Chapter 8: Problem 8
If \(f(x)=\sqrt{3 x+2}\), find \(f\left(\frac{14}{3}\right), f(10)\), and \(f\left(-\frac{1}{3}\right)\).
Short Answer
Expert verified
The values are 4, \(4\sqrt{2}\), and 1, respectively.
Step by step solution
01
Identifying the Function
We are given the function \( f(x) = \sqrt{3x + 2} \). This means that for any input \( x \), the output is the square root of \( 3x + 2 \).
02
Evaluating \( f \left(\frac{14}{3}\right) \)
To find \( f \left(\frac{14}{3}\right) \), substitute \( \frac{14}{3} \) into the function: \( f \left(\frac{14}{3}\right) = \sqrt{3 \left(\frac{14}{3}\right) + 2} \). Simplifying inside the square root gives \( \sqrt{14 + 2} = \sqrt{16} = 4 \).
03
Evaluating \( f(10) \)
Substitute \( 10 \) into the function: \( f(10) = \sqrt{3 \times 10 + 2} \). Simplifying inside the square root gives \( \sqrt{30 + 2} = \sqrt{32} = 4 \sqrt{2} \).
04
Evaluating \( f \left(-\frac{1}{3}\right) \)
Substitute \( -\frac{1}{3} \) into the function: \( f \left(-\frac{1}{3}\right) = \sqrt{3 \times \left(-\frac{1}{3}\right) + 2} \). Simplifying inside the square root gives \( \sqrt{-1 + 2} = \sqrt{1} = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Evaluating Functions
Evaluating functions is similar to solving a puzzle where each piece fits in a specific spot. In mathematics, when we "evaluate" a function, we are essentially determining what output we get for a specific input.
To evaluate a function like \( f(x) = \sqrt{3x + 2} \), we replace the variable \( x \) with the number we want to evaluate. For example, if we want to find \( f(5) \), we substitute \( 5 \) for \( x \):
To evaluate a function like \( f(x) = \sqrt{3x + 2} \), we replace the variable \( x \) with the number we want to evaluate. For example, if we want to find \( f(5) \), we substitute \( 5 \) for \( x \):
- Write: \( f(5) = \sqrt{3 \, \times \, 5 + 2} \)
- Calculate inside the square root: \( f(5) = \sqrt{15 + 2} \)
- Final answer: \( f(5) = \sqrt{17} \)
Square Roots
Square roots are the opposite of squaring a number and are vital in understanding functions in algebra. A square root of a number \( a \) is a value that, when multiplied by itself, gives \( a \). The symbol \( \sqrt{} \) indicates a square root, and the most familiar is \( \sqrt{16} \), which equals \( 4 \), because \( 4 \times 4 = 16 \).
Square roots play a significant role in functions that involve a radical (like \( \sqrt{3x + 2} \)). When simplifying:
Square roots play a significant role in functions that involve a radical (like \( \sqrt{3x + 2} \)). When simplifying:
- Calculate inside the root first.
- Find the square root of the resulting number.
Function Notation
Function notation is a way of writing algebraic equations that clearly shows the input and output relationship. When you see \( f(x) \), this means "the function \( f \) in terms of \( x \)." The letter inside the parenthesis (in this case, \( x \)) represents the input value.
The notation becomes a way to denote that for any input \( x \), there is a specific output called \( f(x) \). This is crucial because:
The notation becomes a way to denote that for any input \( x \), there is a specific output called \( f(x) \). This is crucial because:
- It helps to specify which variable is the independent one (input).
- It clarifies which function you are working with, especially when dealing with multiple functions.