Chapter 2: Problem 54
The greatest positive argument of complex number satisfying \(|z-4|=\operatorname{Re}(z)\) is a. \(\frac{\pi}{3}\) b. \(\frac{2 \pi}{3}\). c. \(\frac{\pi}{2}\) d. \(\frac{\pi}{4}\)
Short Answer
Expert verified
The greatest positive argument is \( \frac{\pi}{3} \), option (a).
Step by step solution
01
Define the Complex Number
Let the complex number be denoted by \( z = x + yi \), where \( x \) and \( y \) are real numbers.
02
Set Up the Equation
Given \( |z - 4| = \operatorname{Re}(z) \), substitute \( z = x + yi \). This becomes \( |(x - 4) + yi| = x \).
03
Calculate the Magnitude
The magnitude \( |(x - 4) + yi| \) is calculated as \( \sqrt{(x-4)^2 + y^2} \). So the equation becomes \( \sqrt{(x-4)^2 + y^2} = x \).
04
Simplify the Equation
Square both sides of the equation to eliminate the square root: \( (x-4)^2 + y^2 = x^2 \).
05
Expand and Rearrange
Expand this to get \( x^2 - 8x + 16 + y^2 = x^2 \). Simplify to \( -8x + 16 + y^2 = 0 \). This implies \( y^2 = 8x - 16 \).
06
Find Condition for Validity
Since \( y^2 \) is non-negative, \( 8x - 16 \geq 0 \) giving \( x \geq 2 \).
07
Consider Range of Polar Angle
Considering the geometric interpretation, the equation \( |z-4| = \operatorname{Re}(z) \) suggests a vertical line. The maximum angle, \( \theta \), in the first quadrant from the positive x-axis is \( \tan^{-1}(\frac{y}{x}) \).
08
Determine Greatest Positive Argument
From the derived equation \( y^2 = 8x - 16 \), use \( x \geq 2 \). For greatest positive argument in the first quadrant (aligning with positive directions), when \( x=2 \), \( y = 0 \). So at \( x = 4 \), \( y = 2\sqrt{3} \) gives greatest angle \( \theta = \frac{\pi}{3} \).
09
Check Possible Angles
Re-evaluate for potential angles; as the circle (centered at \(4,0\)) touches the y-axis at \((-4,0)\), the greatest argument arising is indeed from above, confirming \( \frac{\pi}{3} \) alongside typical unit circle conventions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of Complex Numbers
The magnitude of a complex number is like its "distance" from the origin in the complex plane. To find the magnitude of a complex number such as \( z = a + bi \), we use the formula \( |z| = \sqrt{a^2 + b^2} \). This formula is derived from the Pythagorean theorem, as a complex number can be visualized as a right-angled triangle in the complex plane. Here, \( a \) is the real part and \( b \) is the imaginary part.
- The magnitude tells us how "large" the number is, regardless of its direction or sign.
- It's always a non-negative value.
Polar Coordinates
Polar coordinates provide a different way to express complex numbers through \( r \) and \( \theta \) where \( r \) is the magnitude and \( \theta \) represents the angle or direction compared to the positive x-axis. This is useful when dealing with rotations or when calculating angles as in our exercise.
- Use \( r = \sqrt{x^2 + y^2} \) for magnitude.
- Find \( \theta = \tan^{-1}\left(\frac{y}{x}\right) \) for the angle.
Greatest Positive Argument
The argument of a complex number is the angle that the number forms with the positive direction of the x-axis. It's a key part in the polar form of complex numbers. To find the greatest positive argument of a complex number \( z = a + bi \), you evaluate the angle \( \theta \).
- This involves the angle from \( 0 \) to \( 2\pi \).
- For our equation, solving \( |z-4| = \operatorname{Re}(z) \) reveals possible values of \( x \) that define our argument.
Real and Imaginary Parts
Understanding the real and imaginary parts of a complex number like \( z = a + bi \) is crucial. The real part, \( a \), and the imaginary part, \( b \), allow us to use algebraic methods to manipulate and understand complex numbers.
- The real part is \( a = \operatorname{Re}(z) \).
- The imaginary part is \( b = \operatorname{Im}(z) \).