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Consider the equation $$x y^{\prime}+a(x) y=0$$ where $$a(x)=\sum_{k=0}^{\infty} \alpha_{k} x^{k}$$ and the series converges for \(|x|0\). (a) Show formally that there is a solution \(\phi\) of the form $$\phi(x)=x^{r} \sum_{k=0}^{\infty} c_{k} x^{k}, \quad\left(c_{0}=1\right)$$ where \(r+\alpha_{0}=0\), and \(x>0\). (b) Prove that the series obtained converges for \(|x|

Short Answer

Expert verified
The solution \( \phi(x) \) converges for \( |x| < r_0 \) with \( r = -\alpha_0 \).

Step by step solution

01

Analyze the Given DE

The given differential equation is \( x y^{\prime}+a(x) y=0 \). Here, \( a(x) = \sum_{k=0}^{\infty} \alpha_{k} x^{k} \) and the power series converges within \( |x| < r_{0} \). We aim to find a solution \( \phi(x) = x^{r} \sum_{k=0}^{\infty} c_{k} x^{k} \) such that the series converges.
02

Substitute the Series Solution

Assume \( y = x^{r} \sum_{k=0}^{\infty} c_{k} x^{k} \). Differentiating, \( y' = r x^{r-1} \sum_{k=0}^{\infty} c_{k} x^{k} + x^{r} \sum_{k=0}^{\infty} c_{k} k x^{k-1} \). Substituting these into the DE, \( x (r x^{r-1} \sum_{k=0}^{\infty} c_{k} x^{k} + x^{r} \sum_{k=0}^{\infty} c_{k} k x^{k-1}) + (\sum_{k=0}^{\infty} \alpha_{k} x^{k})(x^{r} \sum_{k=0}^{\infty} c_{k} x^{k}) = 0 \).
03

Simplify and Solve for Coefficients

Rearranging gives \( (r + \alpha_0) c_0 x^r + [(r + k) c_k + \alpha_k c_k] x^{k+r} = 0 \). For this to hold for all \( x \), coefficients must vanish: \( r + \alpha_0 = 0 \) giving \( r = -\alpha_0 \) and for each \( k \), \( (r + k) c_k + \alpha_k c_k = 0 \), solving yields sequence for \( c_k \).
04

Confirm Convergence of the Series

Given \( a(x) \) converges for \( |x| < r_0 \), the weight \( x^r \) does not affect convergence radius since \( r \) is constant. Thus, \( \phi(x) = x^r \sum_{k=0}^{\infty} c_{k} x^{k} \) converges for \( |x| < r_0 \) due to local convergence properties of \( a(x) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Series Solutions
In the realm of Ordinary Differential Equations (ODEs), a power series solution is a method used to find the function that satisfies a given differential equation. A power series is an infinite sum of terms in the form \( a_n x^n \), where each term consists of a coefficient \( a_n \) and a power of \( x \). This method is particularly useful when the equation itself cannot be solved through standard algebraic means.

To illustrate, consider the differential equation \( x y' + a(x) y = 0 \), where \( a(x) = \sum_{k=0}^{\infty} \alpha_k x^k \) is a power series. The solution \( \phi(x) = x^r \sum_{k=0}^{\infty} c_k x^k \) assumes a similar series form. Here, \( r \) and the coefficients \( c_k \) are determined to satisfy the equation.

By differentiating \( y \) and substituting it back into the original equation, one can identify the form or condition for each term. These conditions include equations for \( r \) and recursive relationships for \( c_k \). This structure allows us to resolve more complex ODEs by converting them into solvable sequences.
Convergence of Series
Convergence of a series implies that as more terms are added, the series approaches a specific finite value. It is a critical consideration in power series solutions, ensuring that the derived function \( \phi(x) \) is meaningful and accurate over a particular range of input values.

For the series \( a(x) = \sum_{k=0}^{\infty} \alpha_k x^k \), convergence is guaranteed within the radius \(|x| < r_0\). This means that within this interval, the series sum remains finite and well-defined. In solving the ODE with power series, the convergence of \( a(x) \) sets the stage for the entire solution to remain stable within this domain.

