Chapter 4: Problem 28
\(\mathbf{R}=\left\langle 3 \cos \frac{\pi}{3} t, 2 \sin \frac{\pi}{3} t\right\rangle\) is the (position) vector \(\langle x, y\rangle\) from the origin to a moving point \(P(x, y)\) at time \(t\). When \(t=3,\) the speed of the particle is (A) \(\frac{2 \pi}{3}\) (B) 2 (C) 3 (D) \(\frac{\sqrt{13}}{3} \pi\)
Short Answer
Step by step solution
Understand the Problem
Differentiate to Find Velocity
Evaluate Velocity at t=3
Calculate Speed
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Position Vector
- a couple of values, which indicates the coordinates of point at time
Velocity Vector
- The derivative of gives us the velocity in the x-direction.
- Similarly, differentiating offers the velocity in the y-direction.
Differentiation
- The derivative of the x-component, involves applying the chain rule, due to the multiplication of a constant with a trigonometric function.
- The same principle is applied to the y-component, ensuring all parts are correctly differentiated.
Trigonometric Functions
- They determine how far and in what direction a point moves from the origin at a given time.
- Understanding their derivatives is crucial in the context of velocity computation. For example, the derivative of is
- Similarly, the derivative of is crucial for finding the velocity vector.