| + C \).
04
Check the options
The negative sign must be considered: From differentiation, we know that the derivative of the integral must be the original integrand. Therefore, the correct option must account for this step. The correct form is \(-\ln|1 - \cos 2t| + C \).
05
Final Answer
After comparing with the provided options, the integral \( \int \frac{\sin 2t}{1 - \cos 2t} \, dt \) corresponds to choice (B): \(-\ln |1 - \cos 2t| + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration Techniques
Integral calculus often involves finding the antiderivative or integral of a function. To solve complex integrals, we use **integration techniques**. These methods help simplify the integrand or change the variable to make integration more manageable.
**Common Integration Techniques Include**:
**Common Integration Techniques Include**:
- Substitution Method: Used when the integrand is a composite function. It simplifies the integral by changing the variable.
- Integration by Parts: Useful when the integrand is a product of two functions.
- Partial Fraction Decomposition: Breaks down rational functions into simpler fractions that are easier to integrate.
Trigonometric Identities
**Trigonometric identities** are relationships involving trigonometric functions that hold true for all values of the involved variables. They are immensely powerful in calculus for simplifying expressions.
For the integrand \( \frac{\sin 2t}{1-\cos 2t} \), the following identities were crucial:
For the integrand \( \frac{\sin 2t}{1-\cos 2t} \), the following identities were crucial:
- Double Angle Formulas: \( \sin 2t = 2 \sin t \cos t \) and \( \cos 2t = 1 - 2\sin^2 t \)
- Pythagorean Identities: Expresses squares of trigonometric functions in terms of each other.
Integral of Trigonometric Functions
Calculating the **integral of trigonometric functions** is a common task in calculus. Each basic trigonometric function has a standard integral. For cotangent, it is crucial to know the integral:The integral \( \int \cot t \, dt \) is equal to \( \ln |\sin t| + C \).
Here's the thought process:- Recognize the function form: In our case, the simplified integrand is \( \cot t \).- Recall the standard integral for \( \cot \), which is \( \ln |\sin t| + C \).**After Integrating the Simplified Expression:**When solving the integral, remember to re-substitute any variable changes made during the simplification phase. We switched from \( \sin t \) back to the variable related to original expression, \( 1-\cos 2t \), resulting in \( \ln |1-\cos 2t| + C \). To match the provided answer options, the formula was adjusted to \(-\ln |1-\cos 2t| + C \). This highlights the integral's sensitivity to sign, especially when verifying results with given choices.
Here's the thought process:- Recognize the function form: In our case, the simplified integrand is \( \cot t \).- Recall the standard integral for \( \cot \), which is \( \ln |\sin t| + C \).**After Integrating the Simplified Expression:**When solving the integral, remember to re-substitute any variable changes made during the simplification phase. We switched from \( \sin t \) back to the variable related to original expression, \( 1-\cos 2t \), resulting in \( \ln |1-\cos 2t| + C \). To match the provided answer options, the formula was adjusted to \(-\ln |1-\cos 2t| + C \). This highlights the integral's sensitivity to sign, especially when verifying results with given choices.