Chapter 9: Problem 42
Solve by (a) Completing the square (b) Using the quadratic formula $$ 4 x^{2}+4 x+1=0 $$
Short Answer
Expert verified
Question: Solve the quadratic equation \(4x^2 + 4x + 1 = 0\) using (a) completing the square, and (b) the quadratic formula.
Answer: The solutions for the given quadratic equation are \(x = 0\) and \(x = \frac{-1}{2}\).
Step by step solution
01
Rewrite the equation in the standard form
Rewrite the given equation as \(4(x^2 + x) + 1 = 0\).
02
Divide the equation by the leading coefficient
Divide the equation by the leading coefficient, which is 4, to make the leading term \(x^2\). We get \((x^2 + x) +\frac{1}{4}=0.\)
03
Add and subtract the square of half the coefficient of x
Take half of the coefficient of x (which is 1) and add its square (which is \(\frac{1}{4}\)) to the equation. Then, subtract \(\frac{1}{4}\) to keep the equation balanced. We get \((x^2 + x + \frac{1}{4}) - \frac{1}{4} + \frac{1}{4} = 0.\)
04
Simplify and use the square root property
The left-hand side now becomes a perfect square trinomial: \((x + \frac{1}{2})^2 = \frac{1}{4}\). Now, we can apply the square root property by taking the square root of both sides: $$x + \frac{1}{2} = \pm \frac{1}{2}.$$
05
Solve for x
Subtract \(\frac{1}{2}\) from both sides to solve for x: $$x = \frac{1}{2}(\pm 1 - 1).$$ This gives us two solutions: $$x = 0, \frac{-1}{2}.$$
Method (b) - Using the quadratic formula
06
Identify the coefficients
Identify the coefficients a, b, and c in the given equation: $$a = 4, b = 4, c = 1.$$
07
Plug the coefficients into the quadratic formula
Apply the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.$$ Substitute the values of a, b, and c into the formula: $$x = \frac{-(4) \pm \sqrt{(4)^2 - 4(4)(1)}}{2(4)}.$$
08
Simplify and solve for x
Simplify the expression: $$x = \frac{-4 \pm \sqrt{16 - 16}}{8}.$$ Notice that the expression under the square root is zero. Therefore, $$x = \frac{-4 \pm 0}{8}.$$ This gives us the same two solutions as in the completing the square method: $$x = 0, \frac{-1}{2}.$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
Completing the square is a method used to solve quadratic equations by transforming them into a perfect square trinomial. This method is particularly useful when you need exact solutions or to convert a quadratic equation into its vertex form. Here's how to do it:
- Start with a quadratic equation in the form of ax² + bx + c = 0.
- Divide every term by 'a', the coefficient of x², to simplify the leading term to x².
- Then, take half of the coefficient of x, square it, and add and subtract this value inside the equation to maintain balance.
- Now, rewrite the quadratic part as \( (x + d)^2 \), where d is half the coefficient of x.
- This transformation turns your equation into a square of a binomial, which you can solve by taking the square root of both sides.
Quadratic Formula
The quadratic formula is a universal method for solving any quadratic equation of the form ax² + bx + c = 0. It allows you to find the roots directly using the coefficients a, b, and c. To use the quadratic formula effectively, follow these steps:
- Identify the coefficients a, b, and c from your quadratic equation.
- Plug the coefficients into the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
- This formula calculates the solutions by using both the plus and minus configurations of the square root, allowing for potentially two different solutions depending on the discriminant \( b^2 - 4ac \).
- Simplify the calculations under the square root carefully.
Solving Equations
Solving quadratic equations involves finding the values of x that satisfy the equation ax² + bx + c = 0. The two primary methods taught in school are completing the square and the quadratic formula.
- For simple quadratics or when using vertex form, completing the square is an excellent method for deriving integer or simple rational solutions.
- The quadratic formula, however, is a powerful tool because it works universally on any quadratic equation, regardless of the discriminant's value or the complexity of solutions.
- With both methods, carefully balance and check your calculations, as precision is key to solving accurately.
- Once the solutions are found, you can verify by back-substituting into the original equation to ensure they satisfy it.