Chapter 0: Problem 7
Prove that $$ \left|z_{1}+z_{2}\right|^{2}+\left|z_{1}-z_{2}\right|^{2}=2\left|z_{1}\right|^{2}+2\left|z_{2}\right|^{2} $$
Short Answer
Expert verified
The identity is proven using property of complex numbers: \( 2|z_1|^2 + 2|z_2|^2 \).
Step by step solution
01
Understand the expression
We are given the expression \( \left|z_1+z_2\right|^2 + \left|z_1-z_2\right|^2 = 2\left|z_1\right|^2 + 2\left|z_2\right|^2 \). Here, \( z_1 \) and \( z_2 \) are complex numbers. Recall that the modulus of a complex number \( z \) is given by \( |z|^2 = z \cdot \overline{z} \), where \( \overline{z} \) is the complex conjugate of \( z \).
02
Expand terms using complex conjugates
Expand \( |z_1 + z_2|^2 = (z_1 + z_2)(\overline{z_1 + z_2}) \) and \( |z_1 - z_2|^2 = (z_1 - z_2)(\overline{z_1 - z_2}) \).
03
Substitute expansions into the original equation
Using the expansions: \( |z_1 + z_2|^2 = z_1\overline{z_1} + z_1\overline{z_2} + z_2\overline{z_1} + z_2\overline{z_2} \) and \( |z_1 - z_2|^2 = z_1\overline{z_1} - z_1\overline{z_2} - z_2\overline{z_1} + z_2\overline{z_2} \). Substitute these into the equation: \[ |z_1 + z_2|^2 + |z_1 - z_2|^2 = (z_1\overline{z_1} + z_1\overline{z_2} + z_2\overline{z_1} + z_2\overline{z_2}) + (z_1\overline{z_1} - z_1\overline{z_2} - z_2\overline{z_1} + z_2\overline{z_2}) \].
04
Simplify the expression
Combine like terms from the expansion: \( 2z_1\overline{z_1} + 2z_2\overline{z_2} \). Thus, the expanded expression becomes \( 2|z_1|^2 + 2|z_2|^2 \). This simplifies directly to the right-hand side of the original equation.
05
Verify the identity
Check if the final expression \( 2|z_1|^2 + 2|z_2|^2 \) equals the right-hand side of the equation \( 2|z_1|^2 + 2|z_2|^2 \). The identity holds true, confirming the original statement.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Modulus of Complex Numbers
The modulus of a complex number is a measure of its magnitude, similar to the distance of a point from the origin in a coordinate system. For a complex number represented as \( z = a + bi \), where \( a \) is the real part and \( b \) is the imaginary part, the modulus is calculated as \( |z| = \sqrt{a^2 + b^2} \).
When squared, this becomes \( |z|^2 = a^2 + b^2 \), eliminating the square root.
This is akin to using the Pythagorean theorem to find the hypotenuse of a right-angled triangle formed on the complex plane, where the real part \( a \) is one side and the imaginary part \( b \) is the other.
In the exercise, the expression \( |z_1 + z_2|^2 \) expands by distributing, ultimately linking back to properties of the modulus in simplifying the equation.
When squared, this becomes \( |z|^2 = a^2 + b^2 \), eliminating the square root.
This is akin to using the Pythagorean theorem to find the hypotenuse of a right-angled triangle formed on the complex plane, where the real part \( a \) is one side and the imaginary part \( b \) is the other.
In the exercise, the expression \( |z_1 + z_2|^2 \) expands by distributing, ultimately linking back to properties of the modulus in simplifying the equation.
- The modulus is crucial in complex numbers as it helps compare their sizes and magnitudes.
- It reappears whenever we manipulate complex expressions algebraically.
Complex Conjugates
Complex conjugates are pairs of complex numbers that are reflected over the real axis of the complex plane. Given a complex number \( z = a + bi \), its conjugate is \( \overline{z} = a - bi \).
When you multiply a complex number by its conjugate, the resulting product is a real number. Specifically, \( z \cdot \overline{z} = (a + bi) \cdot (a - bi) = a^2 + b^2 \), which is precisely \( |z|^2 \) – the square of the modulus.
This property is used for simplifying expressions and solving problems involving complex numbers, such as division.
When you multiply a complex number by its conjugate, the resulting product is a real number. Specifically, \( z \cdot \overline{z} = (a + bi) \cdot (a - bi) = a^2 + b^2 \), which is precisely \( |z|^2 \) – the square of the modulus.
This property is used for simplifying expressions and solving problems involving complex numbers, such as division.
- Multiplying by the conjugate helps eliminate the imaginary component, providing straightforward calculations.
- It's particularly powerful in deriving modulus expressions and conducting algebraic simplifications.
Algebraic Identities
Algebraic identities in complex numbers involve using known mathematical principles to simplify expressions, making them useful for problem-solving. Common identities like the difference of squares \( a^2 - b^2 = (a + b)(a - b) \) can be applied in the realm of complex numbers.
For instance, expanding an expression such as \( (z_1 + z_2)(\overline{z_1 + z_2}) \) uses distributive principles to reach results relatable to symmetric expressions on the complex plane.
For instance, expanding an expression such as \( (z_1 + z_2)(\overline{z_1 + z_2}) \) uses distributive principles to reach results relatable to symmetric expressions on the complex plane.
- These identities are constants in mathematics, offering shortcuts to verifying equations or confirming complex properties.
- They help simplify expanded forms into recognizable structures, recognizable through the eyes of someone practiced in seeing identities within numbers.