Chapter 8: Problem 31
Find the inverse function. $$ h(x)=9 x^{5}+7 $$
Short Answer
Expert verified
Answer: The inverse function of h(x) = 9x^5 + 7 is h^(-1)(x) = $$\sqrt[5]{\frac{x - 7}{9}}$$.
Step by step solution
01
Swap the roles of x and y in the function
Replace h(x) with y, swap x and y:
$$
y = 9x^5 + 7
$$
Now, swap x and y
$$
x = 9y^5 + 7
$$
02
Solve for the new independent variable y
We will now solve this equation for y:
Subtract 7 from both sides
$$
x - 7 = 9y^5
$$
Now, divide both sides by 9
$$
\frac{x - 7}{9} = y^5
$$
Finally, take the fifth root of both sides:
$$
y = \sqrt[5]{\frac{x - 7}{9}}
$$
03
Write the inverse function
Now that we have y in terms of x, we can write the inverse function h^(-1)(x):
$$
h^{-1}(x) = \sqrt[5]{\frac{x - 7}{9}}
$$
So, the inverse function of h(x) is:
$$
h^{-1}(x) = \sqrt[5]{\frac{x - 7}{9}}
$$
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Inverses
An inverse function essentially reverses the roles of input and output for a given function. Think of it as a way to "undo" the action of the original function. If you start with a value, apply a function, and then apply its inverse, you'll end up back where you started. This is because inverse functions satisfy the property:
- If the function is denoted by \( f(x) \), then its inverse is denoted by \( f^{-1}(x) \).
- Applying \( f(x) \) followed by \( f^{-1}(x) \), or vice versa, returns the original input.For example: \( f(f^{-1}(x)) = x \) and \( f^{-1}(f(x)) = x \).
Algebraic Manipulation
Algebraic manipulation is the manner by which we rearrange and solve equations. For the task of finding an inverse function, effective manipulation steps are crucial. After interchanging \( x \) and \( y \) in the original function, we need to isolate the new \( y \). The idea is to express \( y \) explicitly in terms of \( x \). This generally involves steps like:
- Subtracting constants from both sides to simplify the equation.
- Dividing by coefficients to manage terms involving \( y \).
- Performing necessary operations such as roots, powers, etc., to fully solve for \( y \).
Solving Equations
Solving equations is a fundamental aspect of algebra. It requires precise steps to find the value of unknowns or to rearrange terms to get a desired form. In the context of inverse functions, solving equations involves reworking the swapped equation to express the new dependent variable in terms of the original independent variable.Essential techniques include:
- Rearranging the equation to move all terms involving the variable of interest to one side.
- Performing arithmetic operations like addition, subtraction, multiplication, or division to simplify.
- Using inverse operations like roots or exponents to eliminate powers and find the answer.