/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Compute the homology groups of t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Compute the homology groups of the following 2-complexes: (a) The quotient of \(S^{2}\) obtained by identifying north and south poles to a point. (b) \(S^{1} \times\left(S^{1} \vee S^{1}\right)\) (c) The space obtained from \(D^{2}\) by first deleting the interiors of two disjoint subdisks in the interior of \(D^{2}\) and then identifying all three resulting boundary circles together via homeomorphisms preserving clockwise oricntations of these circles. (d) The quotient space of \(S^{1} \times S^{1}\) obtained by identifying points in the circle \(S^{1} \times\left\\{x_{0}\right\\}\) that differ by \(2 \pi / m\) rotation and identifying points in the circle \(\left\\{x_{0}\right\\} \times S^{1}\) that differ by \(2 \pi / n\) rotation.

Short Answer

Expert verified
(a) \(H_0 = \mathbb{Z}\), \(H_1 = \mathbb{Z}/2\mathbb{Z}\), \(H_2 = 0\). (b) \(H_0 = \mathbb{Z}\), \(H_1 = \mathbb{Z}^3\), \(H_2 = \mathbb{Z}\). (c) \(H_0 = \mathbb{Z}\), \(H_1 = \mathbb{Z}^3\), \(H_2 = 0\). (d) \(H_0 = \mathbb{Z}\), \(H_1 = \mathbb{Z}^2\), \(H_2 = \mathbb{Z}\).

Step by step solution

01

Understanding the given space (a)

The quotient of \(S^2\) by identifying the north and south poles to a point results in a space known as \(\mathbb{RP}^2\), the real projective plane.
02

Compute homology of \(\mathbb{RP}^2\) (a)

The homology groups of \(\mathbb{RP}^2\) are well-known: - \(H_0(\mathbb{RP}^2) \cong \mathbb{Z}\), - \(H_1(\mathbb{RP}^2) \cong \mathbb{Z}/2\mathbb{Z}\), - \(H_2(\mathbb{RP}^2) = 0\).
03

Understanding the given space (b)

The space \(S^1 \times (S^1 \vee S^1)\) is a 2-dimensional torus with two additional disjoint circles joined at a point, resembling a 'figure-eight' on top of the torus.
04

Compute homology of \(S^1 \times (S^1 \vee S^1)\) (b)

For this space, the homology groups can be computed as: - \(H_0(S^1 \times (S^1 \vee S^1)) \cong \mathbb{Z}\), - \(H_1(S^1 \times (S^1 \vee S^1)) \cong \mathbb{Z}^3\), - \(H_2(S^1 \times (S^1 \vee S^1)) \cong \mathbb{Z}\).
05

Understanding the given space (c)

Start with a disk \(D^2\), remove two interior disks, and then identify the three resulting boundary components together, which topologically results in a 2-sphere with two points identified, giving rise to a space equivalent to the wedge of three circles, \(S^1 \vee S^1 \vee S^1\).
06

Compute homology of \(S^1 \vee S^1 \vee S^1\) (c)

The homology of \(S^1 \vee S^1 \vee S^1\) is:- \(H_0(S^1 \vee S^1 \vee S^1) \cong \mathbb{Z}\), - \(H_1(S^1 \vee S^1 \vee S^1) \cong \mathbb{Z}^3\), - \(H_2(S^1 \vee S^1 \vee S^1) = 0\).
07

Understanding the given space (d)

In this problem, the surface \(T^2 = S^1 \times S^1\) is being identified along its curves similar to turning it into a torus with modified slopes, leading to a torus with a twist at each marked point.
08

Compute homology with rotations (d)

