Chapter 11: Problem 12
Rewrite the equation using logarithms instead of exponents. $$ 10^{m}=n $$
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Chapter 11: Problem 12
Rewrite the equation using logarithms instead of exponents. $$ 10^{m}=n $$
These are the key concepts you need to understand to accurately answer the question.
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Solve the equations. $$ 2215(0.944)^{t}=800 $$
In 2003 the number of sport utility vehicles sold in China was predicted to grow by \(30 \%\) a year for the next 5 years. \({ }^{4}\) What is the doubling time?
Are the expressions in Problems equivalent for positive \(a\) and \(b\) ? If so, explain why. If not, give values for \(a\) and \(b\) that lead to different values for the two expressions. $$ \log (10 b) \text { and } 1+\log b $$
What does the table tell you about \(\log 27 ?\) $$ \begin{array}{c|c|c|c|c} \hline x & 1.40 & 1.42 & 1.44 & 1.46 \\ \hline 10^{x} & 25.1 & 26.3 & 27.5 & 28.8 \\ \hline \end{array} $$
Concern the Krumbein phi \((\phi)\) scale of particle size, which geologists use to classify soil and rocks, defined by the formula \({ }^{15}\) $$ \phi=-\log _{2} D $$ where \(D\) is the diameter of the particle in \(\mathrm{mm}\). A cobblestone has diameter 3 inches. Given that 1 inch is \(25.4 \mathrm{~mm}\), what does it measure on the \(\phi\) scale?
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