Chapter 9: Problem 33
There are 20 cards. Ten of these cards have the letter ' \(T\) printed on them and the other 10 have the letter " \(T^{*}\) printed on them. If three cards are picked up at random and kept in the same order, the probability of making word IIT is a. \(4 / 27\) b. \(5 / 38\) c. \(1 / 8\) d. \(9 / 80\)
Short Answer
Step by step solution
Understand the Problem
Calculate Total Ways to Pick 3 Cards
Determine Favorable Outcomes for 'IIT'
Calculate the Probability
Verify Simplification
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Combinations
\[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]
This formula represents the number of ways to choose \(r\) items from a total of \(n\) without regard to the sequence. For the exercise given, it means we plug in 20 for \(n\) and 3 for \(r\). By calculating \(\binom{20}{3} = 1140\), it shows that there are 1140 possible outcomes for selecting any 3 cards from the 20 available.
Thus, understanding combinations helps us to assess the total number of configurations without considering the order, which is essential in calculating realistic probabilities.
Permutation and Combination
In our specific problem, after determining the combinations of card selections, we dive into permutations for ordering within those selections. While **combinations** calculate how many groups of cards can be selected, permutations would be relevant if the position (order) of each card within those groups also impacts the result. Since the arrangement 'IIT' needs specific positions filled with specific cards, permutations allow for further discernment.
To draw the word 'IIT', we have to choose the cards correctly, focusing on the constraints that dictate which card must take which position. This is why first using combinations to select the cards and then tailoring the exact order through permutations provides a layered approach to solving such probability puzzles effectively. This step-by-step narrowing focus significantly refines our search for valid outcomes.
Probability Theory
- A probability of 0 means the event won't occur.
- A probability of 1 means the event is certain to occur.
- Values between 0 and 1 express varying chances of occurrence.
\[P(\text{IIT}) = \frac{\text{Favorable Outcomes}}{\text{Total Outcomes}} = \frac{450}{1140}\]
Here, 450 represents the specific ways to form the word 'IIT', while 1140 is the total ways to pick any 3 cards. Simplifying this ratio gives a more manageable probability expression, emphasizing the simplicity and elegance of probability theory in assessing likely scenarios.
By systematically identifying both possible outcomes and favorable cases, probability theory provides a structured approach to analyzing such random processes and investigating the various likelihood events within them.