Chapter 2: Problem 23
If \((\cos \theta+i \sin \theta)(\cos 2 \theta+i \sin 2 \theta) \cdots(\cos n \theta+i \sin n \theta)=1\), then the value of \(\theta\) is, \(m \in N\) a. \(4 m \pi\) b. \(\frac{2 m \pi}{n(n+1)}\) \(\begin{array}{ll}\text { c. } & \frac{4 m \pi}{n(n+1)} & \text { d. } \frac{m \pi}{n(n+1)}\end{array}\)
Short Answer
Step by step solution
Express Each Term Using Euler's Formula
Write Down the Complete Product
Calculate the Sum Inside the Exponent
Set the Exponential Equation Equal to 1
Solve for \(\theta\)
Choose the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Euler's formula
- \( e^{i\theta} = \cos \theta + i \sin \theta \)
- \( (\cos \theta + i \sin \theta)(\cos 2\theta + i \sin 2\theta) \cdots (\cos n\theta + i \sin n\theta) \)
- \( e^{i\theta}, e^{i2\theta}, \ldots, e^{in\theta} \)
Arithmetic series
- \( 1 + 2 + \cdots + n \)
- \( S_n = \frac{n(n+1)}{2} \)
- \( \theta(1 + 2 + \cdots + n) = \theta \frac{n(n+1)}{2} \)
Complex numbers
The application of Euler’s formula in our exercise involves representing the trigonometric functions as a complex number, like so:
- \( \cos \theta + i \sin \theta \)
Product of complex numbers
- Distribute each part and combine like terms.
- \( (\cos \theta + i \sin \theta)(\cos 2\theta + i \sin 2\theta) \cdots (\cos n\theta + i \sin n\theta) \)
- \( e^{i(\theta + 2\theta + \cdots + n\theta)} \)
- \( e^{i(\theta(1 + 2 + \cdots + n))} \)
- \( \theta = \frac{4m\pi}{n(n+1)} \)