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Three dice are tossed, one red, one blue, and one green. What outcomes make up the event \(A\) that the sum of the three faces showing equals 5 ?

Short Answer

Expert verified
The event A that the sum of the three faces showing equals 5 when three dice (one red, one blue, one green) are tossed is constituted by the combinations (1,1,3), (1, 3, 1), (3, 1, 1), (1, 2, 2), (2, 1, 2), and (2, 2, 1).

Step by step solution

01

Identify possible outcomes

First, identify all the possible outcomes of rolling three dice. All dice are independent of each other meaning that the outcome of one does not affect the others. For each dice, since there are 6 faces, the total number of possible outcomes will be \(6 * 6 * 6 = 216\).
02

Determine combinations that sum to 5

Next, identify the combinations of outcomes that sum to 5. This involves considering all combinations of three numbers between 1 and 6 that result in a total sum of 5. These include: (1, 1, 3), (1, 3, 1), (3, 1, 1), (1, 2, 2), (2, 1, 2), (2, 2, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), and so on. When taking order into account, there are total of 6 combinations.
03

Identifying the event A

Now we have all the outcomes which make up the event \(A\) that the sum of the three faces showing equals 5. The combinations from the previous step are all the possible outcomes that could make up this event. So, Event A is made up of (1,1,3), (1, 3, 1), (3, 1, 1), (1, 2, 2), (2, 1, 2), and (2, 2, 1).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sum of Dice Outcomes
When rolling dice, a common task is to determine the probability of rolling a certain sum. In the context of our exercise, the sum we're interested in is 5. With three dice, there are limited ways to roll a sum of 5, as the faces of each die range from 1 to 6.

To visualize this, imagine each die as an independent opportunity to contribute towards the sum. The smallest sum occurs when all dice show a 1, totaling 3, and the largest when they all show 6, totaling 18. Hence, achieving exactly 5 requires specific and limited combinations of these numbers. Determining all combinations can be methodical: begin with the smallest value on one die and iterate through possible values on the others that would complete the sum.

For instance, if one die shows a 1, the remaining two must total 4. This can be achieved only by having both roll a 2, or one rolling a 3 and the other a 1. Such systematic listing ensures all possibilities are accounted for. In realizing this and calculating probabilities, it's important to understand the role of combinatory analysis which we will discuss in the next section.
Combinatorics of Dice Rolls
Combinatorics involves the study of counting, arrangements, and combinations, which is fundamental when analyzing dice rolls. Specifically, it helps us understand the different ways dice can land and how these ways contribute to the probability of an event. In our exercise, we are examining combinations of dice that sum to 5.

For a more structured approach, we use combinatorial principles. When three dice are rolled, the variety of outcomes is assessed by considering the multiple ways each individual die's result can tie into the sum. Importantly, the order in which the dice are rolled applies to the count, because each die is distinguishable by its color. So, the roll (1, 2, 2) is different from (2, 1, 2) even though both contribute to the same sum.

To calculate the total number of outcomes, we employ a multiplication rule: the number of outcomes for each die multiplied together. With each die having 6 sides, we arrive at a total of 216 possible outcomes. From there, the six outcomes that sum to 5 are discerned and counted for event A. It's crucial to grasp that although we have 216 total outcomes, only a select few achieve our target sum, highlighting the selective nature of combinatorial analysis.
Independent Events in Probability
Probability often deals with the concept of independent events, which is key to understanding dice rolls. Two events are independent if the occurrence of one does not affect the occurrence of the other. In the case of rolling a red, blue, and green die, each roll is an independent event. The red die landing on a certain number has no impact on the blue or green die's outcome.

This independence is essential when calculating probabilities when dealing with multiple dice. Since the outcome of each die does not affect the others, their probabilities remain constant. For any single die, there is always a 1 in 6 chance of rolling a specific number. However, when looking for specific sums, we must consider how these independent probabilities work together. Each combination of numbers leading to the sum of 5 is an intersection of three independent events – occurring for each die's roll. To find the likelihood of Event A—the sum equalling 5—we count the successful outcomes (six combinations in our case) and divide by the total number of possible outcomes (216 total combinations).

Grasping this aspect of probability will empower students to tackle a broad range of problems that involve independent events, specifically in games of chance like dice rolling.

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