The operation about axes properly retains the torus’s topology, yielding: - \(H_0(T^2) \cong \mathbb{Z}\), - \(H_1(T^2) \cong \mathbb{Z}^2\), - \(H_2(T^2) \cong \mathbb{Z}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Homology Groups
Homology groups are mathematical structures used in algebraic topology to analyze and classify the different types of structures and holes within a topological space. These groups are denoted as \(H_n(X)\), where \(X\) is a topological space and \(n\) represents the dimension. Homology groups give insight into the number and type of "holes" in each dimension.
  • \(H_0(X)\) represents the path-connected components in the space. It gives the number of connected pieces.
  • \(H_1(X)\) describes 1-dimensional "holes", similar to loops or tunnels.
  • \(H_2(X)\) corresponds to 2-dimensional "holes", often visualized like cavities within the space.
For instance, if a surface has three loops, its first homology group, \(H_1\), would represent these loops. Each new homology group corresponds to a different level of complexity, all of which are integral in understanding the topology of any given space.
2-Complexes
A 2-complex is a type of topological space that is built using 2-dimensional polygons, like disks. These spaces can often be used to represent surfaces and are foundational in algebraic topology. They are formulated by connecting edges of these polygons, and they can be analyzed using their homology.
For example, when polygons in a 2-complex are glued together, new shapes and surfaces are formed.
  • These complexes can help visualize and understand complicated surfaces like the torus or the real projective plane.
  • Through their study, one can determine properties like connectedness and the number of holes.
Complexes are surprisingly versatile, giving rise to various kinds of spaces by interpreting how different polygons are put together.
Real Projective Plane
The Real Projective Plane, denoted as \(\mathbb{RP}^2\), is an important geometric surface in algebraic topology. It can initially seem abstract and complex, yet with further exploration, its properties become fascinating.
  • The plane can be visualized as a disk with opposite points on the boundary identified.
  • Another way to imagine \(\mathbb{RP}^2\) is by taking a sphere and identifying opposing points as single points, like joining the north and south poles.
  • Notably, this space is non-orientable, meaning there's no consistent way to differentiate between the 'inside' and 'outside'.
When analyzing its homology groups, \(\mathbb{RP}^2\) has some interesting properties. For instance, \(H_1(\mathbb{RP}^2) \cong \mathbb{Z}/2\mathbb{Z}\), reflecting its non-orientability, and confirming the existence of a single type of twist or loop within the structure.
Torus
The torus is a doughnut-shaped surface that is, in many ways, a classic example in topology due to its simple yet rich structure. It can be represented as \(S^1 \times S^1\), where \(S^1\) is the circle.
  • The torus has both a major and a minor circumference: representing rotations around its center and along its tube.
  • Unlike the real projective plane, the torus is orientable; one can consistently define what is 'inside' and 'outside'.
  • Topologically, the torus is significant because it features multiple holes and loops.
Analyzing its homology groups reveal that, for the torus \(H_1(T^2) \cong \mathbb{Z}^2\), displaying the two fundamental loops through its structure. Additionally, its second homology group, \(H_2(T^2) \cong \mathbb{Z}\), represents a cavity enclosed by the object, underscoring the torus's universal relevance in studies of surface topology.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that \(S^{1} \times S^{1}\) and \(S^{1} \vee S^{1} \vee S^{2}\) have isomorphic homology groups in all dimensions, but their universal covering spaces do not.

Let \(M\) be a closed orientable surface embedded in \(\mathbb{R}^{3}\) in such a way that reflection across a plane \(P\) defines a homeomorphism \(r: M \rightarrow M\) fixing \(M \cap P,\) a collection of circles. Is it possible to homotope \(r\) to have no fixed points?

Show the isomorphism between cellular and singular homology is natural in the following sense: \(A\) map \(f: X \rightarrow Y\) that is cellular \(-\) satisfying \(f\left(X^{n}\right) \subset Y^{n}\) for all \(n-\) induces a chain map \(f_{*}\) between the cellular chain complexes of \(X\) and \(Y,\) and the map \(f_{*}: H_{n}^{C W}(X) \rightarrow H_{n}^{C W}(Y)\) induced by this chain map corresponds to \(f_{*}: H_{n}(X) \rightarrow H_{n}(Y)\) under the isomorphism \(H_{n}^{C W} \approx H_{n}\).

(a) Show that a chain complex of free abelian groups \(C_{n}\) splits as a direct sum of subcomplexes \(0 \rightarrow L_{n+1} \rightarrow K_{n} \rightarrow 0\) with at most two nonzero terms. IShow the short exact sequence \(0 \rightarrow \operatorname{Ker} \partial \rightarrow C_{n} \rightarrow \operatorname{Im} \partial \rightarrow 0\) splits and take \(K_{n}=\) Ker \(\partial .\) (b) In case the groups \(C_{n}\) are finitely generated, show there is a further splitting into summands \(0 \rightarrow \mathbb{Z} \rightarrow 0\) and \(0 \rightarrow \mathbb{Z} \stackrel{m}{\longrightarrow} \mathbb{Z} \rightarrow 0\). [Reduce the matrix of the boundary map \(L_{n+1} \rightarrow K_{n}\) to echelon form by elementary row and column operations. (c) Deduce that if \(X\) is a CW complex with finitely many cells in each dimension, then \(H_{n}(X ; G)\) is the direct sum of the following groups: \- a copy of \(G\) for each \(\mathbb{Z}\) summand of \(H_{n}(X)\) \- a copy of \(G / m G\) for each \(\mathbb{Z}_{m}\) summand of \(H_{n}(X)\) \- a copy of the kemel of \(G \stackrel{m}{\longrightarrow} G\) for each \(\mathbb{Z}_{m}\) summand of \(H_{n-1}(X)\)

Show that the second barycentric subdivision of a \(\Delta\) -complex is a simplicial complex. Namely, show that the first barycentric subdivision produces a \(\Delta\) -complex with the property that each simplex has all its vertices distinct, then show that for a \Delta-complex with this property, barycentric subdivision produces a simplicial complex.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.