Chapter 12: Problem 44
For what values of \(a\) does the equation have a solution in \(x\) ? $$ a^{2}+a x^{2}=0 $$
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Chapter 12: Problem 44
For what values of \(a\) does the equation have a solution in \(x\) ? $$ a^{2}+a x^{2}=0 $$
These are the key concepts you need to understand to accurately answer the question.
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Without solving the equation, decide how many solutions it has. $$ \left(x^{2}+1\right)(x-2)=0 $$
Write the polynomials in exercises in standard form $$a_{n} x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}$$ What are the values of the coefficients \(a_{0}, a_{1}, \ldots, a_{n} ?\) Give the degree of the polynomial. $$ 3-2(x-5)^{2} $$
State the given quantities if \(p(x)\) is a polynomial of degree 5 with constant term 3 , and \(q(x)\) is a polynomial of degree 8 with constant term -2. The degree of \(p(x)^{3} q(x)^{2}\).
Give the leading term. $$ 12 x^{13}+4 x^{5}-11 x^{13} $$
Refer to the functions \(f(x)\) and \(g(x),\) where the function $$ g(x)=1+\frac{1}{2} x+\frac{3}{8} x^{2}+\frac{5}{16} x^{3} $$ is used to approximate the values of $$ f(x)=\frac{1}{\sqrt{1-x}} $$ Given that $$ f(1 / 2)=\frac{1}{\sqrt{1-\frac{1}{2}}}=\frac{1}{\sqrt{\frac{1}{2}}}=\frac{1}{\frac{1}{\sqrt{2}}}=\sqrt{2} $$ use \(g(x)\) to find a rational number (a fraction) that approximately equals \(\sqrt{2}\).
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