Chapter 6: Problem 29
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$-2 n^{2}+3 n+5=0$$
Short Answer
Expert verified
The solutions are \(n = -1\) and \(n = 2.5\).
Step by step solution
01
Identify coefficients
The quadratic equation is given in the form \[-2n^2 + 3n + 5 = 0\]The coefficients are: \(a = -2\), \(b = 3\), and \(c = 5\). These values will be used in the quadratic formula.
02
Apply Quadratic Formula
Use the quadratic formula to find the solutions for \(n\).The formula is given by:\[n = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}\]Plug in the values \(a = -2\), \(b = 3\), and \(c = 5\) into this formula.
03
Calculate Discriminant
First calculate the discriminant \(b^2 - 4ac\):\[b^2 - 4ac = 3^2 - 4(-2)(5) = 9 + 40 = 49\]The discriminant is 49.
04
Solve for Roots
Now substitute back into the quadratic formula:\[n = \frac{{-3 \pm \sqrt{49}}}{2(-2)}\]Compute the roots:\[n = \frac{{-3 + 7}}{-4} = \frac{4}{-4} = -1\] \[n = \frac{{-3 - 7}}{-4} = \frac{-10}{-4} = 2.5\]The solutions to the quadratic equation are \(n = -1\) and \(n = 2.5\).
05
Check Solution with Sum and Product
For roots \(n_1\) and \(n_2\), the sum \(n_1 + n_2\) should equal \(-\frac{b}{a}\) and the product \(n_1 \times n_2\) should equal \(\frac{c}{a}\).Calculate these values:- Sum: \(-1 + 2.5 = 1.5\)- \(-\frac{b}{a} = -\frac{3}{-2} = 1.5\)- Product: \(-1 \times 2.5 = -2.5\)- \(\frac{c}{a} = \frac{5}{-2} = -2.5\)Both the sum and product match the predictions, confirming the correctness of our solutions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula is helpful when factoring is difficult or impossible. To use the quadratic formula, you substitute the coefficients \(a\), \(b\), and \(c\) from your equation into the formula:
Applying this formula, as in the example, enables us to tackle any solvable quadratic equation with confidence.
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Applying this formula, as in the example, enables us to tackle any solvable quadratic equation with confidence.
Discriminant
The discriminant, represented by the expression \( b^2 - 4ac \) in the quadratic formula, is crucial in determining the nature and number of solutions to a quadratic equation. Here’s what the discriminant tells us:
- If the discriminant is positive, as in our example where it equaled 49, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root, indicating a repeated or double root.
- If the discriminant is negative, there are no real roots, and the solutions are complex or imaginary.
Sum and Product of Roots
The sum and product of the roots of a quadratic equation offer a neat way to verify solutions without detailed calculations. Given a quadratic equation \( ax^2 + bx + c = 0 \), the relationships are:
This technique serves as an excellent double-check, ensuring that no computational errors were made in earlier steps.
- Sum of the roots \( (n_1 + n_2) = -\frac{b}{a} \)
- Product of the roots \( (n_1 \times n_2) = \frac{c}{a} \)
This technique serves as an excellent double-check, ensuring that no computational errors were made in earlier steps.