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In American football a turnover is defined as a fumble or an intercepted pass. The table below gives the number of turnovers committed by the home team in four hundred forty games. Test that these data fit a Poisson distribution at the \(0.05\) level of significance. $$ \begin{array}{cc} \hline & \text { Number } \\ \text { Turnovers } & \begin{array}{c} \text { Observed } \\ \text { O } \end{array} \\ \hline 0 & 75 \\ 1 & 125 \\ 2 & 126 \\ 3 & 60 \\ 4 & 34 \\ 5 & 13 \\ 6+ & 7 \\ \hline \end{array} $$

Short Answer

Expert verified
One needs to calculate the mean (lambda) of the observed data, the expected frequencies using the Poisson formula, then perform a chi-square goodness of fit test at the \(0.05\) significance level. The hypothesis whether the data follows a Poisson distribution is determined based on the comparison of the calculated chi-square value and the chi-square critical value.

Step by step solution

01

Calculate the Mean

First, calculate the mean (lambda) for the observed data. This is done by multiplying each observed frequency by its corresponding turnover and summing these totals. The sum is then divided by the total number of games to find the mean. This value will be the expected value, lambda, for a Poisson distribution.
02

Calculate Expected Frequencies

Next, use the Poisson formula: \(P(x ; \lambda)=\frac{e^{-\lambda} \lambda^{x}}{x !}\) to calculate the expected frequency for each category. For the category '6+,' sum the expected frequencies for 6,7,8,...etc.
03

Conduct a Chi-Square Test

After that, conduct a chi-square goodness of fit test to compare the observed and expected frequencies. This involves calculating the chi-square statistic using the formula: \(\chi^{2}=\Sigma \frac{(O-E)^{2}}{E}\) where 'O' represents the observed frequencies and 'E' stands for expected frequencies. Once the chi-square statistic is calculated, compare it to the critical chi-square value at the \(0.05\) significance level with the degrees of freedom equal to \(n - 1 - p\), where \(n\) is the number of outcomes and \(p\) is the number of parameters estimated from the data (in this case \(p = 1\), as we estimated the mean).
04

Draw the Conclusion

Finally, analyze the calculated chi-square value to the critical chi-square value. If the calculated value is greater than the critical value, then reject the null hypothesis. This means the data does not fit a Poisson distribution. But, if the calculated value is less than the critical value, then do not reject the null hypothesis. This indicates that the data does fit a Poisson distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chi-Square Goodness of Fit Test
The chi-square goodness of fit test is a statistical method used to determine how well observed data fit a specific distribution. It's a type of hypothesis test designed to assess whether the observed frequencies of events differ significantly from what we would expect under a given theoretical distribution.

Here's how this test works step by step: First, we calculate the expected frequencies based on the given distribution. In the case of the Poisson distribution, these would be derived using the Poisson formula. Next, we establish the chi-square statistic by using the formula \(\chi^2 = \Sigma \frac{(O - E)^2}{E}\), where 'O' stands for the observed frequency, and 'E' represents the expected frequency. If this statistic is larger than the critical value from the chi-square distribution for a given level of significance (0.05 in the football turnovers example), and the appropriate degrees of freedom, we reject the null hypothesis indicating that the observed distribution does not fit the expected Poisson distribution. Conversely, if the statistic is lower than the critical value, we cannot reject the null hypothesis and conclude that there is no significant deviation between the observed and the expected values.
Expected Frequencies
Within the context of the chi-square goodness of fit test, the term expected frequencies refers to what we would theoretically anticipate occurring in a dataset if a certain hypothesis about a distribution holds true.

In practical terms, to calculate the expected frequencies for a Poisson distribution, we use the mean (lambda) as a parameter. This mean is calculated from the observed data, typically by summing the product of each outcome with its frequency and dividing by the overall number of observations. After calculating the mean, we plug it into the Poisson formula \(P(x ; \lambda) = \frac{e^{-\lambda} \lambda^{x}}{x!}\) to find the expected frequency for each category. For categories encompassing multiple outcomes, such as '6+' turnovers, we sum up the probabilities for all outcomes within that category (i.e., 6, 7, 8, ...) to get the final expected frequency. These values are crucial, as they are used to calculate the chi-square statistic in the subsequent step of the goodness of fit test.
Hypothesis Testing
At its core, hypothesis testing is a systematic method used in statistics to make decisions about populations based on sample data. It begins with the formulation of two competing hypotheses - the null hypothesis (\(H_0\)) and the alternative hypothesis (\(H_a\)).

The null hypothesis typically proposes that there is no effect or no difference, and the alternative hypothesis suggests the opposite. In our example involving football turnovers, the null hypothesis would be that the observed data follows a Poisson distribution, and the alternative would be that it doesn't.

To test these hypotheses, a test statistic is calculated from the sample data - in this case, the chi-square statistic. The calculated value is compared against a critical value based on the significance level chosen (e.g., 0.05), which acts as a threshold. If the test statistic exceeds the critical value, we reject the null hypothesis, indicating the data does not follow the expected distribution. If it doesn't exceed the critical value, we fail to reject the null hypothesis, suggesting there's no statistical evidence that the data does not follow the expected distribution. It's essential to understand that failing to reject the null hypothesis doesn't prove that it is true, merely that there isn't strong enough evidence to conclude that it is false.

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Most popular questions from this chapter

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