Chapter 12: Problem 8
In Exercises 1 through 8 express the splitting field of the indicated polynomial \(f(x) \in \mathbb{Q}[x]\) as a radical extension of \(\mathrm{Q}\). $$ x^{4}+x^{3}+2 x^{2}+x+1 $$
Short Answer
Expert verified
The splitting field is \( \mathbb{Q}(i\sqrt{3}) \).
Step by step solution
01
Identify the polynomial
The polynomial given is \( f(x) = x^4 + x^3 + 2x^2 + x + 1 \). We need to express its splitting field as a radical extension of \( \mathbb{Q} \).
02
Check for Roots Using Rational Root Theorem
Apply the Rational Root Theorem to determine if there are any rational roots. For the polynomial \( f(x) = x^4 + x^3 + 2x^2 + x + 1 \), the possible rational roots are \( \pm 1 \). Testing these, neither is a root because they do not satisfy the polynomial equation.
03
Factor the Polynomial
Since the polynomial does not have rational roots, proceed to factor it using a variety of methods. By testing various substitutions and checking discriminants, you find that the polynomial can be factored as \( (x^2 + x + 1)(x^2 + 2x + 1) \).
04
Solve Factored Polynomials
Now solve the quadratic equations obtained from the factorization:1. \( x^2 + x + 1 = 0 \) results in roots using the quadratic formula: \( x = \frac{-1 \pm \sqrt{-3}}{2} \) which implies roots \( \frac{-1 \pm i\sqrt{3}}{2} \).2. \( x^2 + 2x + 1 = 0 \) directly factors to \( (x+1)^2 = 0 \), which means \( x = -1 \).
05
Construct the Splitting Field
The roots from Step 4 are \( \frac{-1 + i\sqrt{3}}{2}, \frac{-1 - i\sqrt{3}}{2}, \) and \(-1\). Thus, the splitting field is \( \mathbb{Q}\left(\frac{-1 + i\sqrt{3}}{2}\right) \). This can be expressed as a radical extension of \( \mathbb{Q} \) by adjoining \( i\sqrt{3} \) to \( \mathbb{Q} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Roots
In mathematics, a polynomial root is a value for which the polynomial evaluates to zero. For example, if we consider a polynomial function \( f(x) \), a root is a value \( r \) such that \( f(r) = 0 \).
- The roots of a polynomial can be real or complex numbers.
- Finding the roots is crucial for understanding the behavior of the polynomial.
- The number of roots a polynomial can have is equal to its degree, although some roots may be repeated.
Radical Extension
A radical extension, in field theory, refers to a type of extension of a field that involves adding roots of a polynomial to the field. This is crucial for constructing the splitting field, which is the smallest field extension containing all the roots of a polynomial.
- Radical extensions often involve operations like extracting square roots, cube roots, etc.
- In the context of splitting fields, you build the smallest field that includes all the polynomial's roots by adjoining these roots to the original field \( \mathbb{Q} \).
- These extensions help in understanding the solvability of polynomials by radicals.
Factorization
Factorization is breaking down a complex polynomial into simpler components known as factors. These factors are usually lower degree polynomials, which, when multiplied together, reconstruct the original polynomial. In our exercise:
- The polynomial \( x^4 + x^3 + 2x^2 + x + 1 \) was factored into \((x^2 + x + 1)(x^2 + 2x + 1)\).
- Each factor corresponds to a simpler polynomial whose roots are easier to find.
- Factorization simplifies solving polynomial equations and facilitates the identification of polynomial properties.
Quadratic Formula
The quadratic formula is a mathematical expression that provides solutions to quadratic equations of the form \( ax^2 + bx + c = 0 \). The quadratic formula is given by:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula is particularly useful when dealing with polynomial factorization and solving quadratic factors that arise during the process. Here’s how it works:
- It helps find the roots of a quadratic equation directly when factoring is complicated or inefficient.
- The discriminant \( b^2 - 4ac \) determines the nature of the roots (real vs. complex).
- The formula can solve any quadratic equation, making it versatile and powerful.