Chapter 11: Problem 1
Rewrite the equation using exponents instead of logarithms. $$ \log 0.01=-2 $$
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Chapter 11: Problem 1
Rewrite the equation using exponents instead of logarithms. $$ \log 0.01=-2 $$
These are the key concepts you need to understand to accurately answer the question.
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A trillion is one million million. What is the logarithm of a trillion?
Concern the Krumbein phi \((\phi)\) scale of particle size, which geologists use to classify soil and rocks, defined by the formula \({ }^{15}\) $$ \phi=-\log _{2} D $$ where \(D\) is the diameter of the particle in \(\mathrm{mm}\). On the \(\phi\) scale, two particles measure \(\phi_{1}=3\) and \(\phi_{2}=-1,\) respectively. Which particle is larger in diameter? How many times larger?
If possible, use logarithm properties to rewrite the expressions in terms of \(u, v, w\) given that $$u=\log x, v=\log y, w=\log z$$ Your answers should not involve logs. $$ \log \left(x^{2}+y^{2}\right) $$
Solve the equations, first approximately, as in Example \(1,\) by filling in the given table, and thèn to four decimal places by using logarithms. $$ \begin{aligned} &11.8\\\ &\text { Solve }\\\ &0.5^{x}=0.1\\\ &\text { Table }\\\ &\begin{array}{c|c|c|c|c} \hline x & 3.1 & 3.2 & 3.3 & 3.4 \\ \hline 0.5^{x} & & & & \\ \hline \end{array} \end{aligned} $$
If \(\$ 1200\) is invested at \(7.5 \%\) annual interest, compounded continuously, when is it worth \(\$ 15,000 ?\)
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