Chapter 9: Problem 40
For Problems \(35-42\), (a) find the \(y\) intercepts, (b) find the \(x\) intercepts, and (c) find the intervals of \(x\) where \(f(x)>0\) and those where \(f(x)<0\). Do not sketch the graphs. $$ f(x)=(x+2)^{2}(x-1)^{3}(x-2) $$
Short Answer
Expert verified
The y-intercept is (0, 8); x-intercepts are (-2, 0), (1, 0), and (2, 0). f(x)>0 for (-∞, -2)∪(2,∞); f(x)<0 for (-2, 1)∪(1, 2).
Step by step solution
01
Find the y-intercept
The y-intercept of a function is found by evaluating the function at \( x = 0 \). Substitute \( x = 0 \) into the function: \( f(0) = (0+2)^2(0-1)^3(0-2) \). This simplifies to \( f(0) = 2^2(-1)^3(-2) = 4 \times (-1) \times (-2) = 8 \). Thus, the y-intercept is \((0, 8)\).
02
Find the x-intercepts
To find the x-intercepts, set \( f(x) = 0 \) and solve for \( x \). The function can be expressed as \((x+2)^2(x-1)^3(x-2) = 0 \). This equation is zero when any factor is zero: \( x+2 = 0 \), \( x-1 = 0 \), or \( x-2 = 0 \). Solving these equations gives the x-intercepts: \( x = -2 \), \( x = 1 \), and \( x = 2 \). Therefore, the x-intercepts are \((-2, 0)\), \((1, 0)\), and \((2, 0)\).
03
Determine intervals of positive and negative values
To determine where \( f(x) > 0 \) or \( f(x) < 0 \), evaluate the polynomial's behavior between and beyond the critical points \( x = -2 \), \( x = 1 \), and \( x = 2 \). These points divide the real number line into intervals: \((-fty, -2)\), \((-2, 1)\), \((1, 2)\), and \((2, fty)\). Choose test points for each interval: \( x = -3, 0, 1.5, 3 \). Analyze the sign of the function in each interval:- For \( x = -3 \), all terms are negative, hence \( f(x)<0 \).- For \( x = 0 \), \((0+2)^2(0-1)^3(0-2) = 4(-1)(-2) = 8 > 0\).- For \( x = 1.5 \), all terms except \( (x-2) \) are positive, hence \( f(x)<0 \).- For \( x = 3 \), all terms are positive, hence \( f(x)>0 \).Thus, \( f(x)>0 \) on \((-fty, -2) \cup (2, fty)\) and \( f(x)<0 \) on \((-2, 1) \cup (1, 2)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Intercepts
Intercepts are points where a graph crosses the axes. They help us understand the behavior of polynomial functions. In polynomial functions, we typically find two types of intercepts: the \( y \)-intercept and \( x \)-intercepts.
To find the \( y \)-intercept, set \( x = 0 \) and solve the function for \( f(x) \). For the function \( f(x) = (x+2)^2(x-1)^3(x-2) \), substituting \( x = 0 \) gives us \( f(0) = 8 \). Therefore, the \( y \)-intercept is at the point \((0, 8)\).
For \( x \)-intercepts, we set the function equal to zero and solve for \( x \). In our polynomial, this means solving \( (x+2)^2(x-1)^3(x-2) = 0 \). Setting each factor equal to zero gives the solutions \( x = -2 \), \( x = 1 \), and \( x = 2 \). Therefore, the \( x \)-intercepts occur at \(( -2, 0 )\), \(( 1, 0 )\), and \(( 2, 0 )\).
To find the \( y \)-intercept, set \( x = 0 \) and solve the function for \( f(x) \). For the function \( f(x) = (x+2)^2(x-1)^3(x-2) \), substituting \( x = 0 \) gives us \( f(0) = 8 \). Therefore, the \( y \)-intercept is at the point \((0, 8)\).
For \( x \)-intercepts, we set the function equal to zero and solve for \( x \). In our polynomial, this means solving \( (x+2)^2(x-1)^3(x-2) = 0 \). Setting each factor equal to zero gives the solutions \( x = -2 \), \( x = 1 \), and \( x = 2 \). Therefore, the \( x \)-intercepts occur at \(( -2, 0 )\), \(( 1, 0 )\), and \(( 2, 0 )\).
Positive and Negative Intervals
The intervals where a polynomial function is positive or negative are crucial for understanding the overall behavior of the function.
To find where the function \( f(x) = (x+2)^2(x-1)^3(x-2) \) is positive or negative, we examine the intervals created by its \( x \)-intercepts: \( x = -2 \), \( x = 1 \), and \( x = 2 \). These intercepts divide the \( x \)-axis into four intervals: \((-\infty, -2)\), \((-2, 1)\), \((1, 2)\), and \((2, \infty)\).
By choosing test points within each interval, we determine the sign of the function:
To find where the function \( f(x) = (x+2)^2(x-1)^3(x-2) \) is positive or negative, we examine the intervals created by its \( x \)-intercepts: \( x = -2 \), \( x = 1 \), and \( x = 2 \). These intercepts divide the \( x \)-axis into four intervals: \((-\infty, -2)\), \((-2, 1)\), \((1, 2)\), and \((2, \infty)\).
By choosing test points within each interval, we determine the sign of the function:
- In \((-\infty, -2)\), using \( x = -3 \), all factors result in a negative \( f(x) \).
- In \((-2, 1)\), we use \( x = 0 \), resulting in a positive \( f(x) \).
- In \((1, 2)\), testing \( x = 1.5 \), the function is negative.
- Finally, in \((2, \infty)\), using \( x = 3 \), \( f(x) \) is positive.
Factoring Polynomials
Factoring polynomials is an essential skill in algebra that simplifies functions and makes solving them easier. In the function \( f(x) = (x+2)^2(x-1)^3(x-2) \), the factored form reveals critical information about its roots and behavior.
Each factor: \((x+2)^2\), \((x-1)^3\), and \(x-2\) indicates a root of the function where it equals zero. The exponents show the multiplicity of each root. A root's multiplicity affects the graph's crossing or touching behavior at that point. For instance:
Each factor: \((x+2)^2\), \((x-1)^3\), and \(x-2\) indicates a root of the function where it equals zero. The exponents show the multiplicity of each root. A root's multiplicity affects the graph's crossing or touching behavior at that point. For instance:
- \((x+2)^2\) suggests that \( x = -2 \) is a root with even multiplicity, which means the graph touches the \( x \)-axis at \( x = -2 \) and turns around.
- \((x-1)^3\) implies \( x = 1 \) is a root with odd multiplicity, so the graph crosses the \( x \)-axis at this point.
- \(x-2\) has a multiplicity of 1, signifying an odd behavior and a crossing at \( x = 2 \).
Function Analysis
Analyzing a polynomial function involves understanding its roots, intercepts, and behavior across various intervals. With \( f(x) = (x+2)^2(x-1)^3(x-2) \), we have discovered a range of insightful properties.
Function analysis provides:
Function analysis provides:
- **Intercepts**: They reveal where the function interacts with axes, giving initial points for sketching.
- **Signs of intervals**: Important for evaluating whether the function rises or falls in different segments of the \( x \)-axis.
- **Behavior near roots**: Utilizing the multiplicity of roots, we predict if the curve would bounce off or pass through the axis.