When applied to our solution form \( \phi(x) = x^r \sum_{k=0}^{\infty} c_k x^k \), we note that multiplying by \( x^r \) does not alter the regular convergence radius. Thus, if \( a(x) \) converges, so does \( \phi(x) \). This consistency brings confidence to the validity of the solution across the designated range.
Differential Equation Analysis
Analyzing a differential equation (DE) involves understanding its components and determining how they interact to yield a solution. In our example, the equation \( x y^{\prime} + a(x) y = 0 \) combines both differential terms and series expressions, presenting unique challenges and opportunities.

First, by analyzing the structure of the DE, we can identify the terms that will help form the basis of the power series solution. The substitution of \( y = x^r \sum_{k=0}^{\infty} c_k x^k \) into the DE allows for the expression to be rewritten and simplified, highlighting which coefficients affect the outcomes. Terms involving \( r \) are thus isolated, allowing us to solve for \( r \) in terms of \( \alpha_0 \), i.e., \( r = -\alpha_0 \).

Further simplification guides how the coefficients \( c_k \) relate, often leading to recursive formulas that can readily be solved for succeeding terms. This analysis transforms the seemingly complex DE into a step-by-step computational task, productive for finding meaningful solutions.

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Most popular questions from this chapter

Suppose the constants \(a, b\) in the Euler equation $$ x^{2} y^{\prime \prime}+a x y^{\prime}+b y=0 $$ are real. Let \(r_{1}, r_{2}\) denote the roots of the indicial polynomial \(q\). (a) If \(r_{1}=\sigma+i \tau\) with \(\tau \neq 0\). show that \(r_{2}=\bar{r}_{1}=\sigma-i \tau\). (b) If \(r_{1}=\sigma+i \tau\) with \(\tau \neq 0\), show that the functions \(\psi_{1}, \psi_{2}\) given by $$ \begin{aligned} \psi_{1}(x) &=|x|^{\sigma} \cos (\tau \log |x|) \\ \psi_{2}(x) &=|x|^{\sigma} \sin (\tau \log |x|) \end{aligned} $$ form a basis for the solutions of the Euler equation on any interval not containing \(x=0\).

The equation $$ x y^{\prime \prime}+(1-x) y^{\prime}+\alpha y=0 $$ where \(a\) is a constant, is called the Laguerre equation. (a) Show that this equation has a regular singular point at \(x=0\). (b) Compute the indicial polynomial and its roots. (c) Find a solution \(\phi\) of the form $$ \phi(x)=x^{r} \sum_{k=0}^{\infty} c_{k} x^{k} $$ (d) Show that if \(\alpha=n\), a non-negative integer, there is a polynomial solution of degree \(n\).

Define \(1 / \Gamma(k)\), when \(k\) is a non-positive integer, to be zero. Show that if \(n\) is a positive integer the formula for \(J_{-n}(x)\) gives $$ J_{-n}(x)=(-1)^{n} J_{n}(x) $$

If \(\lambda>0\) is such that \(J_{0}(\lambda)=0\), prove that \(J_{0}^{\prime}(\lambda) \neq 0\). (Hint: If \(J_{0}(\lambda)=J_{0}^{\prime}(\lambda)=0\) the uniqueness theorem would imply \(J_{0}(x)=0\) for \(x>0 .\) Alternately, use Ex. 5.) (Remark: The result of this exercise can be used to show that the positive zeros of \(J_{0}\) are denumerable, that is, they may be put into a one-to-one correspondence with the positive integers.)

(a) Find a solution \(\phi\) of the form $$ \phi(x)=|x-1| r \sum_{k=0}^{\infty} c_{k}(x-1)^{k} $$ for the Legendre equation $$ \left(1-x^{2}\right) y^{\prime \prime}-2 x y^{\prime}+\alpha(\alpha+1) y=0 . $$ For what values of \(x\) does the series converge? (Hint. Do not divide by \(x+1\) and multiply by \(x-1\), but note that \(x=(x-1)+1\). Express the coefficients in terms of powers of \(x\) - 1.) (b) Show that there is a polynomial solution if \(\alpha\) is a non-negative integer.

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