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Players 1 and 2 each choose a positive integer up to \(K\). If the players choose the same number then player 2 pays $$\$ 1$$ to player \(1 ;\) otherwise no payment is made. Each player's preferences are represented by her expected monetary payoff. a. Show that the game has a mixed strategy Nash equilibrium in which each player chooses each positive integer up to \(K\) with probability \(1 / K\). b. (More difficult.) Show that the game has no other mixed strategy Nash equilibria. (Deduce from the fact that player 1 assigns positive probability to some action \(k\) that player 2 must do so; then look at the implied restriction on player 1's equilibrium strategy.)

Short Answer

Expert verified
Each player chooses each number from 1 to K with probability 1/K; no deviations improve payoffs, proving this is the sole mixed strategy equilibrium.

Step by step solution

01

Understand the Payoff Matrix

The payoff matrix is simple. If both players choose the same number, player 2 pays $1 to player 1. Otherwise, no payment is made. We need to understand this in the context of mixed strategies.
02

Define Mixed Strategies

In a mixed strategy Nash equilibrium, each player chooses a strategy with a certain probability. Let player 1 and player 2 choose integers from 1 to K, with each integer chosen with probability 1/K.
03

Calculate Expected Payoff

For each player, the expected payoff when using a mixed strategy where each number is chosen with equal probability is calculated. The expected payoff for player 1 for any integer k is \[ E(U_1) = \frac{1}{K} \left( \sum_{k=1}^{K} 1 \cdot \frac{1}{K} \right) \]. For the entire strategy, this simplifies to \[ E(U_1) = \frac{1}{K} \]. Similarly, the expected payoff for player 2 for any integer k: \[ E(U_2) = - \frac{1}{K} \left( \sum_{k=1}^{K} 1 \cdot \frac{1}{K} \right) \] simplifies to \[ E(U_2) = -\frac{1}{K} \].
04

Equilibrium Condition

For equilibrium, each player's strategy must be a best response to the other player's strategy. With mixed strategies each chosen with equal probability, neither player can unilaterally change their strategy to improve their expected payoff. Therefore, the strategy profile where each player chooses integers 1 through K with probability 1/K is a mixed strategy Nash equilibrium.
05

Uniqueness of the Equilibrium

To prove no other mixed strategy Nash equilibria exist, assume player 1 assigns a positive probability to some action k. Player 2, in response, must also assign a positive probability to k, otherwise player 1 could improve the payoff by not choosing k. This leads to the restriction that both players must assign equal probability to each action, else a higher probability on any integer could be exploited, leading to a contradiction. Thus, any deviation from equal probability results in a worse outcome for at least one player, confirming no other mixed equilibrium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Payoff Matrix
The concept of a payoff matrix is fundamental in game theory. It visually represents the outcomes for each player depending on the strategies they choose. In this game, if both players select the same number, player 2 pays $1 to player 1. If they choose different numbers, no exchange takes place. This matrix helps in understanding the consequences of each player's choices in different scenarios. Visualizing these outcomes through the matrix is crucial as it simplifies the understanding of payoffs and helps in analyzing the strategies in mixed strategy Nash equilibrium and other equilibrium conditions.
Mixed Strategies
In game theory, a mixed strategy refers to a scenario where players randomize over possible moves rather than sticking to a single pure strategy. Here, each player randomizes their integer choices from 1 to K. Each choice is made with an equal probability of 1/K. Mixed strategies allow for more complex strategic thinking since players must consider not just specific actions but probabilities across all potential actions. This broadens the strategic landscape and requires players to optimize based on expected payouts rather than fixed outcomes.
Expected Payoff
The expected payoff is a crucial concept when dealing with mixed strategies. It represents the average outcome a player can anticipate, given the probabilities of different strategies. For player 1, the expected payoff is calculated as: \ \( E(U_1) = \frac{1}{K} \left( \sum_{k=1}^{K} 1 \cdot \frac{1}{K} \right) \) \ This simplifies to \ \( E(U_1) = \frac{1}{K} \).\ For player 2, the expected payoff becomes: \ \( E(U_2) = -\frac{1}{K} \left( \sum_{k=1}^{K} 1 \cdot \frac{1}{K} \right) \) \ which simplifies to \ \( E(U_2) = -\frac{1}{K} \).\ These calculations show the balance achieved through mixed strategies, where each player’s choice yields an expected payoff that reflects the fairness and balance of the game structure.
Equilibrium Condition
For a strategy to be in Nash equilibrium, it must be the best response to the other player's strategy. For mixed strategy Nash equilibrium, this means no player can improve their expected payoff by changing their strategy unilaterally. In our game, if each player chooses each integer from 1 to K with equal probability 1/K, neither player can alter their strategy to increase their expected payoff. This mutual best response condition ensures that the players' strategies are indeed in equilibrium.
Uniqueness of Equilibrium
The uniqueness of the mixed strategy Nash equilibrium in this game can be shown by examining any deviations. Assume player 1 assigns a positive probability to some action k. Player 2 must also assign a positive probability to k, or player 1 could alter their strategy to improve their payoff by not choosing k. This interplay enforces that both players must assign equal probability to each action. Any deviation from this equal probability would result in a worse expected outcome for at least one player, thus proving that no other mixed strategy Nash equilibria exist beyond the one where each choice is made with probability 1/K.

