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Suppose \(H_{0}: p=0.75\) is to be tested against \(H_{1}: p<\) \(0.75\) using a random sample of size \(n=7\) and the decision rule "Reject \(H_{0}\) if \(k \leq 3\)." (a) What is the test's level of significance? (b) Graph the probability that \(H_{0}\) will be rejected as a function of \(p\).

Short Answer

Expert verified
The level of significance is found by computing the binomial probability when \(k \leq 3\) and \(p = 0.75\). The graph of the probability of rejecting \(H_{0}\) against \(p\) is obtained by computing the binomial probability for every \(p\) ranging from 0 to 1 and charting these probabilities.

Step by step solution

01

Find the Level of Significance

The level of significance for this test, also known as the p-value, can be calculated by computing the probability of observing \(k \leq 3\) when \(p = 0.75\). This is a binomial probability problem, and the formula to find the probability is \(P(k \leq 3) = \sum_{i = 0}^{3} \binom{7}{i} (0.75)^i (1-0.75)^{7-i}\). Calculate this sum to obtain the level of significance.
02

Graph the Probability of Rejection

Now for different values of \(p\) ranging from 0 to 1, calculate the probability of rejecting \(H_{0}\), which is the probability \(P(k \leq 3)\). This again is a binomial probability problem and the formula to use is \(P(k \leq 3) = \sum_{i = 0}^{3} \binom{7}{i} p^i (1-p)^{7-i}\). Calculate this for each \(p\) value and plot these probabilities against \(p\) values on a graph. This will give a visual representation of the rejection region for this test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Level of Significance
Understanding the level of significance is crucial in hypothesis testing. It represents the threshold at which we decide whether to accept or reject the null hypothesis, denoted as \(H_0\). This threshold is the probability of rejecting the null hypothesis when it is actually true, also referred to as the Type I error rate. In simpler terms, it's the likelihood of a 'false alarm'.

During hypothesis testing, you start with an assumption (the null hypothesis) and then determine the chances of obtaining a sample result at least as extreme as the one observed, assuming the null hypothesis is true. If this calculated probability, known as the p-value, is less than the predetermined level of significance, you would reject the null hypothesis in favor of the alternative hypothesis \(H_1\).

For the given exercise, the level of significance is identified by calculating the probability of obtaining a result \(k \leq 3\) when the true proportion \(p\) is 0.75, according to the binomial distribution. The sum of probabilities for \(k\) from 0 to 3 when \(n=7\) and \(p=0.75\) is computed, thus determining the level at which \(H_0\) would be incorrectly rejected.
Probability Function
The probability function is a mathematical tool that gives us the probability that a random variable will take on a specific value or set of values. In the context of hypothesis testing and particularly with discrete distributions, such as the binomial distribution, the probability function specifies the chances of seeing a certain number of successes in a fixed number of trials.

To build this concept further, let's consider a simple coin toss example. If we toss a coin twice, the probability of getting heads both times, assuming the coin is fair, is determined by the probability function related to the binomial distribution. This function requires two parameters: the total number of trials (in this case, 2 coin tosses), and the probability of success on each trial (for a fair coin, this is 0.5 for getting heads).

The formula for the probability mass function (PMF) of binomial distribution is given as \(P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\), where n is the number of trials, k is the number of successes (heads, for example), p is the success probability for each trial, and \((1-p)\) is the probability of failure. The PMF tells us the likelihood of obtaining k successes in n trials.
Binomial Distribution
The binomial distribution is one of the most important discrete probability distributions. It models the number of successful outcomes in a fixed number of independent trials, with two possible outcomes: success or failure. This distribution is defined by two parameters: the number of trials \(n\), and the probability of success \(p\) in each trial.

In our exercise scenario, we are dealing with seven independent trials \(n=7\), with the test hypothesis stating a success probability of 0.75. The binomial distribution provides the framework to calculate the probability of observing a certain number of successes \(k\), which in this case refers to observations that are less than or equal to 3.

Applying the binomial probability formula \(P(k) = \binom{n}{k} p^k (1-p)^{n-k}\), we can calculate the probabilities required for both determining the level of significance and for graphing the probability of rejection as a function of \(p\). The versatility of the binomial distribution in hypothesis testing lies in its capacity to adjust to different scenarios by varying its parameters \(n\) and \(p\), thus tailoring to the specifics of each test.

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Most popular questions from this chapter

Let \(y_{1}, y_{2}, \ldots, y_{n}\) be a random sample from a normal pdf with unknown mean \(\mu\) and variance \(1 .\) Find the form of the GLRT for \(H_{0}: \mu=\mu_{0}\) versus \(H_{1}: \mu \neq \mu_{0}\).

An urn contains ten chips. An unknown number of the chips are white; the others are red. We wish to test \(H_{0}\) : exactly half the chips are white versus \(H_{1}\) : more than half the chips are white We will draw, without replacement, three chips and reject \(H_{0}\) if two or more are white. Find \(\alpha\). Also, find \(\beta\) when the urn is (a) \(60 \%\) white and (b) \(70 \%\) white.

As a class research project, Rosaura wants to see whether the stress of final exams elevates the blood pressures of freshmen women. When they are not under any untoward duress, healthy eighteen-year-old women have systolic blood pressures that average \(120 \mathrm{~mm} \mathrm{Hg}\) with a standard deviation of \(12 \mathrm{~mm} \mathrm{Hg}\). If Rosaura finds that the average blood pressure for the fifty women in Statistics 101 on the day of the final exam is \(125.2\), what should she conclude? Set up and test an appropriate hypothesis.

Suppose that one observation from the exponential pdf, \(f_{Y}(y)=h e^{-\lambda y}, y>0\), is to be used to test \(H_{0}: \lambda=1\) versus \(H_{1}: \lambda<1\). The decision rule calls for the null hypothesis to be rejected if \(y \geq \ln 10\). Find \(\beta\) as a function of \(\lambda\).

If \(H_{0}: \mu=\mu_{0}\) is rejected in favor of \(H_{1}: \mu>\mu_{0}\), will it necessarily be rejected in favor of \(H_{1}: \mu \neq \mu_{0}\) ? Assume that \(\alpha\) remains the same.

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