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Show that a morphism \(f: X \rightarrow Y\) is finite if and only if for erery ' open affine subset \(V=\operatorname{Spec} B\) of \(Y, f^{-1}(V)\) is affine, equal to Spec \(A,\) where \(A\) is a finite \(B\) -module.

Short Answer

Expert verified
The given statement is true. The proof involves an application of the properties of finite morphisms and the properties of the Spec functor, combined with the properties of affine morphisms, and their relationship with modules. The key steps involve showing that, given the conditions, finite morphisms are preserved.

Step by step solution

01

Assume \(f: X \rightarrow Y\) is a finite morphism

For this part, you are needed to take \(f: X \rightarrow Y\) as a finite morphism. Here, \(f\) being finite implies that it is locally of finite type and quasi-compact.
02

Show that \(f^{-1}(V)\) is affine and is equal to Spec \(A\), where \(A\) is a finite \(B\)-module

Given \(V=\operatorname{Spec} B\) is an open affine subset of \(Y\), you need to show \(f^{-1}(V)\) is affine. Furthermore, you also have to show it is equal to Spec \(A\), where \(A\) is a finite \(B\)-module. Here you can use the fact that a scheme \(X\) is affine if and only if the morphism \(X \rightarrow \operatorname{Spec} \mathbb{Z}\) is affine, and a morphism of schemes is affine if and only if it is quasi-compact and quasi-separated, and it preserves the property of being quasi-compact.
03

Show that \(f: X \rightarrow Y\) is a finite morphism using the proof from step 2

After showing that for every open affine subset \(V=\operatorname{Spec} B\) of \(Y\), \(f^{-1}(V)\) is affine and is equal to Spec \(A\), where \(A\) is a finite \(B\)-module, you should bring it all together to argue that given these conditions hold, \(f: X \rightarrow Y\) must be a finite morphism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Affine Scheme
In algebraic geometry, an affine scheme is a fundamental concept that serves as one of the building blocks for more complex geometric structures. It is essentially the spectrum of a ring and provides the link between algebra and geometry. Let's take the example of a ring, say, the ring of polynomials with coefficients in a field.

An affine scheme can be seen as a geometric space equipped with functions. The set of prime ideals of the given ring forms the points of this space, while the elements of the ring correspond to functions on this space. An open subset of an affine scheme is defined by the non-vanishing locus of a function.

When we consider an affine scheme, denoted as \(\text{Spec} A\), we are looking at the set of all prime ideals of the ring \(A\), together with a certain topology known as the Zariski topology, and a sheaf of rings that provides local data. Affine schemes serve as the local models for all schemes, much like open balls in classical topology serve as local models for manifolds.
Spec A
The notation \(\operatorname{Spec} A\) refers to the spectrum of a ring \(A\), and it plays a central role in the definition of an affine scheme. To understand \(\operatorname{Spec} A\), one must grasp what we mean by the spectrum of a ring. This concept forms a bridge between algebraic structures and geometric notions.

The spectrum is the set of all prime ideals of the ring \(A\), and when we give this set a Zariski topology, we create a topological space that can be examined using the tools of algebraic geometry. In this topology, closed sets are defined by the vanishing of sets of functions (elements of the ring), which corresponds to common zeroes of polynomials in the classical algebraic geometry setting. This connection allows us to think of algebraic equations in terms of geometric spaces and vice versa, creating a powerful framework for solving problems in both domains.
Finite B-Module
In the context of rings and modules, a \(B\)-module \(A\) is considered to be finite if \(A\) is generated by a finite number of elements over \(B\). More technically, this means that there exists a surjective \(B\)-module homomorphism from \(B^n\) to \(A\) for some positive integer \(n\), where \(B^n\) denotes the \(n\)-fold direct product of \(B\) with itself.

If \(A\) is a finite \(B\)-module, it carries an inherent algebraic structure that encodes not only the operations within \(A\) but also how those operations are controlled by the elements of \(B\). When dealing with affine schemes and their morphisms, the concept of a finite module becomes particularly important. For example, in the exercise we mentioned earlier, one criterion for a morphism to be finite is that the pre-image of an open affine subset under the morphism is itself affine, and is represented by a finite \(B\)-module, showing a tight algebraic relationship between the two schemes.
Algebraic Geometry
Algebraic geometry is a rich and deep field of mathematics that merges abstract algebra, particularly commutative algebra, with geometry. It studies geometrical structures that can be defined by polynomial equations, such as curves, surfaces, and more generally, varieties and schemes.

In algebraic geometry, geometric concepts like points, curves, and surfaces correspond to algebraic objects like ideals, rings, and fields. This tight correlation opens the door to using algebraic techniques to tackle geometrical problems and vice versa. The foundational concept of a scheme, which generalizes the idea of a variety, enables mathematicians to use the tools of algebraic geometry to study spaces that do not necessarily have a clear geometric intuition.

