/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 If the ratio of rise to run is t... [FREE SOLUTION] | 91Ó°ÊÓ

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If the ratio of rise to run is to be \(\frac{3}{5}\) for some steps and the rise is 19 centimeters, find the run to the nearest centimeter.

Short Answer

Expert verified
The run is 32 centimeters.

Step by step solution

01

Understanding the Ratio

The problem states that the ratio of rise to run is \( \frac{3}{5} \). This means for every 3 centimeters of rise, there are 5 centimeters of run.
02

Setting Up the Proportion

We can set up the proportion \( \frac{3}{5} = \frac{19}{x} \), where 19 is the known rise, and \( x \) is the unknown run.
03

Solving the Proportion

To find \( x \), we cross-multiply: \( 3x = 5 \times 19 \). This gives \( 3x = 95 \).
04

Solving for x

Divide both sides of the equation by 3 to find \( x \): \( x = \frac{95}{3} \).
05

Calculating the Result

Perform the division: \( \frac{95}{3} = 31.6667 \).
06

Rounding to Nearest Centimeter

Round 31.6667 to the nearest centimeter, which gives us 32.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ratios and Proportions
Ratios and proportions are fundamental concepts in algebra that help us compare quantities. A ratio is a way to express a relationship between two numbers, showing how many times one number contains another. In this exercise, the ratio of rise to run is given as \( \frac{3}{5} \). This means that for every 3 units of rise, there are 5 units of run.

Proportion takes ratios a step further by expressing that two ratios are equal. If two ratios are equal, they form a proportion, as seen in the problem where \( \frac{3}{5} = \frac{19}{x} \). This setup allows us to find an unknown value by comparing it to a known ratio. Understanding these relationships is crucial because they provide a framework to solve problems involving parts and wholes, distances, rates, or scales.

So, whenever you encounter a problem with ratios, setting up a proportion correctly is the first step towards finding the solution.
Cross-multiplication
Cross-multiplication is a powerful method for solving proportions, especially when one value is unknown. Once you set up an equation like \( \frac{3}{5} = \frac{19}{x} \), cross-multiplication helps you eliminate the fractions to find the unknown.

Here's how it works: you multiply the outer terms of the proportion and set them equal to the product of the inner terms. For example, multiplying 3 and \( x \) (the outer terms) and setting it equal to 5 and 19 (the inner terms) gives you the equation \( 3x = 95 \).

This technique doesn't just apply to fractions. Cross-multiplication can be used with any equation where proportions are involved, providing a reliable way to simplify and solve equations. Mastering this technique is particularly useful in algebra, as it helps to streamline calculations and solve for unknowns quickly.
Rounding Numbers
Rounding is a method used to simplify numbers, making them easier to work with or understand. It involves adjusting the digits to the nearest specified place value, such as the nearest whole number, tenth, hundredth, etc. In our problem, after performing the division \( \frac{95}{3} = 31.6667 \), the task is to round the result to the nearest centimeter.

To round a number, look at the digit immediately following the place value you're rounding to (in this case, the tenths place). If this digit is 5 or greater, increase the number in the rounding place by one. If it's less than 5, you leave the rounding place digit unchanged. Therefore, 31.6667 rounds up to 32, since the digit in the tenths place is 6, which is greater than 5.

Rounding makes numbers more manageable and is essential when precision is balanced with usability, like in this exercise where the answer is needed to be a whole number.

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Most popular questions from this chapter

What does it mean to say that two points determine a line?

How do we know that the graphs of \(2 x-3 y=6\) and \(-2 x+3 y=-6\) are the same line?

Now let's use a graphing calculator to get a graph of \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\). By letting \(\mathrm{F}=x\) and \(\mathrm{C}=y\), we obtain Figure 7.15. Pay special attention to the boundaries on \(x\). These values were chosen so that the fraction \(\frac{\text { (Maximum value of } x \text { ) minus (Minimum value of } x \text { ) }}{95}\) would be equal to 1 . The viewing window of the graphing calculator used to produce Figure \(7.15\) is 95 pixels (dots) wide. Therefore, we use 95 as the denominator of the fraction. We chose the boundaries for \(y\) to make sure that the cursor would be visible on the screen when we looked for certain values. Now let's use the TRACE feature of the graphing calculator to complete the following table. Note that the cursor moves in increments of 1 as we trace along the graph. \begin{tabular}{l|lllllllll} F & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline C & & & & & & & & & \end{tabular} (This was accomplished by setting the aforementioned fraction equal to 1 .) By moving the cursor to each of the F values, we can complete the table as follows. \begin{tabular}{r|rrrrrrrrr} F & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline C & \(-21\) & \(-15\) & \(-13\) & \(-12\) & \(-11\) & \(-7\) & \(-1\) & 7 & 16 \end{tabular} The \(\mathrm{C}\) values are expressed to the nearest degree. Use your calculator and check the values in the table by using the equation \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\).

Contains the point \((-3,-7)\) and is parallel to the \(x\) axis

The properties in Problem 75 provide us with another way to write the equation of a line parallel or perpendicular to a given line that contains a given point not on the line. For example, suppose that we want the equation of the line perpendicular to \(3 x+4 y=6\) that contains the point \((1,2)\). The form \(4 x-3 y=k\), where \(k\) is a constant, represents a family of lines perpendicular to \(3 x+4 y=6\) because we have satisfied the condition \(A A^{\prime}=-B B^{\prime}\). Therefore, to find what specific line of the family contains \((1,2)\), we substitute 1 for \(x\) and 2 for \(y\) to determine \(k\). $$ \begin{array}{r} 4 x-3 y=k \\ 4(1)-3(2)=k \\ -2=k \end{array} $$ Thus the equation of the desired line is \(4 x-3 y=-2\). Use the properties from Problem 75 to help write the equation of each of the following lines. (a) Contains \((1,8)\) and is parallel to \(2 x+3 y=6\) (b) Contains \((-1,4)\) and is parallel to \(x-2 y=4\) (c) Contains \((2,-7)\) and is perpendicular to \(3 x-\) \(5 y=10\) (d) Contains \((-1,-4)\) and is perpendicular to \(2 x+\) \(5 y=12\)

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