Chapter 3: Problem 28
Give an example of a set \(A\) in \(\mathbb{R}^{2}\) such that \(\bar{A}=\mathbb{R}^{2}\) and int \(A\) is empty.
Short Answer
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Question: Find a set 饾惔 in 鈩澛 with the given properties: the closure of 饾惔 is equal to 鈩澛 and the interior of 饾惔 is empty.
Answer: The set 饾惔 composed of all the rational points in 鈩澛 satisfies the required properties.
Step by step solution
01
Understanding closure and interior
In this context, the closure of a set 饾惔 refers to the union of 饾惔 and its limit points. In 鈩澛 space, the limit point 饾懃 of 饾惔 is the point such that every open disk centered at 饾懃 contains a point in 饾惔, although 饾懃 may or may not be in 饾惔. The interior of a set 饾惔 is the largest open subset contained in 饾惔.
02
Finding a set 饾惔 in 鈩澛 such that no open disk is entirely contained within it
In order for the interior of 饾惔 to be empty, there must not be any open disks that are entirely contained in 饾惔. 鈩澛 can be represented by coordinate points (饾懃,饾懄) where 饾懃 and 饾懄 are real numbers. We can consider a set 饾惔 composed of all the rational points in 鈩澛, i.e. (饾懃,饾懄) where both 饾懃 and 饾懄 are rational. Since the set of rational numbers is dense in 鈩, there will not be any open disk entirely contained within 饾惔.
03
Verifying that 鈩澛 is the closure of 饾惔
Let's consider a point 饾懃=(饾懃鈧,饾懃鈧) in 鈩澛 with 饾懃鈧 and 饾懃鈧 being real numbers. Since the set of rational numbers is dense in 鈩, we can find sequences of rational numbers 饾憻鈧佲倴 and 饾憻鈧傗倴 such that:
\( r_{1k}\to x_1\), \( r_{2k}\to x_2\)
Now we can form the sequence 饾憛鈧=(饾憻鈧佲倴, 饾憻鈧傗倴) which is a sequence of points in 饾惔. Since 饾憛鈧 converges to 饾懃, 饾懃 is a limit point of 饾惔. Therefore, every point in 鈩澛 is a limit point of 饾惔.
04
Concluding that the given set satisfies the required properties
We have found a set 饾惔 in 鈩澛, such that:
- int 饾惔 is empty because every open disk contains points that are not in 饾惔.
- 饾憥饾渾饾惔 = 鈩澛 since every point in 鈩澛 is either in 饾惔 or a limit point of 饾惔.
So, the set 饾惔, composed of all the rational points in 鈩澛, is an example of a set with the required properties.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Closure of a set
The concept of a closure of a set in mathematics is essential, especially in abstract analysis. When we talk about closure, we mean finding all the points that "touch" a given set \(A\). In formal terms, the closure of a set \(A\) is the smallest closed set that contains \(A\). This includes not only the points in \(A\) itself but also all its limit points.
If you imagine a set as a collection of points scattered around, the closure is the boundary plus all the inside points. Limit points are those that, no matter how close you get, there's always a point of the set nearby.
If you imagine a set as a collection of points scattered around, the closure is the boundary plus all the inside points. Limit points are those that, no matter how close you get, there's always a point of the set nearby.
- The closure of \(A\) is denoted as \(\bar{A}\).
- It is essentially \(A\) along with its limit points.
- Closure covers all the possible convergence points related to the set.
Interior of a set
The interior of a set \(A\) can be a slightly more tricky concept at first, but it's essentially about understanding the 'heart' of a set. Think of it like this: the interior is the largest open space that you can find inside a set.
An open set in this context is one that contains a neighborhood, or tiny "bubble" of points completely within the set, around each of its points. The interior of \(A\) is written as \(\text{int } A\) and is the union of all such 'bubbles' within \(A\).
Thus, the interior of \(A\), which is composed of these rational points, is empty.
An open set in this context is one that contains a neighborhood, or tiny "bubble" of points completely within the set, around each of its points. The interior of \(A\) is written as \(\text{int } A\) and is the union of all such 'bubbles' within \(A\).
- Interior is like a "buffer zone" around points that remain entirely within \(A\).
- If there are no such bubbles, the set has an empty interior.
Thus, the interior of \(A\), which is composed of these rational points, is empty.
Dense sets
Dense sets are fascinating because they appear to "fill" any space, despite perhaps not containing every point. For a set \(A\) to be dense in \(\mathbb{R}^2\), every point in \(\mathbb{R}^2\) must either be in \(A\) or be a limit point of \(A\).
This means that for every spot you pick in \(\mathbb{R}^2\), you can come infinitely close to it with points from \(A\) without actually needing \(\text{A}\) to fill every spot. It's like trying to completely fill a room with only certain specific blocks. You never entirely cover the floor, but you get infinitely close.
So, although the set of all rational points in \(\mathbb{R}^2\) is not the same as \(\mathbb{R}^2\), it is dense in \(\mathbb{R}^2\). This is why its closure is \(\mathbb{R}^2\). As a result, the rational points are scattered so fully across \(\mathbb{R}^2\) that they touch every point.
This means that for every spot you pick in \(\mathbb{R}^2\), you can come infinitely close to it with points from \(A\) without actually needing \(\text{A}\) to fill every spot. It's like trying to completely fill a room with only certain specific blocks. You never entirely cover the floor, but you get infinitely close.
- Dense sets "visit" every point space can hold.
- They often make it possible for many theoretical mathematics applications.
So, although the set of all rational points in \(\mathbb{R}^2\) is not the same as \(\mathbb{R}^2\), it is dense in \(\mathbb{R}^2\). This is why its closure is \(\mathbb{R}^2\). As a result, the rational points are scattered so fully across \(\mathbb{R}^2\) that they touch every point.