Chapter 6: Problem 5
Solve each quadratic equation using the method that seems most appropriate to you. $$x^{2}-18 x=9$$
Short Answer
Expert verified
The solutions are \(x = 9 + 3\sqrt{10}\) and \(x = 9 - 3\sqrt{10}\).
Step by step solution
01
Move All Terms to One Side
Rearrange the given equation \[x^{2} - 18x = 9\]so that it is in the standard form of a quadratic equation \(ax^2 + bx + c = 0\). Subtract 9 from both sides:\[x^{2} - 18x - 9 = 0\].
02
Calculate the Discriminant
For the quadratic equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is calculated as \(b^2 - 4ac\). Identify \(a = 1\), \(b = -18\), \(c = -9\). Then, calculate the discriminant:\[D = (-18)^2 - 4(1)(-9) = 324 + 36 = 360\].
03
Apply the Quadratic Formula
The quadratic formula is given as\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]. Use \(a = 1\), \(b = -18\), \(c = -9\), and the discriminant \(D = 360\):\[x = \frac{18 \pm \sqrt{360}}{2}\].
04
Simplify the Square Root
Find the square root of 360, which is \[\sqrt{360} = 6\sqrt{10}\]. Substitute back into the equation:\[x = \frac{18 \pm 6\sqrt{10}}{2}\].
05
Simplify the Expression
Divide each term by 2:\[x = 9 \pm 3\sqrt{10}\].There are two possible solutions: \(x = 9 + 3\sqrt{10}\) and \(x = 9 - 3\sqrt{10}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
In quadratic equations, the discriminant is a vital concept. It helps determine the nature of the roots of the equation. The discriminant, denoted as \(D\), is found using the formula \(D = b^2 - 4ac\), where \(a\), \(b\), and \(c\) are the coefficients from the quadratic equation in the form \(ax^2 + bx + c = 0\).
Here's how the discriminant works:
Here's how the discriminant works:
- If \(D > 0\), the quadratic equation has two distinct real roots.
- If \(D = 0\), there is exactly one real root, also known as a repeated root.
- If \(D < 0\), the roots are complex numbers, which means that they are not real.
Quadratic Formula
The quadratic formula is a universal method for finding the roots of any quadratic equation. It is especially useful when the equation doesn't factor neatly. The formula is expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
Here's how it works:
Here's how it works:
- Start by identifying the coefficients \(a\), \(b\), and \(c\) from your quadratic equation in standard form.
- Use these coefficients to find the discriminant, \(b^2 - 4ac\). Once this step is complete, plug the values back into the formula.
- Solve for \(x\) to get the roots of the equation. The \(\pm\) symbol in the formula indicates that there will be two possible solutions: one adding the square root of the discriminant, and one subtracting it.
Standard Form of a Quadratic Equation
The standard form of a quadratic equation is crucial for analysis and solving. It is written as \(ax^2 + bx + c = 0\), where:
In the initial step of the exercise, the equation \(x^2 - 18x = 9\) was rearranged to become \(x^2 - 18x - 9 = 0\). This rearrangement aligns it with the standard form, making it straightforward to identify \(a = 1\), \(b = -18\), and \(c = -9\). Understanding how to convert to this form is foundational, providing a clear path forward to solve any quadratic equation.
- \(a\), \(b\), and \(c\) are known coefficients.
- \(a\), the coefficient of \(x^2\), must not be zero.
- \(b\) is the coefficient of \(x\).
- \(c\) is the constant term.
In the initial step of the exercise, the equation \(x^2 - 18x = 9\) was rearranged to become \(x^2 - 18x - 9 = 0\). This rearrangement aligns it with the standard form, making it straightforward to identify \(a = 1\), \(b = -18\), and \(c = -9\). Understanding how to convert to this form is foundational, providing a clear path forward to solve any quadratic equation.