Chapter 9: Problem 12
Graph each of the following rational functions: $$ f(x)=\frac{1}{x^{2}-1} $$
Short Answer
Expert verified
Graph has vertical asymptotes at \(x = 1\) and \(x = -1\), and a horizontal asymptote at \(y = 0\).
Step by step solution
01
Identify the Domain
The function is given by \( f(x) = \frac{1}{x^2 - 1} \). To find the domain, we need to determine where the denominator becomes zero, since division by zero is undefined. Set \( x^2 - 1 = 0 \) and solve for \( x \): \( x^2 - 1 = (x - 1)(x + 1) = 0 \). The solutions are \( x = 1 \) and \( x = -1 \). Thus, the domain of \( f \) is all real numbers except \( x = 1 \) and \( x = -1 \).
02
Find Vertical Asymptotes
The vertical asymptotes occur where the denominator is zero and the function is undefined. From Step 1, we found that \( x = 1 \) and \( x = -1 \) are where the function is undefined. Therefore, there are vertical asymptotes at \( x = 1 \) and \( x = -1 \).
03
Determine Horizontal Asymptote
To find horizontal asymptotes, analyze the behavior of the function as \( x \) approaches infinity or negative infinity. Since the degree of the polynomial in the denominator is greater than the degree of the polynomial in the numerator, \( f(x) \) approaches 0 as \( x \to \pm \infty \). Therefore, there is a horizontal asymptote at \( y = 0 \).
04
Analyze End Behavior
Since the function \( f(x) \) has a horizontal asymptote at \( y = 0 \), as \( x \to \pm \infty \), the function values approach 0, indicating that the graph gets closer to the x-axis but does not intersect it for large positive or negative \( x \).
05
Plot and Analyze Intervals
Choose points in the intervals \((-\infty, -1)\), \((-1,1)\), and \((1, \infty)\) to determine the behavior of the graph. For example: - In \((-\infty, -1)\), choose \(x = -2\): \(f(-2) = \frac{1}{3} > 0\).- In \((-1, 1)\), choose \(x = 0\): \(f(0) = -1 < 0\).- In \((1, \infty)\), choose \(x = 2\): \(f(2) = \frac{1}{3} > 0\).This indicates the graph approaches the vertical asymptotes from opposite sides within those intervals.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Rational Functions
Graphing rational functions involves plotting points on a Cartesian plane where the function is defined and identifying important features like intercepts and asymptotes. For the function \( f(x) = \frac{1}{x^2 - 1} \), the graph has interesting behaviors based on where \( x \) falls in relation to the domain exclusions and asymptotes.
To effectively graph \( f(x) \):
To effectively graph \( f(x) \):
- Identify critical values, such as zeros of the function (if there are any) and where vertical and horizontal asymptotes occur.
- Evaluate several points in each interval determined by these critical values to understand how the function behaves in each section of the domain.
- Use these points to sketch the graph, showing it approaching but never crossing the asymptotes.
Domain and Range
The domain of a rational function is the set of all possible input values (\( x \) values) for which the function is defined. This generally excludes values that make the denominator zero, as division by zero is undefined. For \( f(x) = \frac{1}{x^2 - 1} \), the denominator \( x^2 - 1 \) is zero when \( x = 1 \) and \( x = -1 \).
Therefore, the domain is all real numbers except \( x = 1 \) and \( x = -1 \). In interval notation, this is \((-\infty, -1) \cup (-1, 1) \cup (1, \infty)\).
The range of a function is the set of all possible output values (\( y \) values). For this function, since the horizontal asymptote is at \( y = 0 \), \( f(x) \) can approach 0 but does not actually take the value of 0. It behaves differently in different parts of the domain:
Therefore, the domain is all real numbers except \( x = 1 \) and \( x = -1 \). In interval notation, this is \((-\infty, -1) \cup (-1, 1) \cup (1, \infty)\).
The range of a function is the set of all possible output values (\( y \) values). For this function, since the horizontal asymptote is at \( y = 0 \), \( f(x) \) can approach 0 but does not actually take the value of 0. It behaves differently in different parts of the domain:
- For \( x \) in \((-\infty, -1)\) and \((1, \infty)\), \( f(x) > 0 \).
- For \( x \) in \((-1, 1)\), \( f(x) < 0 \).
Asymptotes
Asymptotes are lines that the graph of a function approaches but never actually reaches. They play a crucial role in understanding the behavior of rational functions. There are two primary types of asymptotes: vertical and horizontal.
- Vertical Asymptotes: These occur at the \( x \)-values where the function becomes undefined. For \( f(x) = \frac{1}{x^2 - 1} \), vertical asymptotes are at \( x = 1 \) and \( x = -1 \). The graph moves towards infinity or negative infinity as it nears these values.
- Horizontal Asymptote: This reflects the behavior of \( f(x) \) as \( x \) approaches infinity. Since the degree of the polynomial in the denominator (2) is greater than the degree of the numerator (0), the horizontal asymptote for this function is at \( y = 0 \).
End Behavior
The end behavior of a rational function describes how the function behaves as \( x \) approaches infinity or negative infinity. This is often influenced by any horizontal asymptotes and the degrees of the numerator and denominator polynomials.
For the function \( f(x) = \frac{1}{x^2 - 1} \), the end behavior is dictated by the horizontal asymptote at \( y = 0 \). As \( x \) approaches either positive or negative infinity:
For the function \( f(x) = \frac{1}{x^2 - 1} \), the end behavior is dictated by the horizontal asymptote at \( y = 0 \). As \( x \) approaches either positive or negative infinity:
- The function values get closer and closer to zero.
- Despite approaching zero, \( f(x) \) will never actually equal zero. This is part of why the x-axis serves as a horizontal asymptote, shaping the graph's distant behavior.