Consider Cournot's game in the case of an arbitrary number \(n\) of firms;
retain the assumptions that the in-verse demand function takes the form (54.2)
and the cost function of each firm \(i\) is \(\mathrm{C}_{i}\left(q_{i}\right)=c
q_{i}\) for all \(q_{i}\), with \(c<\alpha\). Find the best response function of
each firm and set up the conditions for \(\left(q_{1}^{*}, \ldots,
q_{n}^{*}\right)\) to be a Nash equilibrium (see \(\left.(34.3)\right)\),
assuming that there is a Nash equilibrium in which all firms' outputs are
positive. Solve these equations to find the Nash equilibrium. (For \(n=2\) your
answer should be \(\left(\frac{1}{3}(\alpha-c), \frac{1}{3}(\alpha-c)\right)\),
the equilibrium found in the previous section. First show that in an
equilibrium all firms produce the same output, then solve for that output. If
you cannot show that all firms produce the same output, simply assume that
they do.) Find the price at which output is sold in a Nash equilibrium and
show that this price decreases as \(n\) increases, approaching \(c\) as the number
of firms increases without bound.
The main idea behind this result does not depend on the assumptions on the
inverse demand function and the firms' cost functions. Suppose, more
generally, that the inverse demand function is any decreasing function, that
each firm's cost function is the same, denoted by \(C\), and that there is a
single output, say \(q\), at which the average cost of production \(C(q) / q\) is
minimal. In this case, any given total output is produced most efficiently by
each firm's producing \(q\), and the lowest price compatible with the firms' not
making losses is the minimal value of the average cost. The next exercise asks
you to show that in a Nash equilibrium of Cournot's game in which the firms'
total output is large relative to \(q_{\prime}\) this is the price at which the
output is sold.