Chapter 16: Problem 11
Find the equation of the right circular cylinder of radius 1 with axis as \(\frac{x-1}{2}=\frac{y}{3}=\frac{z-3}{1}\)
Short Answer
Expert verified
Based on the information given and the step by step solution, the equation of the right circular cylinder of radius 1 with axis as \(\frac{x-1}{2}=\frac{y}{3}=\frac{z-3}{1}\) is:
\(|(3y - 9)(y - 3)|^2 + (x - 2)^2 = 1\).
Step by step solution
01
Convert the symmetric equation to the parametric form
The symmetric equation of the axis is given by:
\(\frac{x-1}{2}=\frac{y}{3}=\frac{z-3}{1}\)
Let's introduce a parameter \(t\):
\(x = 1 + 2t\)
\(y = 3t\)
\(z = 3 + t\)
Which gives us the parametric equation of the axis:
\(P(t) = (1 + 2t, 3t, 3 + t)\)
02
Find a point on the axis
Evaluate \(P(t)\) at any value of \(t\) to get a point on the axis. Let's use \(t = 0\):
\(P(0) = (1, 0, 3)\)
So, \((1, 0, 3)\) is a point on the axis.
03
Write the general equation of the cylinder
Let the axis direction be given by the vector \(\vec{d} = (2, 3, 1)\). Let any point on the cylinder be \(Q = (x, y, z)\). The cross product of the vector connecting the points on the axis and the cylinder \(\vec{PQ} = (x - 1, y, z - 3)\) and the axis direction vector \(\vec{d}\) is orthogonal to the axis. So, we have
\(\vec{PQ} \times \vec{d} = \vec{M}\)
\(|(x - 1) - 3(z - 3)|^2 + |-2(x - 1) + (z - 3)|^2 = R^2\)
Now, we compute the cross product and simplify.
Substitute \(R = 1\) and square both sides:
\(|^3y - 9(y - 3)|^2 + |-(x - 1) - 1|^2 = 1\)
\(|(3y - 9)(y - 3)|^2 + (x - 2)^2 = 1\)
This is the equation of the right circular cylinder of radius 1 with axis as \(\frac{x-1}{2}=\frac{y}{3}=\frac{z-3}{1}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Form
The parametric form of an equation is useful because it describes a path or collection of points using parameters. In the given problem, the axis of the cylinder is given in symmetric form as \( \frac{x-1}{2} = \frac{y}{3} = \frac{z-3}{1} \). By introducing a parameter \( t \), we can express each variable in terms of \( t \):
- \( x = 1 + 2t \)
- \( y = 3t \)
- \( z = 3 + t \)
Cylinder Axis
Understanding the cylinder axis is crucial for defining the properties and equations of a cylinder. The axis of a cylinder is a straight line about which the cylinder is symmetric and is defined by the parametric equation \( P(t) = (1 + 2t, 3t, 3 + t) \). In this geometry problem, the direction of the axis is crucial and is represented by a vector \( \vec{d} = (2,3,1) \). This axis acts as a spine,
- Defining the orientation of the cylinder.
- Allowing calculations and relationships involving the radius and surface.
- Providing a reference for creating symmetrical parts of the cylinder around it.
Cross Product
The cross product is an essential operation in vector mathematics, allowing us to find a vector orthogonal to two given vectors. When determining the equation for a right circular cylinder, the cross product helps identify vectors perpendicular to the cylinder's axis. Here, we consider the vector connecting the cylinder's surface and a point on the axis, denoted as \( \vec{PQ} = (x - 1, y, z - 3) \).The axis direction vector is \( \vec{d} = (2, 3, 1) \). Using the cross product, \( \vec{PQ} \times \vec{d} \), we find a vector orthogonal to both, which helps correctly express the cylinder's geometry.
- This vector must satisfy certain conditions based on the radius given.
- It encapsulates the cylindrical symmetry and our directional understanding of it.
- Squares of its components are used to frame the cylinder's algebraic equation.
Symmetric Equation
The symmetric equation serves as a starting point for understanding the orientation and direction of lines in three-dimensional space. The given symmetric equation, \( \frac{x-1}{2} = \frac{y}{3} = \frac{z-3}{1} \), offers a concise way to express the condition where multiple variables relate through certain ratios. Its advantage lies in simplicity and clarity, capturing the equality of proportions without extensive arithmetic.
- It allows conversion to parametric equations easily for further calculations.
- The symmetric form is particularly handy for identifying axis directions directly.
- Ratios reflect constant speeds or flows across dimensions.