The field is rich with concepts like dimension, singularities, and morphisms between spaces, which are fundamental to the understanding of the geometry of solutions to algebraic equations. Whether one is dealing with simple conic sections or complex moduli spaces, the principles of algebraic geometry provide a unifying framework for analysis and problem-solving.

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Most popular questions from this chapter

A Complete Nonprojective Variety. Let \(k\) be an algebraically closed field of char \(\neq 2 .\) Let \(C \subseteq \mathbf{P}_{k}^{2}\) be the nodal cubic curve \(y^{2} z=x^{3}+x^{2} z .\) If \(P_{0}=(0,0,1)\) is the singular point, then \(C-P_{0}\) is isomorphic to the multiplicative group \(\mathbf{G}_{m}=\operatorname{Spec} k\left[t, t^{-1}\right](\mathrm{E} \mathrm{x} .6 .7) .\) For each \(a \in k, a \neq 0,\) consider the translation of \(\mathbf{G}_{m}\) given by \(t \mapsto a t .\) This induces an automorphism of \(C\) which we denote by \(\varphi_{a}\) Now consider \(C \times\left(\mathbf{P}^{1}-\\{0\\}\right)\) and \(C \times\left(\mathbf{P}^{1}-\\{\infty\\}\right) .\) We glue their open subsets \(C \times\left(\mathbf{P}^{1}-\\{0, x\\}\right)\) by the isomorphism \(\varphi:\langle P, u\rangle \mapsto\left\langle\varphi_{u}(P), u\right\rangle\) for \(P \in C, u \in \mathbf{G}_{m}=\mathbf{P}^{1}-\\{0, x\\} .\) Thus we obtain a scheme \(X,\) which is our example. The projections to the second factor are compatible with \(\varphi,\) so there is a natural morphism \(\pi: X \rightarrow \mathbf{P}^{1}\) (a) Show that \(\pi\) is a proper morphism, and hence that \(X\) is a complete variety over \(k\) (b) Use the method of \((\text { Ex. } 6.9)\) to show that \(\operatorname{Pic}\left(C \times \mathbf{A}^{1}\right) \cong \mathbf{G}_{m} \times \mathbf{Z}\) and \(\operatorname{Pic}\left(C \times\left(\mathbf{A}^{1}-\\{0\\}\right)\right) \cong \mathbf{G}_{m} \times \mathbf{Z} \times \mathbf{Z}\) [Hint: If \(A\) is a domain and if denotes the group of units, then \(\left.(A[u])^{*} \cong A^{*} \text { and }\left(A\left[u, u^{-1}\right]\right)^{*} \cong A^{*} \times \mathbf{Z} .\right]\) (c) Now show that the restriction map \(\operatorname{Pic}\left(C \times \mathbf{A}^{1}\right) \rightarrow \operatorname{Pic}\left(C \times\left(\mathbf{A}^{1}-\\{0\\}\right)\right)\) is of the form \(\langle t, n\rangle \mapsto\langle t, 0 . n\rangle,\) and that the automorphism \(\varphi\) of \(C \times\left(\mathbf{A}^{1}-\\{0\\}\right)\) induces a map of the form \(\langle t, d, n\rangle \mapsto\langle t, d+n, n\rangle\) on its Picard group. (d) Conclude that the image of the restriction map Pic \(X \rightarrow \operatorname{Pic}(C \times\\{0\\})\) consists entirely of divisors of degree 0 on \(C .\) Hence \(X\) is not projective over \(k\) and \(\pi\) is not a projective morphism.

Shyscraper Sheares. Let \(X\) be a topological space. let \(P\) be a point, and let \(A\) be an abelian group. Define a sheaf \(i_{P}(A)\) on \(X\) as follows: \(i_{p}(A)(\mathcal{L})=A\) if \(P \in L, 0\) otherwise. Verify that the stalk of \(i_{P}(A)\) is \(A\) at every point \(Q \in\left\\{P \text { ; }^{-} \text {, and } 0\right.\) elsewhere, where \(\\{P \text { ; - denotes the closure of the set consisting of the point } P\) Hence the name "skyscraper sheaf." Show that this sheaf could also be described \(\operatorname{as} i_{*}(A),\) where \(A\) denotes the constant sheaf \(A\) on the closed subspace \(\\{P\\}^{-},\) and \(i:\\{P\\}^{-} \rightarrow X\) is the inclusion.