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Most popular questions from this chapter

(Incompetent experts) Consider a (realistic?) variant of the model, in which the experts are not entirely competent. Assume that each expert always correctly recognizes a major problem but correctly recognizes a minor problem with probability \(s<1:\) with probability \(1-s\) she mistakenly thinks that a minor problem is major, and, if the consumer accepts her advice, performs a major repair and obtains the profit \(\pi\). Maintain the assumption that each consumer believes (correctly) that the probability her problem is major is \(r .\) As before, a consumer who does not give the job of fixing her problem to an expert bears the cost \(E^{\prime}\) if it is major and \(I^{\prime}\) if it is minor. Suppose, for example, that an expert is honest and a consumer rejects advice to obtain a major repair. With probability \(r\) the consumer's problem is major, so that the expert recommends a major repair, which the consumer rejects; the consumer bears the cost \(E^{\prime} .\) With probability \(1-r\) the consumer's problem is minor. In this case with probability s the expert correctly diagnoses it as minor, and the consumer accepts her advice and pays \(I ;\) with probability \(1-s\) the expert diagnoses it as major, and the consumer rejects her advice and bears the cost \(I^{\prime} .\) Thus the consumer's expected payoff in this case is \(-r E^{\prime}-(1-r)\left[s I+(1-s) I^{\prime}\right]\) Construct the payoffs for every pair of actions and find the mixed strategy equilibrium in the case \(E>r E^{\prime}+(1-r) I^{\prime} .\) Does incompetence breed dishonesty? More wary consumers?

(Election campaigns) A new political party, \(A\), is challenging an established party, B. The race involves three localities of different sizes. Party \(A\) can wage a strong campaign in only one locality; \(B\) must commit resources to defend its position in one of the localities, without knowing which locality \(A\) has targeted. If \(A\) targets district \(i\) and \(B\) devotes its resources to some other district then \(A\) gains \(a_{i}\) votes at the expense of \(B\); let \(a_{1}>a_{2}>a_{3}>0 .\) If \(B\) devotes resources to the district that \(A\) targets then \(A\) gains no votes. Each party's preferences are represented by the expected number of votes it gains. (Perhaps seats in a legislature are allocated proportionally to vote shares.) Formulate this situation as a strategic game and find its mixed strategy equilibria. Although games with many players cannot in general be conveniently represented in tables like those we use for two-player games, three-player games can be accommodated. We construct one table for each of player 3 's actions; player 1 chooses a row, player 2 chooses a column, and player 3 chooses a table. The next exercise is an example of such a game.

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