Chapter 8: Problem 7
If \(A\) is a matrix such that \(A^{2}+A+2 I=O\), then which of the following is/are true? a. \(A\) is non-singular b. \(A\) is symmetric c. A cannot be skew-symmetric d. \(A^{-1}=-\frac{1}{2}(A+I)\)
Short Answer
Expert verified
a, d are true. A is non-singular, and the inverse formula holds.
Step by step solution
01
Analyze the given equation
We are given the equation \( A^2 + A + 2I = O \). This can be rearranged to \( A^2 + A = -2I \). Here, \( I \) represents the identity matrix and \( O \) the zero matrix.
02
Check if A is non-singular
A matrix is non-singular if it is invertible, meaning its determinant is non-zero. In the equation \( A^2 + A = -2I \), if \( A \) were singular, it would imply \( A^2 + A \) is also singular, which cannot equate to a non-zero matrix \(-2I\). Thus, \( A \) must be non-singular.
03
Check if A is symmetric
A matrix is symmetric if \( A = A^T \). There is no indication from the given equation \( A^2 + A + 2I = O \) that \( A \) must be symmetric. Thus, this cannot be concluded.
04
Check if A can be skew-symmetric
A matrix \( A \) is skew-symmetric if \( A^T = -A \). If \( A \) were skew-symmetric, then \( A^2 \) would be symmetric (since \((A^2)^T = A^T A^T = (-A)(-A) = A^2\)). Therefore, \( A^2 + A + 2I \) would not be the zero matrix unless \( A \) itself is the zero matrix, which is inconsistent with \( A^2 + A = -2I \). Thus, \( A \) cannot be skew-symmetric.
05
Check correctness of the inverse formula
To find the inverse \( A^{-1} \), we use \( A^2 + A = -2I \). Factoring gives \( A(A + I) = -2I \). Assuming \( A^{-1} \) exists, we rearrange terms as \( A^{-1} = -\frac{1}{2}(A + I) \) by multiplying both sides by \( A^{-1} \) to find \( A^{-1} = -\frac{1}{2}(A + I) \), which verifies this formula.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Inversion
Matrix inversion is a process to find a matrix, known as the inverse of the original matrix, which when multiplied with the original matrix yields the identity matrix. The identity matrix, denoted as \(I\), is a special kind of square matrix with 1's on the diagonal and 0's elsewhere. If a matrix \(A\) has an inverse, it is denoted as \(A^{-1}\), and it satisfies the equation \(A \cdot A^{-1} = I\).
This property is very useful in solving systems of linear equations represented in matrix form. However, not all matrices have inverses. Only non-singular matrices have inverses, as they have non-zero determinants.
In the provided exercise, we've shown that \(A^{-1}\) can be expressed using the relation \(A^{-1} = -\frac{1}{2}(A + I)\). This reinforces the idea that \(A\) is invertible and non-singular.
This property is very useful in solving systems of linear equations represented in matrix form. However, not all matrices have inverses. Only non-singular matrices have inverses, as they have non-zero determinants.
In the provided exercise, we've shown that \(A^{-1}\) can be expressed using the relation \(A^{-1} = -\frac{1}{2}(A + I)\). This reinforces the idea that \(A\) is invertible and non-singular.
Singular and Non-Singular Matrices
A matrix is classified as singular or non-singular based on its determinant. A singular matrix has a determinant equal to zero, while a non-singular matrix has a non-zero determinant, indicating that it is invertible.
The importance of a matrix being non-singular lies in its applications. Non-singular matrices can be used in solving linear equations and have well-defined inverses. In contrast, singular matrices are problematic in such operations, as they indicate redundancy or dependency among equations.
In the exercise, we concluded \(A\) is non-singular by observing that \(A^2 + A\) equates to a non-zero matrix \(-2I\). This means \(A\) must have a non-zero determinant, confirming it is non-singular and invertible.
The importance of a matrix being non-singular lies in its applications. Non-singular matrices can be used in solving linear equations and have well-defined inverses. In contrast, singular matrices are problematic in such operations, as they indicate redundancy or dependency among equations.
In the exercise, we concluded \(A\) is non-singular by observing that \(A^2 + A\) equates to a non-zero matrix \(-2I\). This means \(A\) must have a non-zero determinant, confirming it is non-singular and invertible.
Symmetric Matrices
Symmetric matrices have a distinct property where the matrix is equal to its transpose, i.e., \(A = A^T\). This characteristic gives symmetric matrices special algebraic properties and applications, particularly in quadratic forms and eigenvalue problems.
Symmetric matrices can be easily recognized through their components being mirror-reflected along the main diagonal. For example, entries \(a_{ij}\) and \(a_{ji}\) will be equal.
In the analysis of the exercise, no evidence suggests \(A\) satisfies the symmetry condition \(A = A^T\). Therefore, without additional information, we cannot conclude that \(A\) is a symmetric matrix from the given equation.
Symmetric matrices can be easily recognized through their components being mirror-reflected along the main diagonal. For example, entries \(a_{ij}\) and \(a_{ji}\) will be equal.
In the analysis of the exercise, no evidence suggests \(A\) satisfies the symmetry condition \(A = A^T\). Therefore, without additional information, we cannot conclude that \(A\) is a symmetric matrix from the given equation.
Skew-Symmetric Matrices
A skew-symmetric matrix has elements satisfying the relation \(A^T = -A\). This means elements opposite to each other across the main diagonal are negatives of each other, and all diagonal elements are zero.
The skew-symmetric property implies that if a matrix is skew-symmetric, then \(A^2\) will be symmetric since \((A^2)^T = A^T A^T = (-A)(-A) = A^2\).
In our exercise, assuming \(A\) to be skew-symmetric leads to contradictions. Specifically, \(A^2\) would cause \(A^2 + A + 2I\) to not be zero, except when \(A\) itself is zero, which is inconsistent with \(A^2 + A = -2I\). Thus, \(A\) cannot be skew-symmetric.
The skew-symmetric property implies that if a matrix is skew-symmetric, then \(A^2\) will be symmetric since \((A^2)^T = A^T A^T = (-A)(-A) = A^2\).
In our exercise, assuming \(A\) to be skew-symmetric leads to contradictions. Specifically, \(A^2\) would cause \(A^2 + A + 2I\) to not be zero, except when \(A\) itself is zero, which is inconsistent with \(A^2 + A = -2I\). Thus, \(A\) cannot be skew-symmetric.