Chapter 16: Problem 14
What do you need to know about two matrices to know if their sum exists?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
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Chapter 16: Problem 14
What do you need to know about two matrices to know if their sum exists?
These are the key concepts you need to understand to accurately answer the question.
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Check the statements in Exercises \(19-23\) using the matrices \(\mathbf{U}=\left(\begin{array}{ll}2 & 3 \\ 1 & 2\end{array}\right), \mathbf{V}=\left(\begin{array}{cc}-1 & 4 \\ 0 & 2\end{array}\right), \mathbf{W}=\left(\begin{array}{cc}5 & -5 \\ 4 & 7\end{array}\right)\). $$ 2 \mathbf{W}+3 \mathbf{W}=5 \mathbf{W} $$
Given the matrices below, evaluate the expressions if possible. If it is not possible, explain why. $$ \mathbf{A}=\left(\begin{array}{ll} 2 & 3 \\ 8 & 4 \end{array}\right) $$ $$ \mathbf{B}=\left(\begin{array}{cc} 5 & -3 \\ -2 & 7 \end{array}\right) $$ $$ \mathbf{C}=\left(\begin{array}{rrr} 4 & -2 & -5 \\ 0 & -4 & -3 \end{array}\right) $$ $$ \mathbf{D}=\left(\begin{array}{ccc} 2 & 4 & -4 \\ 3 & -10 & 2 \\ 2 & 4 & 5 \end{array}\right) $$ $$ \mathbf{A} \mathbf{A}+\mathbf{A B} $$
In Problems \(24-25,\) refer to \(\mathbf{R}\) and \(\mathbf{M},\) matrices of mean SAT scores. The columns are mean SAT reasoning scores for the years \(2001-2008 .\) The first row is scores for males and the second row is scores for females. Matrix \(\mathbf{R}\) is the Critical Reading scores, and matrix \(\mathbf{M}\) is the Mathematics scores. \(^{1}\). \(\mathbf{R}=\left(\begin{array}{llllllll}509 & 507 & 512 & 512 & 513 & 505 & 504 & 504 \\ 502 & 502 & 503 & 504 & 505 & 502 & 502 & 500\end{array}\right)\) \(\mathbf{M}=\left(\begin{array}{cccccccc}533 & 534 & 537 & 537 & 538 & 536 & 533 & 533 \\ 498 & 500 & 503 & 501 & 504 & 502 & 499 & 500\end{array}\right)\). Calculate \(\mathbf{R}+\mathbf{M}\). What does this represent?
What do you need to know about two matrices to know if their product exists?
If possible, use row operations to solve the systems. $$ \left\\{\begin{array}{l} 6 x+5 y=4 \\ x-3 y=14 \end{array}\right. $$
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