Chapter 2: Problem 20
Suppose that the random variable \(X\) is uniformly distributed symmetrically around zero, but in such a way that the parameter is uniform on \((0,1)\); that is, suppose that $$ X \mid A=a \in U(-a, a) \text { with } A \in U(0,1) \text {. } $$ Find the distribution of \(X, E X\), and \(\operatorname{Var} X\).
Short Answer
Step by step solution
Understanding the Scenario
Finding the Distribution of \( X \)
Computing the Marginal Distribution of \( X \)
Finding the Expected Value of \( X \)
Calculating the Variance of \( X \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Uniform Distribution
- The random parameter, \( A \), follows a uniform distribution over \((0, 1)\).
- Given any specific \( a \) from this range, the variable \( X \) is uniformly distributed over \((-a, a)\), meaning it is equally likely to be anywhere within this interval.
This makes \( X \) defined over a constantly shifting interval, depending on \( A \). This two-step definition defines \( X \)'s behavior based on \( A \)'s value, making the analysis a bit more layered.
Expected Value
This stems from symmetry; since the distribution is evenly spread out over \((-a, a)\), all positive outcomes cancel out the negative ones.
For the exercise, the expected value of \( X \) overall is also zero because when \( X \) is evaluated over all possible \( A \), the symmetrical nature persists:
- \( E[X|A = a] = 0 \)
- Thus, \( E[X] = E[E[X|A]] = 0 \)
Variance
To find the overall variance of \( X \), the law of total variance is used:
- \( \operatorname{Var}(X) = E[\operatorname{Var}(X|A)] + \operatorname{Var}(E[X|A]) \)
- \( \operatorname{Var}(E[X|A]) = 0 \)
- \( E[\operatorname{Var}(X|A)] = \int_0^1 \frac{a^2}{3} \, da = \frac{1}{9} \)
Conditional Probability
- This is expressed as \( f_{X|A}(x|a) = \frac{1}{2a} \), showing the probability density function of \( X \) over \((-a, a)\).
- It informs us exactly how \( X \) behaves when a specific \( A \) is known, illustrating the dependency of \( X \) on \( A \).
By integrating these conditional probabilities over all possible values of \( a \), we derived the marginal distribution \( f_X(x) \). This integrates the dependency of \( X \) on \( A \) into a more global understanding, yielding \( f_X(x) = -\ln|x| \) on \((-1, 1)\).
Understanding this conditional structure is key to analyzing complex systems where outcomes depend on underlying factors.