/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 93 Let \(E\) be an event which is n... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(E\) be an event which is neither a certainty nor an impossibility. If probability is such that \(P(E)=1+\lambda+\lambda^{2}\) and \(P(E)=(1+\lambda)^{2}\) in terms of an unknown \(\lambda\). Then \(P(E)\) is equal to a. 1 b. \(3 / 4\) c. \(1 / 4\) d. none of these

Short Answer

Expert verified
The probability \(P(E)\) is equal to 1.

Step by step solution

01

Establish the Equations

We are given that\[ P(E) = 1 + \lambda + \lambda^2 \]and\[ P(E) = (1 + \lambda)^2. \]Therefore, we can set the two expressions for \(P(E)\) equal to each other:\[ 1 + \lambda + \lambda^2 = (1 + \lambda)^2. \]
02

Expand the Equation

Expand the right-hand side expression:\[ (1 + \lambda)^2 = 1 + 2\lambda + \lambda^2. \]
03

Set Equations Equal and Simplify

Now we have:\[ 1 + \lambda + \lambda^2 = 1 + 2\lambda + \lambda^2. \]Subtract \( 1 + \lambda + \lambda^2 \) from both sides to simplify:\[ 0 = \lambda. \]
04

Evaluate \(P(E)\) using \(\lambda = 0\)

Substituting \(\lambda = 0\) found in the previous step into either expression for \(P(E)\):\[ P(E) = 1 + 0 + 0^2 = 1. \]
05

Conclusion Check

Since we have \( P(E) = 1 \), and it matches option 'a', which is \(1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equations
Equations are mathematical statements that express the equality between two expressions. In our scenario, both expressions for probability are considered. Equations allow us to find the values of unknown variables by manipulating their relationships. The exercise presents us with two expressions for the probability of an event occurring: \( P(E) = 1 + \lambda + \lambda^{2} \) and \( P(E) = (1 + \lambda)^{2} \).
By setting these two equations equal, we explore how variables interact to satisfy both conditions simultaneously, letting us solve for unknowns like \( \lambda \).
This interaction and simplification process unveils crucial insights about the value of the probability \( P(E) \), transforming abstract math into tangible results.
Equations serve as a foundational tool in mathematics for uncovering truths and making predictions based on known quantities.
Algebra
Algebra is a branch of mathematics dealing with symbols and the rules for manipulating those symbols. It is a narrative of relationships and change. In this exercise, we see algebra at play as the two probability expressions are simplified and expanded. Let's delve deeper into the equation \( P(E) = (1 + \lambda)^2 \).
Applying algebraic rules to expand this equation results in \( 1 + 2\lambda + \lambda^2 \). Algebra uses simple operations to transform these expressions systematically. These operations enable us to bring equations into a form that is easier to interpret and solve.
  • Expansion: Breaking down expressions like \((1 + \lambda)^2\) into simpler components.
  • Simplification: Combining like terms, such as reducing \( 1 + 2\lambda + \lambda^2 \) and \( 1 + \lambda + \lambda^2 \) to their simplest forms.
  • Solving: Isolating variables to find their values, shown when \( \lambda \) equals zero.
Algebra acts like the language of logic, translating between abstract problems and concrete solutions.
Problem Solving
Problem solving is the process of working through details of an issue to reach a solution. With the tools of equations and algebra, we can solve for probabilities by methodical reasoning. Let's break down the steps utilized in the solution.
First, identify what you know and what you need to find out. Here, we need the value of \( P(E) \) given two expressions in terms of \( \lambda \). Next, apply mathematical rules to form a solvable equation.
The approach involves aligning both expressions, reducing where possible, and ultimately isolating \( \lambda \).
  • Identify the Given: Both expressions provided.
  • Set Up Equations: Make them equal to find \( \lambda \).
  • Simplify: Use algebra to reduce the complexity.
  • Conclude: Substitute \( \lambda = 0 \) back to find \( P(E) \).
Effective problem solving involves a clear understanding of the goal and the systematic application of mathematical principles to derive the solution, as demonstrated in the exercise.

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Most popular questions from this chapter

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