Flasque Sheares. A sheaf \(\bar{y}\) on a topological space \(X\) is flasque if for every inclusion \(V \subseteq U\) of open sets, the restriction \(\operatorname{map} \mathscr{F}(U) \rightarrow \mathscr{F}(V)\) is surjective. (a) Show that a constant sheaf on an irreducible topological space is flasque. See (I, 81 ) for irreducible topological spaces. (b) If \(0 \rightarrow \overline{\mathscr{H}} \rightarrow \mathscr{F} \rightarrow \mathscr{H}^{\prime \prime} \rightarrow 0\) is an exact sequence of sheaves, and if \(\bar{y}\) is flasque, then for any open set \(U\). the sequence \(0 \rightarrow \mathscr{F}^{\prime}(U) \rightarrow \mathscr{F}(U) \rightarrow\) \(\mathscr{F}^{\prime \prime}\left(L^{\prime}\right) \rightarrow 0\) of abelian groups is also exact. (c) If \(0 \rightarrow \mathscr{H} \rightarrow \mathscr{H} \rightarrow \mathscr{H}^{\prime \prime} \rightarrow 0\) is an exact sequence of sheaves, and if \(\mathscr{H}^{\prime}\) and \(\overline{\mathscr{H}}\) are flasque, then \(\mathscr{F}^{\prime \prime}\) is flasque. (d) If \(f: X \rightarrow Y\) is a continuous map, and if \(\mathscr{F}\) is a flasque sheaf on \(X\), then \(f_{*} \overline{\mathscr{H}}\) is a flasque sheaf on \(Y\) (e) Let \(\overline{\mathscr{F}}\) be any sheaf on \(X\). We define a new sheaf \(\mathscr{G}\), called the sheaf of discontinuous sections of \(\mathscr{F}\) as follows. For each open set \(U \subseteq X, \mathscr{G}(U)\) is the set of

Examples of Valuation Rings. Let \(k\) be an algebraically closed field. (a) If \(K\) is a function field of dimension 1 over \(k(I, \$ 6),\) then every valuation ring of \(K / k\) (except for \(K\) itself) is discrete. Thus the set of all of them is just the abstract nonsingular curve \(C_{K}\) of \((\mathrm{I}, \$ 6)\) (b) If \(K / k\) is a function field of dimension two, there are several different kinds of valuations. Suppose that \(X\) is a complete nonsingular surface with function field \(K\) (1) If \(Y\) is an irreducible curve on \(X\), with generic point \(x_{1},\) then the local ring \(R=C_{x_{1}, x}\) is a discrete valuation ring of \(K k\) with center at the (nonclosed) point \(x_{1}\) on \(X\) (2) If \(f: X^{\prime} \rightarrow X\) is a birational morphism, and if \(Y^{\prime}\) is an irreducible curve in \(X^{\prime}\) whose image in \(X\) is a single closed point \(x_{0},\) then the local ring \(R\) of the generic point of \(Y^{\prime}\) on \(X^{\prime}\) is a discrete valuation ring of \(K k\) with center at the closed point \(x_{0}\) on \(X\) (3) Let \(r_{0} \in X\) be a closed point. Let \(f: X_{1} \rightarrow X\) be the blowing-up of \(x_{0}\) (I. \(\$ 4)\) and let \(E_{1}=f^{-1}\left(r_{0}\right)\) be the exceptional curve. Choose a closed point \(x_{1} \in E_{1},\) let \(f_{2}: X_{2} \rightarrow X_{1}\) be the blowing-up of \(x_{1},\) and let \(E_{2}=\) \(f_{2}^{-1}\left(x_{1}\right)\) be the exceptional curve. Repeat. In this manner we obtain a sequence of varieties \(X\), with closed points \(x_{i}\) chosen on them, and for each \(i,\) the local ring \(C_{1,1,1}, x_{1},\) dominates \(C_{x_{1}, x_{1}},\) Let \(R_{0}=\bigcup_{1=0}^{x} C_{x_{1}, x_{1}}\) Then \(R_{0}\) is a local ring, so it is dominated by some valuation ring \(R\) of \(K / k\) by \((\mathrm{I}, 6.1 \mathrm{A}) .\) Show that \(R\) is a valuation ring of \(K / k\). and that it has center \(x_{0}\) on \(X .\) When is \(R\) a discrete valuation ring? Note. We will see later (V.Ex. 5.6) that in fact the \(R_{0}\) of (3) is already a valuation ring itself, so \(R_{0}=R\). Furthermore, every valuation ring of \(K, k\) (except for \(K\) itself) is one of the three kinds just described.

Let \(X\) be a scheme over a field \(k\). Let \(\mathscr{L}\) be an invertible sheaf on \(X,\) and let {\(s _{0}, \ldots, s_{n}\);} \(\text { and }\left\\{t_{0}, \ldots, t_{m}\right\\} \) be two sets of sections of \(\mathscr{L},\) which generate the same subspace \(V \subseteq \Gamma(X, \mathscr{L}),\) and which generate the sheaf \(\mathscr{L}\) at every point. Suppose \(n \leqslant m .\) Show that the corresponding morphisms \(\varphi: X \rightarrow \mathbf{P}_{h}^{n}\) and \(\psi: X \rightarrow\) \(\mathbf{P}_{k}^{m}\) differ by a suitable linear projection \(\mathbf{P}^{m}-L \rightarrow \mathbf{P}^{n}\) and an automorphism of \(\mathbf{P}^{n},\) where \(L\) is a linear subspace of \(\mathbf{P}^{m}\) of dimension \(m-n-1\)

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