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91Ó°ÊÓ

What must be true of events \(A\) and \(B\) if (a) \(A \cup B=B\) (b) \(A \cap B=A\)

Short Answer

Expert verified
For (a), A must be a subset of B (this means B contains all elements of A) and for (b), A must again be a subset of B (also means B includes every element of A).

Step by step solution

01

Interpretation of \(A \cup B=B\)

The statement \(A \cup B=B\) implies that every element that is in either A or B, or in both, is included in B. This means that B contains all of A's elements. So, A must be a subset of B.
02

Interpretation of \(A \cap B=A\)

The statement \(A \cap B=A\) implies the intersection of A and B is A, which represents all the elements that A and B have in common. This means that all elements of A are also in B. Therefore, A must be a subset of B in this case as well.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Subset and Superset Relationships
At the heart of set theory lies the concept of subset and superset relationships. When we say 'subset,' we are referring to a set whose elements are all contained within another set. Imagine a bag of red marbles within a larger bag of various colored marbles; the red marbles form a subset of the larger marble collection.

Formally, if every element in set A is also in set B, we say that A is a subset of B, and write it as \( A \subseteq B \). For example, if set A is {1, 2} and B is {1, 2, 3, 4}, A is a subset of B because all elements of A are in B.

A superset, on the other hand, is the larger set that contains all elements of its subsets. Continuing with our previous example, set B is a superset of set A, because it contains all elements of A and possibly more. We can denote this relationship as \( B \supseteq A \).

A couple of key points to keep in mind are:
  • If set A is a subset of B and B is a subset of A, then A and B are actually the same set, known as 'equal sets'.
  • Every set is a subset of itself, which means \( A \subseteq A \)
Union of Sets
The union of two sets is a fundamental operation that combines all the elements from both sets, without duplication. In our analogy, if you have one bag of red marbles and another of blue, then the union of these two bags will give you a mixed bag of red and blue marbles.

The union is symbolically represented by the cup symbol \( \cup \), and mathematically, it's defined as \( A \cup B = \{ x : x \in A \text{ or } x \in B \} \). This definition may sound complex, but it simply means that the union set consists of all elements that are in A, in B, or in both A and B.

For instance, if set A is {1, 2, 3} and set B is {3, 4, 5}, then the union \( A \cup B \) is the set {1, 2, 3, 4, 5}. Notice that '3' is not listed twice, because in set theory, we do not consider repetitions.

The union operation is associative and commutative, which means that the order in which sets are united doesn't change the result \( ((A \cup B) \cup C = A \cup (B \cup C)) \) and \( A \cup B = B \cup A \).
Intersection of Sets
The intersection of sets refers to a new set made up of the common elements that the sets share. This is like finding all the people who appear on both the guest lists of two separate parties.

For the intersection, we use the cap symbol \( \cap \), and it's defined as \( A \cap B = \{ x : x \in A \text{ and } x \in B \} \). The elements of \( A \cap B \) must be in both A and B.

If we stick with our example sets A = {1, 2, 3} and B = {3, 4, 5}, their intersection \( A \cap B \) is the set {3} since that is the only element they have in common. An important note is that if two sets have no elements in common, their intersection is an empty set, denoted by \( \emptyset \).

Just as with the union operation, the intersection is commutative and associative, meaning \( A \cap B = B \cap A \) and \( (A \cap B) \cap C = A \cap (B \cap C) \).

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