Chapter 6: Problem 1
Solve each quadratic equation using the method that seems most appropriate to you. $$x^{2}-4 x-6=0$$
Short Answer
Expert verified
The solutions are \(x = 2 + \sqrt{10}\) and \(x = 2 - \sqrt{10}\).
Step by step solution
01
Determine the Method
To solve the quadratic equation \(x^2 - 4x - 6 = 0\), notice that the quadratic is not easily factorable, so using the quadratic formula is most appropriate. The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
02
Identify Coefficients
Identify the coefficients \(a\), \(b\), and \(c\) in the equation \(x^2 - 4x - 6 = 0\). Here, \(a = 1\), \(b = -4\), and \(c = -6\).
03
Substitute Coefficients into the Quadratic Formula
Plug in \(a = 1\), \(b = -4\), and \(c = -6\) into the quadratic formula: \[x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \times 1 \times (-6)}}{2 \times 1}\]
04
Calculate the Discriminant
Calculate the discriminant \(b^2 - 4ac\): \[(-4)^2 - 4 \times 1 \times (-6) = 16 + 24 = 40\].
05
Compute the Roots
Now compute the roots using the quadratic formula: \[x = \frac{4 \pm \sqrt{40}}{2}\]First, simplify \(\sqrt{40}\) as \(2\sqrt{10}\).\[x = \frac{4 \pm 2\sqrt{10}}{2}\] This simplifies to \[x = 2 \pm \sqrt{10}\].
06
Write the Final Solution
The solutions to the quadratic equation \(x^2 - 4x - 6 = 0\) are: \[x = 2 + \sqrt{10}\] and \[x = 2 - \sqrt{10}\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \(ax^2 + bx + c = 0\). This formula offers a straightforward way to find the roots, or solutions, of any quadratic equation. It is especially useful when an equation cannot be easily factored. The quadratic formula is given by:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Discriminant
The discriminant is a vital component of the quadratic formula. It helps determine the nature and number of roots a quadratic equation has. The discriminant is found inside the square root of the quadratic formula. It is calculated using the expression:
- \(b^2 - 4ac\)
- If the discriminant is positive, the equation has two distinct real roots.
- If the discriminant is zero, there is exactly one real root, often called a repeated or double root.
- If the discriminant is negative, the equation has two complex roots, meaning there are no real solutions.
- \((-4)^2 - 4 \times 1 \times (-6) = 16 + 24 = 40\)
Roots of Equations
The roots of a quadratic equation are the values of \(x\) that satisfy the equation, making it equal to zero. In our example, using the quadratic formula, we find:
- \(x = 2 + \sqrt{10}\)
- \(x = 2 - \sqrt{10}\)
Factoring
Factoring is another method to solve quadratic equations, but it is not always applicable. When quadratic expressions can be written as a product of simpler terms, we can find the roots by setting each term equal to zero. For instance, an equation such as \(x^2 - 5x + 6 = 0\) can be factored into \((x - 2)(x - 3) = 0\). Here, the solutions are \(x = 2\) and \(x = 3\).However, in cases where quadratic equations cannot be easily factored, like \(x^2 - 4x - 6 = 0\), the quadratic formula becomes the most efficient method. Factoring relies on recognizing patterns or easily factorable numbers, which isn't always possible with complex coefficients or non-integer solutions.