Chapter 10: Problem 3
In Exercises 1 through 6 determine whether the indicated set of vectors is a basis for the indicated vector space \(V\) over the indicated field \(F\). $$ \\{2+3 i,-5\\} \quad V=C \quad F=\mathbb{R} $$
Short Answer
Expert verified
The set \( \{2+3i, -5\} \) is a basis for \( \mathbb{C} \) over \( \mathbb{R} \).
Step by step solution
01
Understand the Problem
We need to determine if the set \( \{2+3i, -5\} \) is a basis for the vector space \( V = \mathbb{C} \) over the field \( F = \mathbb{R} \). This involves checking if the vectors are linearly independent and span the vector space.
02
Define Basis Requirements
A set of vectors is a basis for a vector space if: 1) the vectors are linearly independent, and 2) they span the vector space. For \( \mathbb{C} \) over \( \mathbb{R} \), a basis must have two vectors, since \( \mathbb{C} \) is two-dimensional over the reals.
03
Check Linear Independence
To check if \( \{2+3i, -5\} \) are linearly independent over \( \mathbb{R} \), assume \( a(2+3i) + b(-5) = 0 \). Solving for real numbers \( a \) and \( b \), gives us two equations: \( 2a - 5b = 0 \) and \( 3a = 0 \). From \( 3a = 0 \), we find \( a = 0 \). Substituting \( a = 0 \) in \( 2a - 5b = 0 \) gives \( b = 0 \). Thus, they are linearly independent.
04
Check Spanning the Space
Since \( \mathbb{C} \) is two-dimensional over \( \mathbb{R} \), a set of two linearly independent vectors will span \( \mathbb{C} \). Here, \( 2+3i \) and \( -5 \) are independent and thus span \( \mathbb{C} \).
05
Conclusion
The set \( \{2+3i, -5\} \) consists of linearly independent vectors and spans the vector space \( \mathbb{C} \) over \( \mathbb{R} \), so it is a basis for \( \mathbb{C} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Independence
In vector spaces, linear independence is a crucial concept that determines whether a set of vectors can serve as a basis. To determine if vectors are linearly independent, one must check if the only solution to a particular linear combination of these vectors being equal to zero is the trivial solution. For example, if we have vectors \( v_1 \) and \( v_2 \), they are linearly independent if the equation \( a_1v_1 + a_2v_2 = 0 \) only holds true when \( a_1 = 0 \) and \( a_2 = 0 \). In simpler terms, there aren't any non-zero coefficients \( a_1 \) and \( a_2 \) that can make the equation hold. This condition is pivotal for forming a basis. If vectors are linearly independent:
- They do not lie on the same line (in 2D) or plane (in 3D), making them capable of forming a unique direction in the vector space.
- They complement each other by not being a combination or multiple of each other, showcasing diverse directions.
Complex Numbers
Complex numbers extend the concept of one-dimensional number lines (real numbers) to two-dimensional planes. A complex number is of the form \(a + bi\), where:
- \(a\) and \(b\) are real numbers, representing the real and imaginary parts respectively.
- \(i\) is the imaginary unit, satisfying the property \(i^2 = -1\).
Real Number Field
The real number field, denoted as \( \mathbb{R} \), forms the foundation for many mathematical concepts and structures. Real numbers include all rational and irrational numbers, forming an unbroken continuum of values. This is significant because:
- It is the field over which many vector spaces, including spaces involving complex numbers, can be defined.
- It provides closure properties, meaning operations like addition and multiplication performed on real numbers will yield real numbers.
- Real numbers support ordering, which isn't available in fields like complex numbers.